reshape

How do I output the correct percentages on each bar of my Likert chart?

由 早过忘川 提交于 2020-05-15 08:05:12
问题 I'm trying to get my code to output the percentage on top of each individual bar. Right now, the percentages shown below are on the wrong side. My code combines Labels 1 and 2 and Labels 3 and 4, and then outputs those numbers on the incorrect sides. Is there a function to label those bars correctly? I'm including my code, the data from the .csv file, and the current visualization. library(ggplot2) library(reshape) library(likert) library(dplyr) setwd("~/Desktop/") df <- read.csv("Likert_Test

How to further melt a dataset?

由 [亡魂溺海] 提交于 2020-05-05 12:42:10
问题 I'm working with the following data: #Reproducible Example Bills <- c("93-HCONRES-106", "93-HCONRES-107", "93-HCONRES-108") Members <- c("00134", "00416;00010;00017;00026", "00416;00503;00513;00568") data <- data.frame(Bills, Members) Where the data looks like this: #Data Structure Bills Members 1 93-HCONRES-106 00134 2 93-HCONRES-107 00416;00010;00017;00026 3 93-HCONRES-108 00416;00503;00513;00568 What I would like is for the dataset to extend, such that each bill corresponds with each

numpy 添加删除去重及形状变换

由 自闭症网瘾萝莉.ら 提交于 2020-04-04 11:24:19
一、数组的添加删除与去重 下面是几个常见的数组操作： append:将值添加到数组末尾 insert: 沿指定轴将值插入到指定下标之前 delete: 返回删掉某个轴的子数组的新数组 unique: 寻找数组内的唯一元素 >>> a = np.array([[1,2,3],[4,5,6]]) >>> np.append(a, [7,8,9]) # 附加后，变成了一维的 array([1, 2, 3, 4, 5, 6, 7, 8, 9]) >>> a #原来的数组没有改变 array([[1, 2, 3], [4, 5, 6]]) >>> a.append([10,11,12]) # ndarray没有这个方法 --------------------------------------------------------------------------- AttributeError Traceback (most recent call last) <ipython-input-165-a36f3ca1308b> in <module>() ----> 1 a.append([10,11,12]) AttributeError: 'numpy.ndarray' object has no attribute 'append' >>> np.append(a, [[7,8,9]

Numpy resize or Numpy reshape

由 若如初见. 提交于 2020-03-27 11:44:24
问题 I've been scouring the stackexchange archives and can not seem to come across the right answer... should reshape be used, should resize be used, but both fail... setup: 3 netCDF files of two resolutions... 1 500 meter, 2 1000 meter need to resize or decrease resolution or reshape or whatever the right word is the higher resolution file :) using either gdalinfo or "print (np.shape(array))" we know that the higher resolution file has a shape or size of (2907, 2331) and the lower resolution

Numpy resize or Numpy reshape

由 感情迁移 提交于 2020-03-27 11:43:34
问题 I've been scouring the stackexchange archives and can not seem to come across the right answer... should reshape be used, should resize be used, but both fail... setup: 3 netCDF files of two resolutions... 1 500 meter, 2 1000 meter need to resize or decrease resolution or reshape or whatever the right word is the higher resolution file :) using either gdalinfo or "print (np.shape(array))" we know that the higher resolution file has a shape or size of (2907, 2331) and the lower resolution

Transpose data by groups in R

由 谁说我不能喝 提交于 2020-03-21 11:45:08
问题 I have data in the following structure: x <- read.table(header=T, text=" X Y D S a e 1 10 a e 2 20 a f 1 50 b c 1 40 b c 2 30 b c 3 60 b d 1 10 b d 2 20") And I want to get the following result: X Y 1 2 3 a e 10 20 a f 50 b c 40 30 60 b d 10 20 For every combination of columns X and Y I would like to transpose data in column S by order in column D . I thought xtabs() will work, but I don't think so, my best version is: xtabs(formula=S~Y+D,data=x) With result: D Y 1 2 3 c 40 30 60 d 10 20 0 e

Reshape Table in MySQL or R [duplicate]

由 允我心安 提交于 2020-03-20 07:57:16
问题 This question already has answers here : How to reshape data from long to wide format (11 answers) Closed 2 years ago . I have the following table: perid date rating 10001 2005 RD 10001 2006 GN 10001 2007 GD 10002 2008 GD 10002 2009 YW 10002 2010 GN 10002 2011 GN 10003 2005 GD 10003 2006 GN 10003 2007 YW how can I turn this table to the following format: perid 2005 2006 2007 2008 2009 2010 2011 10001 RD GN GN N/A N/A N/A N/A 10002 N/A N/A N/A GD YW GN GN 10003 GD GN YW N/A N/A N/A N/A Or if I

MATLAB Find the indexes that have a particular date

由 核能气质少年 提交于 2020-02-25 05:26:33
问题 I am trying to find the index in Date3 , a column vector of date numbers from 01/01/2008 to 01/31/2014 that has been repeated many times, matches day . I basically want to organize idx into a cell array like idx{i} in which each cell is one day (So return all the indexes where Date3 equals day, where day is one of the days between 01/01/2008 and 01/31/2014. Eventually, I want to pull out the data for each day by applying the index I found to the variable Data2 (Reshape Data2 so that instead

RelationNetwork

由 北慕城南 提交于 2020-02-22 18:02:31
论文：Relation Networks for Object Detection 论文链接： https://arxiv.org/abs/1711.11575 代码链接： https://github.com/msracver/Relation-Networks-for-Object-Detection 这篇文章的细节可以通过阅读源码来加深理解，这篇博客就来介绍这篇文章的部分源码。 因为这篇文章主要是在网络结构上做改动，所以这篇博客以resnet_v1_101_rcnn_attention_1024_pairwise_position_multi_head_16_learn_nms.py为例介绍网络结构，这个例子在Faster RCNN基础上引入relation module，包括全连接层和NMS阶段。 链接： resnet_v1_101_rcnn_attention_1024_pairwise_position_multi_head_16_learn_nms.py 接下来介绍的代码顺序和链接中的不大一样，这里按照代码运行时的顺序介绍，目的是方便跟着数据流进行阅读，主要涉及几个方法： 全局网络构造：get_symbol；ROI信息的坐标变换：extract_position_matrix；ROI信息的坐标embedding：extract_position_embedding

reshaping the data from wide to long [duplicate]

由 爱⌒轻易说出口 提交于 2020-02-06 07:55:50
问题 This question already has answers here : Reshaping data.frame from wide to long format (7 answers) Closed 15 days ago . Please help me with the following matter I have a wide data frame that I need to reshape. This is the df I have mydf <- data.frame(date=1983:1985,January=c(5,7,8),February=c(12,18,19)) mydf this is the output I need output <- data.frame(date=rep(c(1983,1984,1985),each=2),Month=rep(c("January","February"),3),Value=c(5,12,7,18,8,19)) output 回答1: We can use pivot_longer library
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