repeat

问题 I tried to use the code below to create a continuously rotating square on the screen. But I don't know why the rotational speed is changing. How could I change the code to make the rotational speed invariable? I tried different UIViewKeyframeAnimationOptions , but seems none of them work. override func viewDidLoad() { super.viewDidLoad() let square = UIView() square.frame = CGRect(x: 55, y: 300, width: 40, height: 40) square.backgroundColor = UIColor.redColor() self.view.addSubview(square)

问题 I have 2 dataframes, Tg and Pf, each of 127 columns. All columns have at least one row and can have up to thousands of them. All the values are between 0 and 1 and there are some missing values (empty cells). Here is a little subset: Tg Tg1 Tg2 Tg3 ... Tg127 0.9 0.5 0.4 0 0.9 0.3 0.6 0 0.4 0.6 0.6 0.3 0.1 0.7 0.6 0.4 0.1 0.8 0.3 0.9 0.9 0.6 0.1 Pf Pf1 Pf2 Pf3 ...Pf127 0.9 0.5 0.4 1 0.9 0.3 0.6 0.8 0.6 0.6 0.6 0.7 0.4 0.7 0.6 0.5 0.1 0.6 0.5 0.3 0.3 0.3 Note that some cell are empty and the

问题 My app has an alarm function using UILocalNotification, and it works great. However, if the user uninstalls the app, then later REINSTALLS it, he would receive all the "in between" notifications at once. I have tried to call: [[UIApplication sharedApplication] cancelAllLocalNotifications]; if it's the first time the app is launched, but it doesn't help, because the notification is received even before application:didFinishLaunchingWithOptions: is called. This was worse in 4.0 when the alarm

问题 I am implementing a flashcard game and I want to implement spaced repetition. I don't need something complex like in SuperMemo, but simply space the learning based on the score for each card. What I am looking for at the moment is how to calculate the number of days until a card is shown again, based on its score. I found that ZDT uses the list in the screenshot below (1, 2, 3, 5, etc.). Does anybody know how to dynamically generate this list (so that I can calculate beyond a score of 12)? Or

问题 How can I repeat the line in notepad++ ? For example I have the following input: a 01 a 02 a 03 a 04 And I would like it to become: a 01 a 01 a 02 a 02 a 03 a 03 a 04 a 04 So every line should be displayed twice . 回答1: If you don't mind the semi-manual process, you can start at the first line and repeat the following key combination until you reach the end of the document (you get very fast at this) Ctrl + D Down Down This duplicates the current line, then moves down twice (to the line

问题 I'm trying to add a custom UIToolBar to all of my keyboards with as little repetition. The way I'm currently doing it requires me to add the code to all my viewDidLoads and assign every textfield's delegate to the viewController I'm using. I have tried creating my own UIToolBar subclass but I find that I can't really do that when the target for my "Done" and "cancel" buttons are the self view. Does anyone have any suggestions for creating an easily reusable toolbar? Thanks in advance.

问题 so basically what Im trying to do is to write a piece of code about making a cup of tea(school homework) so basically here is my code print ("Making A Cup Of Tea") a=input("How many for Tea") print ("there are",a,"People for tea") b=input ("Would you like Sugar? YES/NO") if (b) == ("YES"): c=input("How many sugars?") elif (b) == ("NO"): print ("Okay No sugar") e=input("How Much Milk Would You Like? SMALL/MEDIUM/LARGE") print ("YOUR ORDER IS BEING PROCESSED PLEASE WAIT...") if (a) == ("1"):

问题 Seems like this very simple maneuver used to work for me, and now it simply doesn't. A dummy version of the problem: df <- data.frame(x = 1:5) # create simple dataframe df x 1 1 2 2 3 3 4 4 5 5 df$y <- c(1:5) # adding a new column with a vector of the exact same length. Works out like it should df x y 1 1 1 2 2 2 3 3 3 4 4 4 5 5 5 df$z <- c(1:4) # trying to add a new colum, this time with a vector with less elements than there are rows in the dataframe. Error in `$<-.data.frame`(`*tmp*`, "z",

问题 I need to find the regex expression to find a character that repeats 4 or more times with grep. I know that the expression is {n,}, so if I need to find lines, for example, when the character "g" repeats 4 or more times, in theory with grep man page is: grep "g{4,}" textsamplefile But doesn't work. Any help? The character could have other letters. For example, a valid match is: g example g of g valid g match g g other g valid g match g is g here g gggg other 回答1: you should change your grep

问题 How to match any character which repeats n times? Example: for input: abcdbcdcdd for n=1: .......... for n=2: ......... for n=3: .. ..... for n=4: . . .. for n=5: no matches After several hours my best is this expression (\w)(?=(?:.*\1){n-1,}) //where n is variable which uses lookahead. However the problem with this expression is this: for input: abcdbcdcdd for n=1 .......... for n=2 ... .. . for n=3 .. . for n=4 . for n=5 no matches As you can see, when lookahead matches for a character, let