proc

问题 I have gcc-4.6 & gcc-4.7 both installed on my machine and I made gcc the default compiler. But still I could see 4.6 under "cat /proc/version" but I want 4.7 in place of 4.6. cat /proc/version Linux version 3.2.0-4-rt-686-pae (debian-kernel@lists.debian.org) (gcc version 4.6.3 (Debian 4.6.3-14) ) #1 SMP PREEMPT RT Debian 3.2.65-1+deb7u2 How can I change gcc version here from 4.6 to 4.7 ? Any help would be really helpfull for me. Many Thanks. 回答1: As the same problem is mentioned here https:/

问题 This question already has answers here : What does map(&:name) mean in Ruby? (15 answers) Closed 5 years ago . I'm reviewing someone's ruby code and in it they've written something similar to: class Example attr_reader :val def initialize(val) @val = val end end def trigger puts self.val end anArray = [Example.new(10), Example.new(21)] anArray.each(&:trigger) The :trigger means the symbol is taken and the & transforms it into a proc ? If that's correct, is there any way of passing variables

问题 To my PHPeoples, This is sort of a weird PHPuzzle, but I'm wondering if it's PHPossible. The end goal is the equivalent functionality of mysql mydb < file.sql But with an API like this ./restore < file.sql Where restore is a PHP script like this #!/usr/bin/env php $cmd = "msyql mydb"; passthru($cmd, $status); However, I want to pass STDIN to the passthru command. The clear benefit here is that I can put restore somewhere in a pipeline and everything works peachy. Here's an example # would be

问题 This question already has answers here : Ruby ampersand colon shortcut [duplicate] (2 answers) What does map(&:name) mean in Ruby? (15 answers) Closed 6 years ago . Here's the line of code I'm trying to wrap my head around: Category.all.map(&:id).each { |id| Category.reset_counters(id, :products) } Hoping someone can help me understand what (&:id) is doing and how it impacts the rest of the line? I believe it turns the symbol :id into a proc that'll respond to id ?!? But then it gets

问题 I have the following code: ods tagsets.excelxp file = 'G:\CPS\myworkwithoutmissing.xml' style = printer; proc tabulate data = final; Class Year Self_Emp_Inc Self_Emp_Uninc Self_Emp Multi_Job P_Occupation Full_Part_Time_Status; table Year, P_Occupation*n; table Year, (P_Occupation*Self_Emp_Inc)*n; table Year, (Self_Emp_Inc*P_Occupation)*n; run; ods tagsets.excelxp close; When I run this code, I get the following error message: WARNING: A class, frequency, or weight variable is missing on every

问题 Is it possible to configure Oracle 11g installation so that it has more than 18 characters length? Investigating possible cause of locally un-producible bug that might have been caused if customer configured rowid to have more than 18 characters. The table doesn't have an index. Using rowid to delete given records shortly after, but it's possible that other records are inserted in between. 回答1: If you're really looking at a logical ROWID (UROWID) or a ROWID from a non-Oracle database, sure.

问题 I am writing an EDA utility, relying on a TCL 8.6 compliant API. My challenge is as follows: My utility runs on transistors' models in the database, and does some analyisis, using an EDA vendors' TCL API command. I can pass to the TCL commands a TCL procedure name/pointer, and the analysis will rely on my code, rather than the EDA vendors' code. The in-house written proc accepts as an argument a pointer to the specific transistor's instance in the EDA vendor's database. Now, the EDA vendor

问题 This question was migrated from Unix & Linux Stack Exchange because it can be answered on Stack Overflow. Migrated 5 years ago . I'm trying to compile "slock" to implement some tweaks. It fails to start, on this: #ifdef __linux__ #include <fcntl.h> static void dontkillme(void) { int fd; fd = open("/proc/self/oom_score_adj", O_WRONLY); if (fd < 0 && errno == ENOENT) return; if (fd < 0 || write(fd, "-1000\n", 6) != 6 || close(fd) != 0) die("cannot disable the out-of-memory killer for this

问题 Wondering how this following can be done in base SAS. I've got the following code. libname SASData '/folders/myfolders/Datafiles'; data chap9ques6; set SASData.medical(keep=VisitDate); DayOfWeek = weekday(VisitDate); run; proc format; value Days 1='Sunday' 2='Monday' 3='Tuesday' 4='Wednesday' 5='Thursday' 6='Friday' 7='Saturday'; run; proc freq data=chap9ques6; tables DayOfWeek /nocum nopercent missprint; Format DayOfWeek Days.; run; Which produces an acceptable result like this. The FREQ

问题 As we know there is some process which is faster than other. But I always wonder Why proc process faster than others? 回答1: Confusion. The /proc/ file system (read proc(5)) is indeed a pseudo-file system without real files on any hard disk. So reading it is quick (and could be faster than reading a file on a spinning hard disk). For example you could write some C code fopen -ing /proc/self/maps , looping on every line using fgets , and showing that line on your stdout , and finally fclose ing