polar-coordinates

Matplotlib polar plot radial axis offset

你说的曾经没有我的故事 提交于 2019-12-04 03:19:53
I was wondering, is it possible to offset the start of the radial axis or move it outside of the graph. This is what I'm hoping to achieve: And this is what I have for now. I have read the documentation and different topics on SO, but I couldn't find anything helpful. Does that mean that it is not even possible if it is not mentioned anywhere. Thank you in advance. EDIT (added snippet of a code used to create the plot): ax = fig.add_subplot(111, projection='polar') ax.set_theta_zero_location('N') ax.set_theta_direction(-1) ax.plot(X,lines[li]*yScalingFactor,label=linelabels[li],color=color

SVG polar gradients

血红的双手。 提交于 2019-12-03 16:06:28
I'm a beginner at SVG, but I'd like to learn some techniques. To be short, is there a simple way to create something like this? I was thinking about creating a polar gradient and then clipping it: But how do I generate a polar gradient? Even if there's no native method, maybe it could be made with a simple linear gradient and then using some rectangular-polar coordinate transformation. Is there a way to do so? So this is the solution I developed: <?xml version="1.0" standalone="no"?> <!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 1.1//EN" "http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd"> <svg viewBox

get point coordinates based on direction and distance (vector)

女生的网名这么多〃 提交于 2019-12-03 07:36:43
问题 I need to find the coordinates of the second point. I know the angle between the points in radians and I also know the length of the vector. I would really appreciate if someone could point me towards the solution. 回答1: Given L as the length of the vector and Ang the angle x2 = x1 + Math.cos(Ang) * L y2 = y1 + Math.sin(Ang) * L Oops... I just noted the top to bottom orientation of the Y axis... Konstantin Levin, you will need adapt slightly because the formulas above assume a typical

Python Uniform distribution of points on 4 dimensional sphere

风格不统一 提交于 2019-12-03 07:10:49
I need a uniform distribution of points on a 4 dimensional sphere. I know this is not as trivial as picking 3 angles and using polar coordinates. In 3 dimensions I use from random import random u=random() costheta = 2*u -1 #for distribution between -1 and 1 theta = acos(costheta) phi = 2*pi*random x=costheta y=sin(theta)*cos(phi) x=sin(theta)*sin(phi) This gives a uniform distribution of x, y and z. How can I obtain a similar distribution for 4 dimensions? A standard way , though, perhaps not the fastest , is to use Muller's method to generate uniformly distributed points on an N-sphere:

modified polar plot using ggplots or other alternative packages using R

独自空忆成欢 提交于 2019-12-03 05:01:56
I am trying to create nice (!) polar plot with the following data. gr1 <- c(0, 5, 15, 20, 30, 40) gr3 <- c(0, 5, 10, 25, 40, 60, 80) gr2 <- c(0, 15, 25, 30, 40) df2<- data.frame (pos = c(gr1, gr2, gr3), group = c(rep(1, length(gr1)), rep(2, length(gr1)), rep(2, length(gr1)))) inner circle segment to mark first tier, group 1, between 15, 20 group 3, between 5, 10 between 40 to 60 second tier, group 1, between 15, 20 group 3, between 5, 10 between 10, 25 between 40 to 60 The angle between two lines between the interval between two pos. there are more than two tier in my real data to plot. The

Circular Stacked Bar Plot in R

泄露秘密 提交于 2019-12-03 03:34:41
I came across this awesome and relatively straightforward package seen here that can create beautiful normalized stacked bar plots in polar form like so . I hope to create a similar plot but that is not normalized and can instead have raw values as input. On his blog, he indicates that someone made a un-normalized version of his code that can produce plots like this: This is almost exactly what I need but I can't figure out how to stack the bars to produce a graph like so (sorry for quality): Here is some toy data that is a subset of the real data I will use and that follows his input format:

get point coordinates based on direction and distance (vector)

社会主义新天地 提交于 2019-12-02 20:20:30
I need to find the coordinates of the second point. I know the angle between the points in radians and I also know the length of the vector. I would really appreciate if someone could point me towards the solution. Given L as the length of the vector and Ang the angle x2 = x1 + Math.cos(Ang) * L y2 = y1 + Math.sin(Ang) * L Oops... I just noted the top to bottom orientation of the Y axis... Konstantin Levin, you will need adapt slightly because the formulas above assume a typical trigonometric coordinates system. In your case the formulas should be: x2 = x1 + Math.cos(Ang) * L // unchanged y2 =

GPU ray casting (single pass) with 3d textures in spherical coordinates

好久不见. 提交于 2019-12-01 11:33:11
i' am implementing an algorithm of volume rendering "GPU ray casting single pass". For this, i used a float array of intensity values as 3d textures ( this 3d textures describes a regular 3d grid in spherical coordinates ). Here there are example of array values: 75.839354473071637, 64.083049468866022, 65.253933716444365, 79.992431196592577, 84.411485976957096, 0.0000000000000000, 82.020319431382831, 76.808403454586994, 79.974774618246158, 0.0000000000000000, 91.127273013466336, 84.009956557448433, 90.221356094672814, 87.567422484025627, 71.940263118478072, 0.0000000000000000, 0

Arrows in Polar Matplotlib Plot

笑着哭i 提交于 2019-12-01 09:03:40
I am trying to plot the phasors of the voltage across the resistor, capacitor, and inductor in an series R-L-C circuit. I have done all of the calculations and I can get a decent plot with just the normal ax.plot(theta,r,....) . I would like to make the phasor vectors look like arrows. I have been trying to use ax.arrow(0,0,theta,magnitude) but it looks like a line still. The gist to the code that I have written is here : GIST My image that I create is I tried to follow the example that I found on this list because it is very similar to what I want to accomplish, it produces the following

Arrows in Polar Matplotlib Plot

倖福魔咒の 提交于 2019-12-01 06:12:17
问题 I am trying to plot the phasors of the voltage across the resistor, capacitor, and inductor in an series R-L-C circuit. I have done all of the calculations and I can get a decent plot with just the normal ax.plot(theta,r,....) . I would like to make the phasor vectors look like arrows. I have been trying to use ax.arrow(0,0,theta,magnitude) but it looks like a line still. The gist to the code that I have written is here : GIST My image that I create is I tried to follow the example that I