negative

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a travel bot with following intents:- BookAFlight (trained with 20 utterances) GetTicketCopy (trained with 20 utterances) CancelTicket (trained with 20 utterances) None (default) (currently not trained) MS documentation suggests that I train None for atleast 1-2 utterances for every 10 utterances added to other intents. Which means I would need say 6-12 utterances to train None. My query is what kind of utterances should be used to train None? Everything under the sun apart from what is relevant to my bot ( for e.g. I want to order a

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have run into a situation in my code where a function returns a double, and it is possible for this double to be a zero, a negative zero, or another value entirely. I need to distinguish between zero and negative zero, but the default double comparison does not. Due to the format of doubles, C++ does not allow for comparison of doubles using bitwise operators, so I am unsure how to procede. How can I distinguish between the two? 回答1: Call std::signbit() to determine the state of the sign bit. 回答2: Due to the format of doubles, C++ does not

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: Doesn't bitwise-ANDing with 0xff essentially mean getting the same value back, for that matter, in this code? byte [] packet = reader . readPacket (); short sh ; sh = packet [ 1 ]; sh &= 0xFF ; System . out . print ( sh + " " ); Weirdly, I get a -1 if that ANDing is not included but a 255 when included Could someone explain the reason? As I see it 0xff is just 1111 1111. Isn't it? 回答1: Yes, 0xff is just 1111 1111 . But this is attempting to display the unsigned byte value, even though in Java byte s are signed. The value 0xff is -1

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: In View.java, setId - "Sets the identifier for this view. The identifier does not have to be unique in this view's hierarchy. The identifier should be a positive number." & findViewById - "Look for a child view with the given id. If this view has the given id, Why I could not use a negative number as the id of the view? I commented out the public final View findViewById ( int id ) { // The original android check at here // if (id < 0) { // is commented out to test if system could run when Ids are negative numbers if ( id == NO_ID )

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: In an Android manifest, how can I use a negative match in the android:pathPattern ? I'd like to use a pathPattern that matches on all URLs except for a specific hostname, if it's possible. 回答1: It doesn't look like that's possible--in fact, it seems to be designed not to work that way. I suspect <intent-filter> is the wrong tool for whatever you're trying to do. Even if you could use android:pathPattern to specify the hostname (isn't that what android:host is for?), it's more of a glob than a regex; according to the docs , it's deliberately

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: TensorFlow: How to handle void labeled data in image segmentation? 2 answers In Caffe, there is an option with its SoftmaxWithLoss function to ignore all negative labels (-1) in computing probabilities, so that only 0 or positive label probabilities add up to 1. Is there a similar feature with Tensorflow softmax loss? 回答1: Just came up with a work-around --- I created a one-hot tensor on the label indices using tf.one_hot (with the depth set at the # of labels). tf.one_hot automatically zeros out all

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I found this function at php.net. It seems to work on positive numbers, but fails on negative ones: function gmp_shiftr ( $x , $n ) { // shift right return ( gmp_div ( $x , gmp_pow ( 2 , $n ))); } echo - 1 >> 8 ; //returns -1, presumably correctly echo "<br />" ; echo gmp_strval ( gmp_shiftr (- 1 , 8 )); //returns 0, presumably incorrectly How could I fix up the function to work with negatives? Two ideas I have: Maybe I could do something along the lines of if ( whatever ) { $a >> $b } else { gmp_shiftr ( $a , $b ) }? Or, maybe I

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: There are many questions already answered for replacing everything positive numbers. But, I couldn't find any answer which preserves both positive and negative numbers. I want to replace everything that isn't number(positive or negative). The output should be the following eg. 0 | success. id - 1234| -> 0 1234 and -10 | failure. id - 2345| -> -10 2345 Apparently this answers for the positive part. 回答1: You can use this regex to match positive/negative integers: [+-]?\b\d+\b RegEx Demo to match positive/negative numbers including decimals: [+

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: How do you take the square root of a negative number in C++? I know it should return a real and a complex part, I get a NaN? How do I take the real part? 回答1: #include <complex> int main() { std::complex<double> two_i = std::sqrt(std::complex<double>(-4)); } or just std::complex<double> sqrt_minus_x(0, std::sqrt(std::abs(x))); 回答2: sqrt(-x) where x is a positive number is simply 0 + sqrt(x)*i . The real part is just 0. In general, the real part is x > 0 ? sqrt(x) : 0 and the imaginary part is x < 0 ? sqrt(x) : 0 . 回答3: If what you call a

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm struggling with an error whilst trying to compile GIT. I've searched Google and the GIT source issues/bugs for similar issues but i've not found anything to help me. Originally I received the following error root@teemo:/usr/src/git# make prefix=/usr install install-doc install-html install-info; CC http-push.o In file included from cache.h:39:0, from http-push.c:1: /usr/include/zlib.h:34:19: fatal error: zconf.h: No such file or directory #include "zconf.h" ^ compilation terminated. make: *** [http-push.o] Error 1 I created a symbolic