rotation

问题 Let's consider this SVG file from Openclipart (link to raw SVG file). For reference, it looks like this: I now want to rotate the hands so that I can make the clock show some arbitrary time. I have determined that the hour hand is encoded by this path element: <path d="m 458.13588,295.06406 c 1.74675,-16.11195 25.92429,-46.33386 37.207,-59.62773 l -0.0945,-0.0895 c -12.66188,11.97753 -41.49863,37.74816 -57.33149,40.35684 -30.58445,5.03466 -23.84883,26.09555 -19.57494,34.86553 l -52.97792,55

问题 Can anyone help me out with Eigen? I tried to convert quaternion to matrix and then back and got completely different matrices. I am not able to trust quaternion before understanding this issue. Here is the code: #include <Eigen/Geometry> #include <iostream> void Print_Quaternion(Eigen::Quaterniond &q){ std::cout<<"["<<q.w()<<" "<<q.x()<<" "<<q.y()<<" "<<q.z()<<"]"<<std::endl; } void Verify_Orthogonal_Matrix(Eigen::Matrix3d &m) { std::cout<<"|c0|="<<m.col(0).norm()<<",|c1|="<<m.col(1).norm()<

问题 I would like to make some kind of solar system in pygame. I've managed to do a fixed one but I thought it would be more interesting to do one with planets moving around the sun and moons around planets etc. Is there a way I could do that (using pygame if possible)? What I would like is : Sun = pygame.draw.circle(...) planet1 = pygame.draw.circle(...) etc. a = [planet1, planet2, ...] for p in a: move p[2] to pos(x, y) That is what I think would work but I'm not sure how to do it. Also, I've

问题 I have the following issue: I have an application, which continuously produces output to stderr and stdout. The output of this application is captured in a logfile (the app is redirected as: &> log.txt ). I don't have any options to produce a proper logging to file for this. Now, I have a cron job, which runs every hour and beside of doing other things, it also tries to rotate this logfile above, by copying it to log.txt.1 and then creates an empty file and copies it to log.txt It looks like:

问题 This question already has answers here : Rotating a NxN matrix in Java (11 answers) Closed 19 hours ago . I want a 2d matrix to rotate to the right, it compiles fine but when I try to the run it says that the array index is out of bounds exception . For example, I want {{10,20,30},{40,50,60}} to rotate into {{40,10},{50,20},{60,30}} : public static int[][] rotate(int[][] m) { int[][] rotateM = new int[m[0].length][m.length]; for (int i = 0; i < m.length; i++) { for (int j = 0; j < m[0].length

问题 This question already has answers here : Rotating a NxN matrix in Java (11 answers) Closed 19 hours ago . I want a 2d matrix to rotate to the right, it compiles fine but when I try to the run it says that the array index is out of bounds exception . For example, I want {{10,20,30},{40,50,60}} to rotate into {{40,10},{50,20},{60,30}} : public static int[][] rotate(int[][] m) { int[][] rotateM = new int[m[0].length][m.length]; for (int i = 0; i < m.length; i++) { for (int j = 0; j < m[0].length

问题 This question already has answers here : Rotating a NxN matrix in Java (11 answers) Closed 19 hours ago . I want a 2d matrix to rotate to the right, it compiles fine but when I try to the run it says that the array index is out of bounds exception . For example, I want {{10,20,30},{40,50,60}} to rotate into {{40,10},{50,20},{60,30}} : public static int[][] rotate(int[][] m) { int[][] rotateM = new int[m[0].length][m.length]; for (int i = 0; i < m.length; i++) { for (int j = 0; j < m[0].length

问题 In my rails app, i let the user upload images to use as thumbnails for resources they've made. I do all the image processing with imagemagick's convert command: i convert to jpg, letterbox it to 800x600px and then make some smaller thumbnail versions of that. This is all working fine. The problem is that some images that have come off my iPhone, for example, have the wrong orientation. My desktop seems to variously deal with this: when i see the tiny thumbnail for the image in the file

问题 How to rotate a div to certain height suppose 10px. I can rotate a div otherwise around 360 degrees. I need the angle by which the div would touch the line. 回答1: You can apply the coordinate formula of the circle: (x - a)² + (y - b)² = r² . Because we've interest in the angle only, we can position the circle on the origin, and ignore a and b , which makes the calculation much more simple. In the image, the green items are known, the cyan items are helpers, and the red items are the changes

问题 How to rotate a div to certain height suppose 10px. I can rotate a div otherwise around 360 degrees. I need the angle by which the div would touch the line. 回答1: You can apply the coordinate formula of the circle: (x - a)² + (y - b)² = r² . Because we've interest in the angle only, we can position the circle on the origin, and ignore a and b , which makes the calculation much more simple. In the image, the green items are known, the cyan items are helpers, and the red items are the changes