prefix-operator

How to differentiate (when overloading) between prefix and postfix forms of operator++? (C++)

二次信任 提交于 2019-11-27 14:48:47
Because I've overloaded the operator++ for an iterator class template<typename T> typename list<T>::iterator& list<T>::iterator::operator++() { //stuff } But when I try to do list<int>::iterator IT; IT++; I get a warning about there being no postifx ++ , using prefix form. How can I specifically overload the prefix/postifx forms? Daniel Earwicker Write a version of the same operator overload, but give it a parameter of type int . You don't have to do anything with that parameter's value. If you're interested in some history of how this syntax was arrived out, there's a snippet of it here .

What does “!--” do in JavaScript?

会有一股神秘感。 提交于 2019-11-27 08:56:14
问题 I have this piece of code (taken from this question): var walk = function(dir, done) { var results = []; fs.readdir(dir, function(err, list) { if (err) return done(err); var pending = list.length; if (!pending) return done(null, results); list.forEach(function(file) { file = path.resolve(dir, file); fs.stat(file, function(err, stat) { if (stat && stat.isDirectory()) { walk(file, function(err, res) { results = results.concat(res); if (!--pending) done(null, results); }); } else { results.push

Prefix form of unary operator in Haskell

本小妞迷上赌 提交于 2019-11-27 05:38:01
In GHCi: Prelude> (+3) 2 5 Prelude> (*3) 2 6 Prelude> (/3) 2 0.6666666666666666 Prelude> (-3) 2 No instance for (Num (t -> t1)) arising from the literal 3' at <interactive>:1:2 Possible fix: add an instance declaration for (Num (t -> t1)) In the expression: 3 In the expression: (- 3) 2 In the definition of it': it = (- 3) 2 How can I correct the last one to make it return -1? Haskell's grammar doesn't allow you to use - like that. Use the subtract function instead: (subtract 3) 2 Travis Brown As a footnote to grddev's answer , here's the relevant paragraph from the Haskell 98 Report : The

Prefix form of unary operator in Haskell

我的梦境 提交于 2019-11-26 11:42:11
问题 In GHCi: Prelude> (+3) 2 5 Prelude> (*3) 2 6 Prelude> (/3) 2 0.6666666666666666 Prelude> (-3) 2 No instance for (Num (t -> t1)) arising from the literal 3\' at <interactive>:1:2 Possible fix: add an instance declaration for (Num (t -> t1)) In the expression: 3 In the expression: (- 3) 2 In the definition of it\': it = (- 3) 2 How can I correct the last one to make it return -1? 回答1: Haskell's grammar doesn't allow you to use - like that. Use the subtract function instead: (subtract 3) 2 回答2:

What is the difference between prefix and postfix operators?

▼魔方 西西 提交于 2019-11-26 01:24:33
问题 The following code prints a value of 9. Why? Here return(i++) will return a value of 11 and due to --i the value should be 10 itself, can anyone explain how this works? #include<stdio.h> main() { int i= fun(10); printf(\"%d\\n\",--i); } int fun (int i) { return(i++); } 回答1: There is a big difference between postfix and prefix versions of ++ . In the prefix version (i.e., ++i ), the value of i is incremented, and the value of the expression is the new value of i . In the postfix version (i.e.,

Why avoid increment (“++”) and decrement (“--”) operators in JavaScript?

人盡茶涼 提交于 2019-11-25 22:45:39
问题 One of the tips for jslint tool is: ++ and -- The ++ (increment) and -- (decrement) operators have been known to contribute to bad code by encouraging excessive trickiness. They are second only to faulty architecture in enabling to viruses and other security menaces. There is a plusplus option that prohibits the use of these operators. I know that PHP constructs like $foo[$bar++] has may easily result with off-by-one errors, but I couldn\'t figure out a better way to control the loop than a