问题
I've a text file, from that I want to match the full paragraph block but my current regex doesn't work to match full paragraph including the new line.
Text Example:
NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão
OTHER TEXT GOES HERE
....................
020007/002832/2020.
EXONERAR DOUGLAS ALVES BORRHER do cargo em comissão
OTHER TEXT GOES HERE
....................
020007/002832/2020.
NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo
OTHER TEXT GOES HERE
....................
020007/002832/2020.
From the above text block I want to match the full paragraph starting with word NOMEAR
NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão
OTHER TEXT GOES HERE
....................
020007/002832/2020.
NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo
OTHER TEXT GOES HERE
....................
020007/002832/2020.
What I have tried
import re
pattern = re.compile("NOMEAR (.*)", re.DOTALL)
for i, line in enumerate(open('pdf_text_tika.txt')):
for match in re.finditer(pattern, line):
print ('Found on line %s: %s' % (i+1, match.group()))
Output:
Found on line 1305: NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão
Found on line 1316: NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo
回答1:
You may use this simpler regex using MULTILINE
mode:
^NOMEAR.+(?:\n.+)*
In python:
import re
pattern = re.compile(r'^NOMEAR.+(?:\n.+)*', re.MULTILINE)
with open('pdf_text_tika.txt', 'r') as file:
data = file.read()
print (pattern.findall(data))
RegEx Demo
回答2:
Using this pattern:
(NOMEAR (?:.+\n)+)
And this code:
import re
pattern = re.compile(r'(NOMEAR (?:.+\n)+)')
text = 'NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão\n' \
'OTHER TEXT GOES HERE\n' \
'....................\n' \
'020007/002832/2020.\n\n' \
'EXONERAR DOUGLAS ALVES BORRHER do cargo em comissão\n' \
'OTHER TEXT GOES HERE\n' \
'....................\n' \
'020007/002832/2020.\n\n' \
'NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo\n' \
'OTHER TEXT GOES HERE\n' \
'....................\n' \
'020007/002832/2020.'
print(pattern.findall(text))
The output is (I formatted the newlines to be more readable since it all came in one line):
['NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão\n
OTHER TEXT GOES HERE\n
....................\n
020007/002832/2020.\n',
'NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo\n
OTHER TEXT GOES HERE\n
....................\n']
回答3:
Are you trying to find 2 matches in your sample text; i.e., the 2 portions that begin with NOMEAR and end with a period followed by either 2 newlines or the end of the whole text?
import re
text = """NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão
OTHER TEXT GOES HERE
....................
020007/002832/2020.
EXONERAR DOUGLAS ALVES BORRHER do cargo em comissão
OTHER TEXT GOES HERE
....................
020007/002832/2020.
NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo
OTHER TEXT GOES HERE
....................
020007/002832/2020."""
pattern = re.compile("NOMEAR (?:.*?).(?:\n\n|\Z)", re.DOTALL)
matches = re.findall(pattern, text)
print("".join(matches))
回答4:
import re
t = """NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão
OTHER TEXT GOES HERE
....................
020007/002832/2020.
EXONERAR DOUGLAS ALVES BORRHER do cargo em comissão
OTHER TEXT GOES HERE
....................
020007/002832/2020.
NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo
OTHER TEXT GOES HERE
....................
020007/002832/2020."""
r = re.compile(r'(?=NOMEAR)(.*?)(?<=\d[.])', flags=re.S)
for i in r.finditer(t):
print(i.group(0))
NOMEAR JOSIAS CARLOS BORRHER do cargo em comissão
OTHER TEXT GOES HERE
....................
020007/002832/2020.
NOMEAR RAFAEL DOS SANTOS PASSAGEM para exercer o cargo
OTHER TEXT GOES HERE
....................
020007/002832/2020.
来源:https://stackoverflow.com/questions/65010417/python-regex-match-full-paragraph-including-new-line