println

What is the difference between System.out.println() and System.err.println() in Java? Carlos G. In Java System.out.println() will print to the standard out of the system you are using. On the other hand, System.err.println() will print to the standard error. If you are using a simple Java console application, both outputs will be the same (the command line or console) but you can reconfigure the streams so that for example, System.out still prints to the console but System.err writes to a file. Also, IDEs like Eclipse show System.err in red text and System.out in black text by default. System

I am new to Java programming, and today while messing with eclim and vim, I discovered that the System.out.println(); function is not working. class apples{ public static void main(String args[]){ double tuna = 5.28; System.out.print(tuna); } } This does not give me a result. But when I do: class apples{ public static void main(String args[]){ double tuna = 5.28; System.out.println(tuna); } } (The only difference is the "println") I get 5.28, the correct behavior. Anyone know why this would happen, or is this the way it should be happening? .println() automatically appends a newline, .print()

What are some scenarios in which java's System.out.println would fail to produce any output. I have a call to it inside of a method and sometimes when the method is called I get the println and othertimes I don't. Update: I am also using System.out.flush() after the println. Update: Thank you for the debugging help. It turned out a blocking call to open a dialog made output appear vastly out of the proper order. I thought the method I was trying to print messages for was being called when the dialog closed but the method itself was what was calling the dialog and so after the closing it was

The use of println and print in Swift both print to the console. But the only difference between them seems to be that println returns to the next line whereas print will not. For example: println("hello world") println("another world") will output the following two lines: hello world another world while: print("hello") print("world") outputs only one line: helloworld The print seems to be more like the traditional printf in C. The Swift documentation states that println is the equivalent to NSLog but what's the purpose of print , is there any reason to use it other than not returning to the

I have a multi-threaded Java application that will output information about a message it receives to the console for debugging purposes. Each time the application receives a message, it will call a System.out.println(String) on the message. The problem that I am having is that if the application gets flooded with messages, System.out.println() prints erroneous information (like old buffer information). This is leading me to wonder if there is a threading issue where multiple threads are calling the println function at one time, and not properly flushing the buffer. In my main program (thread),

I have a doubt which follows. public static void main(String[] args) throws IOException{ int number=1; System.out.println("M"+number+1); } Output: M11 But I want to get it printed M2 instead of M11. I couldn't number++ as the variable is involved with a for loop, which gives me different result if I do so and couldn't print it using another print statement, as the output format changes. Requesting you to help me how to print it properly. Óscar López Try this: System.out.printf("M%d%n", number+1); Where %n is a newline Add a bracket around your sum, to enforce the sum to happen first. That way,