redundancy

问题 I have a list of character vector s: my.list <- list(e1 = c("a","b","c","k"),e2 = c("b","d","e"),e3 = c("t","d","g","a","f")) And I'm looking for a function that for any character that appears more than once across the list 's vector s (in each vector a character can only appear once), will only keep the first appearance. The result list for this example would therefore be: res.list <- list(e1 = c("a","b","c","k"),e2 = c("d","e"),e3 = c("t","g","f")) Note that it is possible that an entire

问题 I am working on a university assignment for a Object Oriented design module. Following linguistic analysis of nouns and verbs, and identification of use cases, the class diagram is now being made. The relevant parts of the program are as follows: The program is used by shop employees. There is a list of products that represent what is in the shop. Each product has unique details, including associated supplier and delivery company (which can have parent class called 'external company'). There

问题 I'm interested in cross-colo fail-over strategies for web applications, such that if the main site fails users seamlessly land at the fail-over site in another colo. The application side of things looks to be mostly figured out with a master-slave database setup between the colos and services designed to recover and be able to pick up mid-stream. I'm trying to figure out the strategy for moving traffic from the main site to the fail-over site. DNS failover, even with low TTLs, seems to carry

问题 How do I compare similar strings in jquery? <script src="../../js/jq.js"></script> <script> $(function(){ var str1 = $.trim($('#str1').val().toUpperCase()); var str2 = $.trim($('#str2').val().toUpperCase()); if(str1==str2){ console.log('yep'); } }); </script> <input type="text" id="str1" value="One String"/> <input type="text" id="str2" value="One String1"/> Comparing "One String" and "One String1" is not going to work if I'm only checking if the two values are equal. Is there any way to do

问题 I've built and installed (under the prefix ~/alt ) LLVM-Clang trunk (23 apr 2012) successfully using GCC-4.6 on Ubuntu 12.04 and in turn libc++ using this Clang-build. When I want to use it I have to supply both -lc++ and -libstdc++ as follows /home/per/alt/bin/clang -x c++ -I/home/per/alt/include/v1 -L/home/per/alt/lib -std=gnu++0x -g -Wall ~/f.cpp -lm -lc++ -lstdc++ -lpthread -o f to compile f.cpp containing #include <iostream> using std::cout; using std::endl; int main(int argc, const char

问题 map :: (a -> b) -> [a] -> [b] fmap :: Functor f => (a -> b) -> f a -> f b liftM :: Monad m => (a -> b) -> m a -> m b Why do we have three different functions that do essentially the same thing? 回答1: map exists to simplify operations on lists and for historical reasons (see What's the point of map in Haskell, when there is fmap?). You might ask why we need a separate map function. Why not just do away with the current list-only map function, and rename fmap to map instead? Well, that’s a good

问题 Cppcheck (version 1.46.1) gives the following warning for an enum like this one: enum DATABASE_TYPE { DATABASE_TYPE_UNKNOWN = -1, // <- line of warning DATABASE_TYPE_ORACLE, DATABASE_TYPE_MSACCESS }; Redundant code: Found a statement that begins with numeric constant I don't think, that it's redundant. It's quite important to be able to do things like that. Is this an error of cppcheck or am I not seeing something? Update I managed to boil it down to a minimal example. This was complicated by

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . I'm looking for Java libraries of the Reed Solomon algorithm. What I need is to partition a given file in different chunks with redundancy. So, after partitioning in N chunks, I can re-build the file with just K of these chunks (Where k < N). This is supposed to be one of the key features of Reed Solomon. This

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 4 years ago . I'm making a tankgame. In my PlayPanel class I wrote this code, as you can see it is mostly the same but it's used for 3 different ArrayList s. I would really like to know how to write this method once only in order to reuse it for all the ArrayList s because it seems so untidy. //obstacles for

问题 I'm new to setting up relational databases. I'm trying to create two tables in MySQL, a USER table and a COMPANY table. Both should be able to have multiple phone numbers associated with them, so I created a PHONE table and wanted to have a one-to-many relationship from both COMPANY to PHONE, and from USER to PHONE. There only seem to two options in what I am trying to do: Keep two foreign keys in PHONE, one referencing COMPANY, and one referencing USER. They would both default to NULL and