python-3.7

问题 I have to run a bokeh script as a module using the -m option from the top directory, because it needs to import some other portable module under the same directory python -m bokeh_module.bokeh_sub_module The directory tree is shown below. By running the above command, it doesn't show the image no matter where the png file is placed, is there a way to resolved the issue? Thank you for any help. . ├── other_module │ ├── __init__.py │ └── other_sub_module.py ├── bokeh_module │ ├── __init__.py │

问题 ModuleNotFoundError: No module named 'pandas_datareader' Hello peeps, I need help with this ModuleNotFoundError: No module named 'pandas_datareader'. i have installed pandas_datareader more than 10x using pip install command but returns this error in both Pycharm and the default IDLE for python 3.7. I know there already a couple of threats on this forum addressing this issue, but non has helped me so far. Confession: I'm a newbie in python (40 hours experience so far)switching careers from

问题 I have an application that ran fine under the Python 2.7 Standard framework, and runs fine as two separate applications in the 3.7 framework, but I can't figure out how to configure them as a single application with two services. main.app consists of the following two lines (paralleling what used to work in the 2.7 framework) from app import app from update import update The app.yaml for main consists of nothing but runtime: python37 Each of the two python packages under main (app and update)

问题 ModuleNotFoundError: No module named '_tkinter' I want to import turtle in Python 3.7 Traceback (most recent call last): File "my.py", line 1, in from turtle import * File "/usr/local/lib/python3.7/turtle.py", line 107, in import tkinter as TK File "/usr/local/lib/python3.7/tkinter/ init .py", line 36, in import _tkinter # If this fails your Python may not be configured for Tk ModuleNotFoundError: No module named '_tkinter' 回答1: The IDE tells you that your python is not confingured for Tk

问题 Hi i am trying to fix this issue when i run python3 brain.py below i get this error Illegal instruction (core dumped) from imageai.Prediction import ImagePrediction import os execution_path=os.getcwd() prediction = ImagePrediction() prediction.setModelTypeAsSqueezeNet() prediction.setModelPath(os.path.join(execution_path, "squeezenet_weights_tf_dim_ordering_tf_kernels.h5")) prediction.loadModel() predictions, probabilities = prediction.predictImage(os.path.join(execution_path, "giraffe.jpg"),

问题 I'm attempting a countdown clock in python 3.7 using win10toast, time and playsound. Here's the code: import time import playsound import win10toast Toaster = win10toast.ToastNotifier() def countdown(y): while y > 0: print(y) y -= 1 time.sleep(1) playsound.playsound('alarm-clock-ringing.mp3') Toaster.show_toast('Countdown notifier', 'countdown over', duration=9, icon_path=r'D:\img.ico') try: x = int(input('how many seconds do you want to countdown?: ')) countdown(x) except ValueError: print(

问题 I am using Python 3.7 on Windows. What I am trying to do: - lock a method of an instance of a class, when another process has acquired that same lock. Attempts: I have already successfully done this, but I don't want a global variable here for the lock, but instead one completely internal to the class from multiprocessing import Lock, freeze_support,Pool from time import sleep def do_work(name): print(name+' waiting for lock to work...',end='') sleep(2) with lock: print('done!') print(name+'

问题 I am using Python 3.7 on Windows. What I am trying to do: - lock a method of an instance of a class, when another process has acquired that same lock. Attempts: I have already successfully done this, but I don't want a global variable here for the lock, but instead one completely internal to the class from multiprocessing import Lock, freeze_support,Pool from time import sleep def do_work(name): print(name+' waiting for lock to work...',end='') sleep(2) with lock: print('done!') print(name+'

问题 I am using Python 3.7 on Windows. What I am trying to do: - lock a method of an instance of a class, when another process has acquired that same lock. Attempts: I have already successfully done this, but I don't want a global variable here for the lock, but instead one completely internal to the class from multiprocessing import Lock, freeze_support,Pool from time import sleep def do_work(name): print(name+' waiting for lock to work...',end='') sleep(2) with lock: print('done!') print(name+'

问题 I'm trying to build a @dataclass that defines a schema but is not actually instantiated with the given members. (Basically, I'm hijacking the convenient @dataclass syntax for other purposes). This almost does what I want: @dataclass(frozen=True, init=False) class Tricky: thing1: int thing2: str def __init__(self, thing3): self.thing3 = thing3 But I get a FrozenInstanceError in the __init__ method: dataclasses.FrozenInstanceError: cannot assign to field 'thing3' I need the frozen=True (for