polynomials

Function for polynomials of arbitrary order (symbolic method preferred)

ぃ、小莉子 提交于 2019-12-17 20:14:22
问题 I've found polynomial coefficients from my data: R <- c(0.256,0.512,0.768,1.024,1.28,1.437,1.594,1.72,1.846,1.972,2.098,2.4029) Ic <- c(1.78,1.71,1.57,1.44,1.25,1.02,0.87,0.68,0.54,0.38,0.26,0.17) NN <- 3 ft <- lm(Ic ~ poly(R, NN, raw = TRUE)) pc <- coef(ft) So I can create a polynomial function: f1 <- function(x) pc[1] + pc[2] * x + pc[3] * x ^ 2 + pc[4] * x ^ 3 And for example, take a derivative: g1 <- Deriv(f1) How to create a universal function so that it doesn't have to be rewritten for

R: Translate a model having orthogonal polynomials to a function using qr decomposition

落爺英雄遲暮 提交于 2019-12-14 00:15:28
问题 I'm using R to create a linear regression model having orthogonal polynomial. My model is: fit=lm(log(UFB2_BITRATE_REF3) ~ poly(QPB2_REF3,2) + B2DBSA_REF3,data=UFB) UFB2_FPS_REF1= 29.98 27.65 26.30 25.69 24.68 23.07 22.96 22.16 21.51 20.75 20.75 26.15 24.59 22.91 21.02 19.59 18.80 18.21 17.07 16.74 15.98 15.80 QPB2_REF1 = 36 34 32 30 28 26 24 22 20 18 16 36 34 32 30 28 26 24 22 20 18 16 B2DBSA_REF1 = DOFFSOFF DOFFSOFF DOFFSOFF DOFFSOFF DOFFSOFF DOFFSOFF DOFFSOFF DOFFSOFF DOFFSOFF DOFFSOFF

Print polynomial in variable format in python

别说谁变了你拦得住时间么 提交于 2019-12-13 02:36:12
问题 from numpy import linalg,dot import numpy.polynomial.polynomial as poly x7=poly.Polynomial([1,2]) print x7 according to above code in python it should print 1 + 2x^2, but it is printing poly [1. 2.]. Please help. 回答1: I'd recommend using numpy.poly1d and numpy.polymul , where the coefficients are a0*x2 + a1*x + a2 . For example, to represent 3*x**2 + 2*x + 1 : p1 = numpy.poly1d([3,2,1]) therefor for your problem you could use: p2= numpy.poly1d([2,0,1]) print p2 and printing p2 will represent:

I have a A = 3×3 matrix in which position of elements are to be shuffled based on polynomial function result

霸气de小男生 提交于 2019-12-12 05:15:44
问题 A = [1 2 3; 4 5 6; 7 8 9]; Now reshaping the matrix A to form a row vector gives B. B = [1 4 7 2 5 8 3 6 9]; Evaluating polynomial function f(x) = (7x+6x^2+3x^3)mod 9 by putting values for 'x' ranging from (1,...,9) since there are 9 elements. Ex. For x=1, f(x) = 16 mod 9 = 7 For x=2, f(x) = 62 mod 9 = 8 till x = 9 results in permute. permute = [7 8 3 1 2 6 4 5 9]; permute vector gives positions. Using matrix indexing, the positions of elements in row vector B are arranged according to

Pretty printing polynomials with dictionary python

匆匆过客 提交于 2019-12-11 12:18:54
问题 I'm struggling to create the __ str __ function (aka pretty print) with polynomials, where dictionaries are used to contain the powers as keys and the elements as coefficients. I have done it with lists but I haven't mastered dictionaries yet. Is there anything to improve? You can see in the second polynomial that if my last constant is not a constant, after arranging the keys with the reverse() function, the plus is always there, what can i do to prevent that? By the way I am trying to

Generate random polynomials with MATLAB

情到浓时终转凉″ 提交于 2019-12-11 12:07:44
问题 I want to generate random binary polynomials with parameters (n,m) . n is the number of polynomials to be generated and m is the number of elements of each polynomials. At the same time I need it's polynomial to be unique. And I also need to exclude the result with all elements equal to zero. For example for n=3 and m=3 I am looking for something like [1 0 1] [1 0 0] [1 1 1] . Is there any command in mat lab which I can use to have the above results?? I would also like to avoid the for loop

Creating a python lmfit Model with arbitrary number of parameters

邮差的信 提交于 2019-12-11 04:27:27
问题 Is there a way to construct a an lmfit Model based on a function with an arbitrary number of dependent variables? For example: from lmfit import Model def my_poly(x, *params): func = 0 for i in range(len(params)): func+= params[i]*z**i return func #note: below does not work my_model = Model(my_poly, independent_vars = ['x'], param_names = ['A','B','C']) Something similar to the above would be wonderful if I am interested in a polynomial series and want to test the performance as the series

Extract the coefficients of a polynomial with istringstream c++

自作多情 提交于 2019-12-11 03:08:47
问题 currently i'm working on a project (namely, creating a class of a polynomial) and i've already implemented the "add-subtract-divide-and-so-on" methods. But i'm stuck on a method to pass from a string like that 3x^1-2x^4 to a vector of coefficients like 0 3 0 0 4. So here's the code: string s; cin >> s; istringstream iss(s); double coeff; char x, sym; int degree; vector<double> coefficients; int i = 0; while (iss >> coeff >> x >> sym >> degree) { //if (sign == '-') coeff *= -1; if (degree == i

Find the coefficients of the polynomial given its roots

家住魔仙堡 提交于 2019-12-10 18:27:12
问题 I am trying to write an algorithm which will find a(0),..., a(n-1) , given the values of n, x_1, ..., x_n, a(n) , such that: a(n)*p^n + a(n-1)*p^(n-1) + ... + a(1)*p + a(0) = a(n)(p-x_1)(p-x_2)...(p-x_n) for all real p. After multiplying a(n)(p-x_1)(p-x_2) I've thought of using Viete's formulas to find the coefficients. But it turns out writing the code down isn't as obvious as I expected. I want to use only the basics in my code - that is loops, if-s addition and multiplication - no ready/

Polynomial function cannot be solved by Python sympy

て烟熏妆下的殇ゞ 提交于 2019-12-10 15:29:03
问题 I have problems by solving a polynomial function with sympy. The following example shows a case which gives an error message that I cannot manage. If the polynomial gets simpler the solver works properly. Please copy and paste the code to check the error on your system as well. import sympy from sympy import I omega = sympy.symbols('omega') def function(omega): return - 0.34*omega**4 \ + 7.44*omega**3 \ + 4.51*I*omega**3 \ + 87705.64*omega**2 \ - 53.08*I*omega**2 \ - 144140.03*omega \ - 22959