reverse

问题 I have a string with the name "Mustang Sally Bob" After i run my code i want the string output to be like this: gnatsuM yllaS boB My approach is to count the words until the space and save the index of where the space is located in the string. then Then I want to print the characters starting from the space backwards. #include <stdio.h> int main() { char* test="Mustang Sally Bob"; int length; //string length int x; for(length=0;test[length] !=0&&test[length];length++); //get string length int

问题 How to detect whether the class from the jar file is extending other class or if there are method calls to other class objects or other class objects are created ? and then system out which class extend which class and which class called methods from which class . Im using Classparser to parser the jar . here is part of my code : String jarfile = "C:\\Users\\OOOO\\Desktop\\Sample.Jar"; jar = new JarFile(jarfile); Enumeration<JarEntry> entries = jar.entries(); while (entries.hasMoreElements())

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . For some reason when I apply the reverse method, nothing changes. public static string ReverseString(string word) { char[] myArray = word.ToCharArray(); myArray.Reverse(); string ans = string.Join("", myArray); return ans; } 回答1: Try Array.Reverse(myArray) instead of myArray.Reverse() . You are confusing

问题 I am looking for the C program for reverse the digits like below: If i enter: 123456 Then the result would be: 654321 Please help me. 回答1: Use % 10 to get the last digit. Output it. Divide the number by 10 to get all but the last digit. Use % 10 to get the last digit of that. And so on, until the number becomes 0. 回答2: Here is a simple solution to this complex problem: #include <stdio.h> int main() { int ch; ch = getchar(); if (ch != '\n') { main(); printf("%c", ch); } } A new version that

问题 I'm coding an application which can make a reverse proxy connection but I have a problem! The error is here: new Form1.ProxyConfig() When I try to run it I get an error: " A ref or out argument must be an assignable variable " private void startToolStripMenuItem_Click(object sender, EventArgs e) { if (this.startToolStripMenuItem.Text == "Start") { var form2 = new Form2(); if (form2.ShowDialog() != DialogResult.OK) return; int num1 = Form1.ProxyListenerStart(ref new Form1.ProxyConfig() {

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Iterating through a LinkedHashMap in reverse order How to traverse Linked Hash Map in a reverse order? Is there any predefined method in map to do that? I'm creating it as follows: LinkedHashMap<Integer, String> map = new LinkedHashMap<Integer,String>(); map.put(1, "one"); map.put(2, "two"); map.put(3, "three"); 回答1: List<Entry<Integer,String>> list = new ArrayList<>(map.entries()); for( int i = list.size() -1;

问题 How can I sort this list in descending order? timestamp = [ "2010-04-20 10:07:30", "2010-04-20 10:07:38", "2010-04-20 10:07:52", "2010-04-20 10:08:22", "2010-04-20 10:08:22", "2010-04-20 10:09:46", "2010-04-20 10:10:37", "2010-04-20 10:10:58", "2010-04-20 10:11:50", "2010-04-20 10:12:13", "2010-04-20 10:12:13", "2010-04-20 10:25:38" ] 回答1: In one line, using a lambda : timestamp.sort(key=lambda x: time.strptime(x, '%Y-%m-%d %H:%M:%S')[0:6], reverse=True) Passing a function to list.sort : def

问题 I am trying to copy the code of else state to the if statement. In here I see if-eqz as the if condition but I don't know where the else condition is here. Can someone help me find else condition so that I can copy it to become the if code also. I also want to know where is the start and the end of the else statement body if-eqz v1, :cond_1 .line 103 :goto_1 return-object v0 .line 82 :cond_0 invoke-static {}, Landroid/os/Environment;->getExternalStorageDirectory()Ljava/io/File; move-result

问题 My general question is that I want to select all columns from a left join, and I don't need to know the ID that joins the two tables. I know that it is unnecessary to select all, but since you need all the fields except the ids, why isn't there a shorter way to: SELECT * except "this column", i feel like the action time should be shorter by doing the reverse way? T1: aID, c1, c2, c3, c4 t2: aID, c1, c2, c3, c4 Select * from t1 left join t2 on t1.aid = t2.aid result: t1:aid, c1, c2, c3, c4,

问题 Here is my method that is suppose to reverse the array. (Also, keep in mind that this method can receive a jagged array) public static int[][] reverse(int[][]a){ int[][] rev = new int[a.length][]; int row = a.length; for(int x=0;x<a.length;x++){ int col = a[x].length-1; for(int y=0; y< a[x].length;y++){ rev[row-1][col-1]= a[x][y]; col--; } row--; } return rev; }// reverse method I keep getting Exception in thread "main" java.lang.NullPointerException at Home.reverse(Home.java:259) at Home