operation

Illegal operation on empty result set

感情迁移 提交于 2019-11-28 02:17:47
I'm trying to build a pay desk in a grocery store and my code actually performs what I intend for it to do, but for one thing. After I ask the user to enter how many of an item they want, the product information is gathered and works fine, but when it's supposed to ask the user to enter product-ID for next product, the line is repeated and I get the following exception in my catch: "Illegal operation on empty result set". Again, all the calculations and everything is fine except for the repeating of that line. Any ideas on what might be the problem? The output that is repeat is like this:

Date operations on xsl 1.0

£可爱£侵袭症+ 提交于 2019-11-27 15:54:48
I need to get 3 days before and after a given date defined in a variable, and store each one of them in a new individual variable in xsl 1.0. i can't use any extensions or third party tools. Looking trough the answers in the forums, i found this: Expanding datetime ranges in XSLT 1.0 for a similar problem, but i dont fully understand if and how it would aply to my code. Mi date variable is in standard dateTime format, like this: <xsl:variable name="Date" select="2014-05-13T00:00:00"/> And i would need to output an html similar to this: <table> <tr> <td> 2014-05-10 <td> </tr> <!---some rows

How do i get the invoked operation name within a WCF Message Inspector

筅森魡賤 提交于 2019-11-27 14:22:06
I'm doing a message inspector in WCF: public class LogMessageInspector : IDispatchMessageInspector, IClientMessageInspector which implements the method: public object AfterReceiveRequest(ref Message request, IClientChannel channel, InstanceContext instanceContext) I can get the name of the invoked service with: instanceContext.GetServiceInstance().GetType().Name But how do I get the name of the invoked operation? Kent Boogaart It's not pretty, but this is what I did to get the operation name: var action = OperationContext.Current.IncomingMessageHeaders.Action; var operationName = action

Equalizer not always supported, even when api >= 9?

百般思念 提交于 2019-11-27 07:45:56
问题 before enabling equalizer capabilities, I check for api level to make sure it's equal or greater than 9. From the reports I'm getting from my users, it seems that some exceptions are thrown anyway : the code eq = new Equalizer(0, mp.getAudioSessionId()) can raise : Caused by: java.lang.UnsupportedOperationException: Effect library not loaded at android.media.audiofx.AudioEffect.<init>(AudioEffect.java:355) at android.media.audiofx.Equalizer.<init>(Equalizer.java:149) and the code eq

Illegal operation on empty result set

时间秒杀一切 提交于 2019-11-26 23:42:12
问题 I'm trying to build a pay desk in a grocery store and my code actually performs what I intend for it to do, but for one thing. After I ask the user to enter how many of an item they want, the product information is gathered and works fine, but when it's supposed to ask the user to enter product-ID for next product, the line is repeated and I get the following exception in my catch: "Illegal operation on empty result set". Again, all the calculations and everything is fine except for the

The operation has timed out at System.Net.HttpWebRequest.GetResponse() while sending large number of requests to a host

感情迁移 提交于 2019-11-26 18:02:00
I am sending a large number of simultaneous requests to a particular web service with different data. To achieve this, I have created a number of threads(around 50 in number). Total number of requests per minute may increase up to 10000. The application in the form of a windows service runs fine for a few minutes and then a operation time out error is encountered. I have tried the usual suspects such as increasing DefaultConnectionLimit , closing the web response object. Since the requests do not take much time on server, I have also set the request Timeout and ReadWriteTimeout to 5 seconds.

Is addition of byte converts to int because of java language rules or because of jvm?

放肆的年华 提交于 2019-11-26 17:46:51
byte a = 1; byte b = 1; byte c = a + b; Throws error: possible loss of precision byte subt = a_s - a_b; ^ required: byte found: int Is this behavior has something to do with jvm or its been defined in java language . EDIT : And if it is defined in java language then does it because of keeping jvm in mind ? Means if java supports byte datatype then why operation on byte results int if java supports byte datatype then why operation on byte results int Because that's how the Java Virtual Machine is designed. There is no instruction set to perform operation on a byte type. Rather the instruction

How do i get the invoked operation name within a WCF Message Inspector

蹲街弑〆低调 提交于 2019-11-26 16:43:23
问题 I'm doing a message inspector in WCF: public class LogMessageInspector : IDispatchMessageInspector, IClientMessageInspector which implements the method: public object AfterReceiveRequest(ref Message request, IClientChannel channel, InstanceContext instanceContext) I can get the name of the invoked service with: instanceContext.GetServiceInstance().GetType().Name But how do I get the name of the invoked operation? 回答1: It's not pretty, but this is what I did to get the operation name: var

Is addition of byte converts to int because of java language rules or because of jvm?

萝らか妹 提交于 2019-11-26 03:58:36
问题 byte a = 1; byte b = 1; byte c = a + b; Throws error: possible loss of precision byte subt = a_s - a_b; ^ required: byte found: int Is this behavior has something to do with jvm or its been defined in java language . EDIT : And if it is defined in java language then does it because of keeping jvm in mind ? Means if java supports byte datatype then why operation on byte results int 回答1: if java supports byte datatype then why operation on byte results int Because that's how the Java Virtual

Why do these two multiplication operations give different results?

*爱你&永不变心* 提交于 2019-11-26 03:19:38
问题 Why do I need to add an \"L\" letter to get the correct long value? And what is the other value? long oneYearWithL = 1000*60*60*24*365L; long oneYearWithoutL = 1000*60*60*24*365; System.out.println(oneYearWithL);//gives correct calculation result : 31536000000 System.out.println(oneYearWithoutL)//gives incorrect calculation result: 1471228928 回答1: long oneYearWithL = 1000*60*60*24*365L; long oneYearWithoutL = 1000*60*60*24*365; Your first value is actually a long (Since 365L is a long , and