println

Can we print a java message on console without using main method, static variable and static method?

眉间皱痕 提交于 2019-12-07 05:08:08
问题 public class Test { /** * @param args */ // 1st way public static void main(String[] args) { // TODO Auto-generated method stub System.out.println("Test....!!!!!"); } // 2nd way static{ System.out.println("Test....!!!!!"); System.exit(1); } // 3rd way private static int i = m1(); public static int m1(){ System.out.println("Test...!!!!"); System.exit(0); return 0; } Other than this, can we print message any other way. 回答1: Of course you can, from a class constructor, method or instance block

How do I print variables in Rust and have it show everything about that variable, like Ruby's .inspect?

流过昼夜 提交于 2019-12-05 17:49:19
问题 use std::collections::HashMap; fn main() { let mut hash = HashMap::new(); hash.insert("Daniel", "798-1364"); println!("{}", hash); } will fail to compile: error[E0277]: `std::collections::HashMap<&str, &str>` doesn't implement `std::fmt::Display` --> src/main.rs:6:20 | 6 | println!("{}", hash); | ^^^^ `std::collections::HashMap<&str, &str>` cannot be formatted with the default formatter | Is there a way to say something like: println!("{}", hash.inspect()); and have it print out: 1) "Daniel"

java System.out.println() strange behavior long string

社会主义新天地 提交于 2019-12-05 10:03:02
Can somebody explain me why this code does not print the numbers? String text = new String("SomeString"); for (int i=0; i<1500; i++) { text = text.concat(i+""); } System.out.println(text); Result SomeString If I lower the number of runs to 1000 it works, why?! And also if I add not only a number but also a character, it works. Ok New Update: Thanks for the code examples. I tried them all but what I found out is, that the console actually display the numbers but only in fontcolor white. But the first part of the String SomeString is black. I use jdk1.7.0_06 ! This is eclipse bug. Fixed width

println in scala for-comprehension

血红的双手。 提交于 2019-12-05 08:48:06
问题 In a for-comprehension, I can't just put a print statement: def prod (m: Int) = { for (a <- 2 to m/(2*3); print (a + " "); b <- (a+1) to m/a; c = (a*b) if (c < m)) yield c } but I can circumvent it easily with a dummy assignment: def prod (m: Int) = { for (a <- 2 to m/(2*3); dummy = print (a + " "); b <- (a+1) to m/a; c = (a*b) if (c < m)) yield c } Being a side effect, and only used (so far) in code under development, is there a better ad hoc solution? Is there a serious problem why I

Can we print a java message on console without using main method, static variable and static method?

半腔热情 提交于 2019-12-05 08:24:36
public class Test { /** * @param args */ // 1st way public static void main(String[] args) { // TODO Auto-generated method stub System.out.println("Test....!!!!!"); } // 2nd way static{ System.out.println("Test....!!!!!"); System.exit(1); } // 3rd way private static int i = m1(); public static int m1(){ System.out.println("Test...!!!!"); System.exit(0); return 0; } Other than this, can we print message any other way. Mena Of course you can, from a class constructor, method or instance block for instance. However if you're talking about launching a simple program with the command line (e.g.

What is in android.util.Log#println_native()?

纵然是瞬间 提交于 2019-12-04 19:35:44
Here is the android.util.Log source code. At the very bottom (line 340), what is in the method: public static native int println_native(int bufID, int priority, String tag, String msg); i guess println_native() is more or less like its println() , just with an int bufID different. But even i got the codes of println_native() , i still lack com.android.internal.os.RuntimeInit (line 19, the import ) to simulate android.util.Log in old Android version. Just did some digging in the android source code. This function maps to static jint android_util_Log_println_native(JNIEnv* env, jobject clazz,

System.out.println not functioning

走远了吗. 提交于 2019-12-04 03:37:27
问题 What are some scenarios in which java's System.out.println would fail to produce any output. I have a call to it inside of a method and sometimes when the method is called I get the println and othertimes I don't. Update: I am also using System.out.flush() after the println. Update: Thank you for the debugging help. It turned out a blocking call to open a dialog made output appear vastly out of the proper order. I thought the method I was trying to print messages for was being called when the

How do I print variables in Rust and have it show everything about that variable, like Ruby's .inspect?

情到浓时终转凉″ 提交于 2019-12-04 03:00:30
use std::collections::HashMap; fn main() { let mut hash = HashMap::new(); hash.insert("Daniel", "798-1364"); println!("{}", hash); } will fail to compile: error[E0277]: `std::collections::HashMap<&str, &str>` doesn't implement `std::fmt::Display` --> src/main.rs:6:20 | 6 | println!("{}", hash); | ^^^^ `std::collections::HashMap<&str, &str>` cannot be formatted with the default formatter | Is there a way to say something like: println!("{}", hash.inspect()); and have it print out: 1) "Daniel" => "798-1364" Nate Mara What you're looking for is the Debug formatter: use std::collections::HashMap;

println in scala for-comprehension

你。 提交于 2019-12-03 22:08:34
In a for-comprehension, I can't just put a print statement: def prod (m: Int) = { for (a <- 2 to m/(2*3); print (a + " "); b <- (a+1) to m/a; c = (a*b) if (c < m)) yield c } but I can circumvent it easily with a dummy assignment: def prod (m: Int) = { for (a <- 2 to m/(2*3); dummy = print (a + " "); b <- (a+1) to m/a; c = (a*b) if (c < m)) yield c } Being a side effect, and only used (so far) in code under development, is there a better ad hoc solution? Is there a serious problem why I shouldn't use it, beside being a side effect? update showing the real code, where adapting one solution is

Scala a better println

偶尔善良 提交于 2019-12-03 16:15:51
I often find myself doing things like: println(foo) when I'd like to do: println foo The compiler does not allow this. Also, println is a mouthful, I really just want to say: echo foo So, in a base package object I created the echo version of println: def echo(x: Any) = Console.println(x) Easy enough, have echo application wide, great. Now, how do I invoke echo without needing to wrap the Any to print in parens? object ∊ {def cho(s: Any) {println(s)}} ∊cho "Hello world" will save your fingers. It works because ∊ is a math-symbol in the Unicode Sm set, hence counts as an operator in Scala , so