问题
I have to run a bokeh script as a module using the -m option from the top directory, because it needs to import some other portable module under the same directory
python -m bokeh_module.bokeh_sub_module
The directory tree is shown below. By running the above command, it doesn't show the image no matter where the png file is placed, is there a way to resolved the issue? Thank you for any help.
.
├── other_module
│ ├── __init__.py
│ └── other_sub_module.py
├── bokeh_module
│ ├── __init__.py
│ ├── image.png # not showing
│ └── bokeh_sub_module.py
└── image.png # not showing either
bokeh_sub_module.py
from other_module import other_sub_module
from bokeh.plotting import figure, show
# do something with other_sub_module
p = figure(match_aspect=True)
p.image_url( ['image.png'], 0, 0, 1, 1 ) # not showing
p.image_url( ['./bokeh_module/image.png'], 0, 0, 1, 1 ) # not showing either
show(p)
By the way, if I run pytohn bokeh_sub_module.py from the bokeh_module directory, the image.png inside the same directory can be found with no problems.
回答1:
image_url requires URLs, and neither of your calls to image_url use URLs.
Try to use absolute URLs and add file:// in front of them.
来源：https://stackoverflow.com/questions/62623089/plot-a-local-image-using-bokeh-image-url-by-running-python-with-the-m-option