python-3.x

Groupby and drop NaN rows while preserving one in Pandas

余生长醉 提交于 2021-02-17 03:33:05
问题 Given a test dataset as follows: id city name 0 1 bj NaN 1 2 bj jack 2 3 bj NaN 3 4 bj jim 4 5 sh NaN 5 6 sh NaN 6 7 sh steve 7 8 sh fiona 8 9 sh NaN How could I groupby city and drop NaN rows for name while preserving one only for each group ? Many thanks. The expected result will like this: id city name 0 1 bj NaN 1 2 bj jack 2 4 bj jim 3 5 sh NaN 4 7 sh steve 5 8 sh fiona New dataset read by df = pd.read_clipboard(na_filter = False) from excel file, please note N/A should not be considered

pandas extract regex allowing mismatches

人盡茶涼 提交于 2021-02-17 03:30:16
问题 Pandas has a very fast and nice string method, extract(). This method works perfectly with a regex such as this one: strict_pattern = r"^(?P<pre_spacer>ACGAG)(?P<UMI>.{9,13})(?P<post_spacer>TGGAGTCT)" test_df R1 21 ACGAGTTTTCGTATTTTTGGAGTCTTGTGG 22 ACGAGTAGGGAGGGGGGTGGAGTCTCAGCG 23 ACGAGGGGGGGGAGGCTGGAGTCTCCGGGT 24 ACGAGAATAACGTTTGGTGGAGTCTACCAC 25 ACGAGGGGAATAAATATTGGAGTCTCCTCC 26 ACGAGATTGGGTATGCTGGAGTCTCTGTTC 27 ACGAGGTACCCGCGCCATGGAGTCTCTCTG 28 ACGAGTGGTTTTTGTCGTGGAGTCTCACCA 29

Would like to understand why switch_to_alert() is receiving a strikethrough and how to fix

拈花ヽ惹草 提交于 2021-02-17 03:29:50
问题 I'm trying to 'accept' a simple modal alert (an onscreen popup with only OK button) but switch_to_alert() in driver.switch_to_alert() is receiving a strikethrough (on pycharm). I'm using data driven testing script with OpenPyxl. I have written a condition that takes username and password from spreadsheet and adds it to login on webpage. If login is successful the code is work but the 'else' condition (ie. if fails login fails) is giving me issues due to the popup alert and I'm not sure how to

Getting started on python triple quotes

纵饮孤独 提交于 2021-02-17 03:19:48
问题 I wrote a simple triple quote print statement. See below. For the OVER lineart, it gets truncated into two different lines (when you copy paste this into the interpreter.) But, if I insert a space or any at the end of each of the lines, then it prints fine. Any idea why this behavior in python. I am inclined to think this is due to \ and / at the end of the lines, but I cannot find a concrete reason. I tried removing them and and have some observations but would like a clear reasoning.. print

Emiting QTableWidgetItem specific signal on being clicked

China☆狼群 提交于 2021-02-17 02:52:06
问题 I want to implement the functionality that multiple QTableWidgetItems inside of a QTableWidget can be selected and unselected so that the values and "positions" of those QTableWidgetItems is known for further use. Inside of the QTableWidget there are some empty cells, for aesthetics/spacing, which should be ignored by the functionality I'm trying to implement. But that could also easily be done afterwards by checking if a selected item does have content. self.table_widget.itemClicked.connect

Conda skeleton pypi: ModuleNotFoundError: No module named 'numpy'

自闭症网瘾萝莉.ら 提交于 2021-02-17 02:31:26
问题 I'm trying to create a conda package from a package I've uploaded to PyPI, by following this tutorial. I've downloaded and installed the latest Anaconda environment for Linux (Ubuntu 16.04). After installing conda-build I am able to run the conda skeleton pypi click command as per the example, but running it for my own package mf2 , I encounter the error: ModuleNotFoundError: No module named 'numpy' resulting in Error: command failed: <anaconda_path>/python setup.py install I've already tried

I encounter an AUTHENTICATIONFAILED error when connecting to email with imaplib library

谁说胖子不能爱 提交于 2021-02-17 02:11:06
问题 How can I connect to imaplib library without encountering AUTHENTICATIONFAILE error !? My Gmail inbox shows me a serious security alert (login attempt blocked) when logging in through the web browser. IMAP_SERVER = 'imap.gmail.com' USERNAME = '******@gmail.com' PASSWORD = '******' client = imaplib.IMAP4_SSL(IMAP_SERVER) client.login(USERNAME, PASSWORD) 回答1: This is most likely gmail blocking "less secure apps" from connecting to your account. This blocking is enabled, by default. From a

Dragging object along x-axis in pygame

南楼画角 提交于 2021-02-17 02:06:39
问题 I want to be able to drag the blue object along the x-axis (black line) using mouse so that it does not move in y-direction. When I try to drag it, nothing happens. Where is the problem? import pygame def initialize(): pygame.init() global height, width height = 600 width = 900 screen = pygame.display.set_mode((width, height)) screen.fill((255, 255, 255)) pygame.draw.line(screen, (0, 0 ,0), (0, height / 2), (width, height / 2), 3) return screen def object(): dragging = False object_1 = pygame

Dragging object along x-axis in pygame

試著忘記壹切 提交于 2021-02-17 02:06:26
问题 I want to be able to drag the blue object along the x-axis (black line) using mouse so that it does not move in y-direction. When I try to drag it, nothing happens. Where is the problem? import pygame def initialize(): pygame.init() global height, width height = 600 width = 900 screen = pygame.display.set_mode((width, height)) screen.fill((255, 255, 255)) pygame.draw.line(screen, (0, 0 ,0), (0, height / 2), (width, height / 2), 3) return screen def object(): dragging = False object_1 = pygame

Dragging object along x-axis in pygame

核能气质少年 提交于 2021-02-17 02:06:19
问题 I want to be able to drag the blue object along the x-axis (black line) using mouse so that it does not move in y-direction. When I try to drag it, nothing happens. Where is the problem? import pygame def initialize(): pygame.init() global height, width height = 600 width = 900 screen = pygame.display.set_mode((width, height)) screen.fill((255, 255, 255)) pygame.draw.line(screen, (0, 0 ,0), (0, height / 2), (width, height / 2), 3) return screen def object(): dragging = False object_1 = pygame