regex-lookarounds

问题 We are using the following regex to recognize urls (derived from this gist by Jim Gruber). This is being executed in Scala using scala.util.matching which in turn uses java.util.regex : (?i)\b((?:https?:(?:/{1,3}|[a-z0-9%])|[a-z0-9.\-]+[.](?!js)[a-z]{2,6}/)(?:[^\s()<>{}\[\]]+)(?:[^\s`!()\[\]{};:'".,<>?«»“”‘’])|(?:(?<!@)[a-z0-9]+(?:[.\-][a-z0-9]+)*[.](?!js)[a-z]{2,6}\b/?(?!@))) This version has escaped forward slashes, for Rubular: (?i)\b(((?:https?:(?:\/{1,3}|[a-z0-9%])|[a-z0-9.\-]+[.](?!js)

问题 my first Q here. I have a log file that has multiple similar strings as hits: Region: AR OnlineID: Atl_Tuc ---Start--- FIFA 18 Legacy Edition ---END--- Region: FR OnlineID: jubtrrzz ---Start--- FIFA 19 Undertale Pro Evolution Soccer™ 2018 ---END--- Region: US OnlineID: Cu128yi ---Start--- KINGDOM HEARTS HD 1.5 +2.5 ReMIX ---END--- Region: RO OnlineID: Se116 ---Start--- Real Farm EA SPORTS™ FIFA 20 LittleBigPlanet™ 3 ---END--- Region: US OnlineID: CAJ5Y ---Start--- Madden NFL 18: G.O.A.T.

问题 I have a string containing a list of key-value pairs like this: "a:1,b:2,c:3". I would like to extract a value for a specified key so that e.g. I would get "1" for "a". I was planning to do it with a regex like this: '(?<=(^|,)$KEY:)^,*' but it seems grep doesn't support lookarounds. (I'm not even sure this regex works correctly.) Is there another way? 回答1: You may use grep -oP "(?:^|,)$KEY:\K[^,]+" The -o option outputs matches. -P enables PCRE engine. The double quotes are necessary for

问题 I have a string containing a list of key-value pairs like this: "a:1,b:2,c:3". I would like to extract a value for a specified key so that e.g. I would get "1" for "a". I was planning to do it with a regex like this: '(?<=(^|,)$KEY:)^,*' but it seems grep doesn't support lookarounds. (I'm not even sure this regex works correctly.) Is there another way? 回答1: You may use grep -oP "(?:^|,)$KEY:\K[^,]+" The -o option outputs matches. -P enables PCRE engine. The double quotes are necessary for

问题 I've a text file, from that I have extracted these two paragraph block. The text example is give below. Text Example: EXONERAR, com validade a contar de 19 de agosto de 2020 , DE- NILSON DE BRITO LIMA , ID FUNCIONAL Nº 2100423-4 , do cargo em comissão de Coordenador , símbolo DAS-8 , da Coordenadoria de Gestão Centralizada de Serviços, da Superintendência de Gestão Centralizada, da Subsecretaria de Logística , da Secretaria de Estado de Planejamento e Gestão . Processo nº SEI- 120001/010643

问题 I've a text file, from that I want to match the full paragraph block but my current regex doesn't work to match full paragraph including the new line. Text Example: NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão OTHER TEXT GOES HERE .................... 020007/002832/2020. EXONERAR DOUGLAS ALVES BORRHER do cargo em comissão OTHER TEXT GOES HERE .................... 020007/002832/2020. NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo OTHER TEXT GOES HERE .................... 020007

问题 I've a text file, from that I want to match the full paragraph block but my current regex doesn't work to match full paragraph including the new line. Text Example: NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão OTHER TEXT GOES HERE .................... 020007/002832/2020. EXONERAR DOUGLAS ALVES BORRHER do cargo em comissão OTHER TEXT GOES HERE .................... 020007/002832/2020. NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo OTHER TEXT GOES HERE .................... 020007

来源： https://stackoverflow.com/questions/63631451/how-to-match-abbreviations-with-their-meaning-with-regex

来源： https://stackoverflow.com/questions/63631451/how-to-match-abbreviations-with-their-meaning-with-regex

来源： https://stackoverflow.com/questions/59804860/regex-match-characters-when-not-preceded-by-a-string