relation

Retrieve Records from Quickblox API

孤人 提交于 2019-12-13 07:13:15
问题 I am using Quickblox SDK in my Application and designed Custom Objects in the Quickblox Admin panel.Here i am having some complex relationship between Custom Objects and not able to figure out how to retrieve the records using the Quickblox API. Problem: There are two tables 1.User 2.Group, i am successfully fetching all the groups created by a specific using by using parent_id key as mention in Quickblox API for maintaining relationships between tables. I want to retrieve all the groups

Silverstripe: get var from many_many relation custom upload

瘦欲@ 提交于 2019-12-13 01:08:47
问题 I would like to know how customize this uploadfield to get from $belongs_many_many Act table. A part of the code.... <? class MultipleBlock extends DataObject { private static $db = array( 'Act' => 'Varchar', private static $many_many = array( 'MultipleBlockColumns' => 'MultipleBlockColumn' ); } class MultipleBlockColumn extends DataObject { static $belongs_many_many = array( 'MultipleBlocks' => 'MultipleBlock' ); private static $has_one = array( 'Image' => 'Image', ); $fields->addFieldToTab(

Relation is DS.PromiseMany instead model and data

本小妞迷上赌 提交于 2019-12-12 06:09:24
问题 What I need is: 1) Represent list of partners App.Partner= DS.Model.extend( { name: attr(), site: attr(), contacts: DS.hasMany('partner-contact', { async: true, polymorphic: true }) } ); 2) and names of partners contacts App.PartnerContact = DS.Model.extend( { name: attr(), phone: attr(), post: attr(), email: attr(), partnerId: attr(), partner: DS.belongsTo('partner') } ); So I have route: App.CallsMyContactsRoute = Ember.Route.extend({ //needs: "partner-contacts", model: function () { return

if current_user.id = @game.user_id

耗尽温柔 提交于 2019-12-12 03:21:46
问题 I have links to the show pages for each game in my project and if the games user_id matches the id of the currently signed in user then I want it to display the edit button if they are not then it shouldn't display. I currently have the following code set but it doesn't work. Every game has the edit button display. The code is as followed: <% if current_user.id = @game.user_id %> <div id="text3"><%= link_to 'Edit', edit_game_path(@game) %></div><br /> <% end %> Any ideas? 回答1: MrDanA's answer

Saving a basic relation in Parse

北战南征 提交于 2019-12-12 01:47:40
问题 The example was straight forward but not surprisingly, it is not working. mLate is an object or array of objects from the Late table. My code: var user = Parse.Object.extend("User"); var userQuery = new Parse.Query(Parse.User); var Late = Parse.Object.extend("Late"); var lateQuery = new Parse.Query(Late); userQuery.get("yCDDEWoiwM", {//this is where the userID goes success: function (userDetails) { var relation = userDetails.relation("mLate"); relation.add(mLate); userDetails.save(); Given

Core Data: re-setting to-many relationship

纵然是瞬间 提交于 2019-12-12 01:18:04
问题 I have created model which you can see there: http://i.imagehost.org/0836/2009-11-08_14_37_41.png I want to store information about sound categories and some sample sounds for each category. Category has Name (NSString) and SoundsRelation (NSSet of NSData, which represents sounds). Here is the problem: For example I have some category which contains several sounds associated with it. Assume number of sounds is 3. So if I do NSLog(@"description: \n%@", category); I will see information about

JPA map relation entity parentID

断了今生、忘了曾经 提交于 2019-12-11 19:43:13
问题 could someone help me to understand how can I define an entity with JPA mapping that has a relation with it self? For example, my entity is CompanyDivision, divisionA contains divisionB, divisionC and divisionB contains divisionB1, divisionB2 divisionA divisionB divisionB1 divisionB2 divisionC Thank you! 回答1: It's not different from a relation between 2 different Entities. Here's an example: class CompanyDivision { @OneToMany(mappedBy = "parentDivision") private Set<CompanyDivision>

How to realize Yii2 relation through string not array?

折月煮酒 提交于 2019-12-11 17:08:14
问题 I have a class named ChatMessage. There are 2 main columns in DB (from_user, to_user). I want to relate one of these 2 columns to User model id. How can I use a relation query that looks like this public function getChattedUser() { return $this->hasOne(User::className(), '(case when(chat_message.from_user={Yii::$app->user->id}) then chat_message.to_user else chat_message.from_user END)=user.id'); } 回答1: Short answer: this is not possible . ActiveRecord relations are more complicated than you

Firestore - How to model and query relation of 2 collections - IOT use case - v2

℡╲_俬逩灬. 提交于 2019-12-11 15:53:05
问题 extending to my question Firestore - How to model and query relation of 2 collections - IOT use case I'ved now seen a video on this, and this recommends modelling relations using document ID. https://www.youtube.com/watch?v=jm66TSlVtcc skip to 6:07 I want to know if it would work in this case (modifying the example from my original question to fit to this youtube recommendation of firestore relation: Eg: I have 2 different collection - tracking and venue tracking <-- collection 1. document

Laravel Eloquent relation issue for multiple tables

 ̄綄美尐妖づ 提交于 2019-12-11 15:42:27
问题 In Laravel 5.5 I try to create a small application to manage products of a couple of sellers/stores. Therefore, I have four different models like this: Seller.php class Attribute extends Model { public function items() { return $this->belongsToMany(Item::class); } } Item.php class Item extends Model { public function seller() { return $this->belongsTo(Seller::class); } public function category() { return $this->belongsTo(Category::class); } public function attributes() { return $this-