regex-group

问题 How can I use capturing groups inside lookahead assertion? This code: say "ab" ~~ m/(a) <?before (b) > /; returns: ｢a｣ 0 => ｢a｣ But I was expecting to also capture 'b'. Is there a way to do so? I don't want to leave 'b' outside of the lookahead because I don't want 'b' to be part of the match. Is there a way to capture 'b' but still leave it outside of the match? NOTE: I tried to use Raku's capture markers, as in: say "ab" ~~ m/<((a))> (b) /; ｢a｣ 0 => ｢a｣ 1 => ｢b｣ But this does not seem to

问题 How can I use capturing groups inside lookahead assertion? This code: say "ab" ~~ m/(a) <?before (b) > /; returns: ｢a｣ 0 => ｢a｣ But I was expecting to also capture 'b'. Is there a way to do so? I don't want to leave 'b' outside of the lookahead because I don't want 'b' to be part of the match. Is there a way to capture 'b' but still leave it outside of the match? NOTE: I tried to use Raku's capture markers, as in: say "ab" ~~ m/<((a))> (b) /; ｢a｣ 0 => ｢a｣ 1 => ｢b｣ But this does not seem to

问题 How can I use capturing groups inside lookahead assertion? This code: say "ab" ~~ m/(a) <?before (b) > /; returns: ｢a｣ 0 => ｢a｣ But I was expecting to also capture 'b'. Is there a way to do so? I don't want to leave 'b' outside of the lookahead because I don't want 'b' to be part of the match. Is there a way to capture 'b' but still leave it outside of the match? NOTE: I tried to use Raku's capture markers, as in: say "ab" ~~ m/<((a))> (b) /; ｢a｣ 0 => ｢a｣ 1 => ｢b｣ But this does not seem to

问题 Nginx regex location syntaxe Regex expressions can be used with Nginx location block section, this is implemented with the PCRE engine. What does exactly this feature support as it is not fully documented? 回答1: Nginx location: Nginx location block section have a search order, a modifier, an implicit match type and an implicit switch to whether stop the search on match or not. the following array describe it for regex. # -------------------------------------------------------------------------

问题 I am trying to "append" new information to a CSV file. The problem is that that information is not in a dataframe structure, but is information extracted from a text using regular expressions. The sample text would be the next one: Lorem ipsum dolor sit amet, consectetur adipiscing elit. Etiam id diam posuere, eleifend diam at, condimentum justo. Pellentesque mollis a diam id consequat. TITLE-SDFSD-DFDS-SFDS-01-01: This is the title 1 that is split into two lines with a blank line in the

问题 I am trying to "append" new information to a CSV file. The problem is that that information is not in a dataframe structure, but is information extracted from a text using regular expressions. The sample text would be the next one: Lorem ipsum dolor sit amet, consectetur adipiscing elit. Etiam id diam posuere, eleifend diam at, condimentum justo. Pellentesque mollis a diam id consequat. TITLE-SDFSD-DFDS-SFDS-01-01: This is the title 1 that is split into two lines with a blank line in the

问题 I am trying to "append" new information to a CSV file. The problem is that that information is not in a dataframe structure, but is information extracted from a text using regular expressions. The sample text would be the next one: Lorem ipsum dolor sit amet, consectetur adipiscing elit. Etiam id diam posuere, eleifend diam at, condimentum justo. Pellentesque mollis a diam id consequat. TITLE-SDFSD-DFDS-SFDS-01-01: This is the title 1 that is split into two lines with a blank line in the

问题 I want to do a JavaScript replaceAll() using a variable (rather than a string) in a case-insensitive search, but also retaining the case of the matched text (in the return). For example, console.log('doc.p:', doc.p.toString().substring(0, 26)) var query = this.manager.store.get('q').value.toString(); console.log('query:', query, '| type:', typeof(query)) console.log(doc.p.toString().replaceAll(/(dna)/gi, '***$1***')) console.log(doc.p.toString().replaceAll(/(query)/gi, '***$1***')) is giving

问题 Team, I am trying to count two patterns in a file and list them as pattern1: 2 pattern2: 3 #!/usr/bin/python import os import re d = dict() with open('/home/user/waste/nodes-prod.log', 'r') as file: for line in file: line = line.strip() for word in line.split(): node1 = re.match(r"team1.*", word) type(node1) node2 = re.match(r"team2.*", word) type(node2) if node1 in d: d[node1] = d[node1] + 1 else: d[node2] = d[node2] + 1 for key in list(d.keys()): print(key, ":", d[key]) my /home/user/waste

问题 I need a regex expression that will select files with particular file name format from the file list of properties files. I need to select files with file names with following file format: <app_name>_<app_version>_<environment>.properties here <app_name> can be any alphanumeric with special character <A-Z/a-z/0-9/special char> like abc123 or app1-1 here <app_version> can be any alphanumeric with special character <A-Z/a-z/0-9/special char/float value> like abc or even float/integer/string 1.0