nsdatecomponents

I got a NSDate for example 1/6 -12 (Friday) and trying to find out what weekday it is. My week starts at Monday so Friday should be weekday 5. NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; [calendar setFirstWeekday:2]; NSDateComponents *components = [calendar components:NSWeekdayCalendarUnit fromDate:firstOfJulyDate]; NSLog(@"weekday %i",components.weekday); Output: weekday 6 Doesn't matter what i set setFirstWeekday to, output will always be 6. What am i doing wrong? Try doing something like this: NSCalendar *gregorian = [[[NSCalendar alloc]

I'm trying to sethours in NSDateComponents, I wrote the following code NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; NSDateComponents *dateComps = [[NSDateComponents alloc] init]; [dateComps setDay:intDay]; [dateComps setMonth:intMonth]; [dateComps setYear:intYear]; [dateComps setHour:intHoures]; [dateComps setMinute:intMinutes]; NSDate *itemDate; itemDate = [calendar dateFromComponents:dateComps]; NSLog(@"reminder date: %@", itemDate); but when I set the hours as 13, it sets it as 11. I want hours in 24 style. Anyone can help me in this issue?

Using today as an example, how do I determine which date it was, 230 workdays ago? I know how to do it iteratively with a while loop checking date and subtracting 1 if it's a workday, but I'm wondering if there is a better method. Also, let's take a Sunday 1 PM as an example, and subtract 3 work days and 2 hours from that time. First, it doesn't make sense to subtract work-time from weekends. So it would have to move the time to 23:59:59 of Friday, and then subtract those 3 days and 2 hours. If it's a Monday at 1:30 AM, and I'm subtracting 5 days and 3 work-hours from that time, then the

I have created a calendar in my app, using the date object this way: NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; NSDateComponents *weekdayComponents = [gregorian components:(NSDayCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSMinuteCalendarUnit)fromDate:[NSDate date]]; NSInteger day = [weekdayComponents day]; NSInteger month = [weekdayComponents month]; NSInteger year = [weekdayComponents year]; m_dateFormatter.dateFormat = @"dd/MM/yyyy"; [gregorian setTimeZone:[NSTimeZone timeZoneWithAbbreviation:@"UTC"]]; NSDateComponents

I am developing a app which uses the date, month, year. I want the current month dates,because current month can have 28,29,30,31 days. I have tried to get current year months. but i don't know the code for above. here is my code. NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; NSDate *today = [NSDate date]; NSCalendar *currentCalendar = [NSCalendar currentCalendar]; NSDateComponents *yearComponents = [currentCalendar components:NSYearCalendarUnit fromDate:today]; int currentYear = [yearComponents year]; for(int months = 0; months < 12; months++) { NSString *monthName =

I'd like to get the current hour and minute as integers. So if right now is 3:16am, I'd like to get the two integers: 3 and 16. But it looks like [NSDate date] will give the number of seconds since 1970, or it can give a string of the current time representation, but there is no easy way to get them as integers? I see a post in Getting current time , but it involved NSDateComponents and NSCalendar ? That's way too complicated... all that was need is something like NSDate *date = [NSDate date]; int hour = [date getHour]; // which is not possible Is there a simpler way than using 3 classes