negative

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I want to use a css3 transition to smooth a compass movement using phonegap. i calculate the desired rotation as angle from 0 to 359. The problem is, when it should go from for example 359 to 0 it doesn't turn 1 degree clockwise, but instead it turns 359 degree counter clockwise. Is there a way to tell css to always take the shortest way for a rotation? 回答1: The transform is doing exactly what you tell it to. It starts at 359deg and goes to 1deg. You are looking to 'rollover' 360deg back to 1deg, which is really 361deg. The way the transform

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Why does numeric_limits::min return a negative value for int, but positive values for e.g. float and double? #include #include using namespace std; int main() { cout ::min() ::min() ::min() Output: int: -2147483648 float: 1.17549e-38 double: 2.22507e-308 From cppreference: Returns the minimum finite value representable by the numeric type T. For floating-point types with denormalization, min returns the minimum positive normalized value. Note that this behavior may be unexpected , especially when compared to the behavior of min for integral

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: This question already has an answer here: Accessing an array out of bounds gives no error, why? 17 answers I alloced an int array of 3 elements, and thought of this code below: int a[3]; for(int i = -2; i < 3; ++i){ a[i] = i; cout<<a[i]<<" "; } Here's its output: -2 -1 0 1 2 It seems like array a has 5 alloced space, and a is at the middle of those space. Any ideas? 回答1: To explain how negative indexes work, you first have to learn (or remember) that for any array or pointer a and index i , the expression a[i] is equal to *(a + i) . That

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: As far as I know when you use a left shift bitwise operator in C it's guaranteed that the vacant bits will be filled with 0s. However, I've read that the right shift is implementation-dependent, meaning in some machines the vacant bits will be filled with 0s, in others they will be filled with 1s. I am using the right shift in a program, and indeed my machine is filling the vacant bits with 1s. Problem is I would need it to fill with 0s instead. Is there a way to force 0s to be used on right shifts? One solution would be, after the right

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm using a logistic regression model in sklearn and I am interested in retrieving the log likelihood for such a model, so to perform an ordinary likelihood ratio test as suggested here . The model is using the log loss as scoring rule. In the documentation, the log loss is defined "as the negative log-likelihood of the true labels given a probabilistic classifier’s predictions" . However, the value is always positive, whereas the log likelihood should be negative. As an example: from sklearn.linear_model import LogisticRegression from

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm trying to make a function in Python that takes a list of integers as input and returns a greater list containing all positive and negative possibilities of those numbers. Pretend '+' is a positive number and '-' is a negative number The output should match up with: foo([-4]) >>> [ [4], [-4] ] foo([+, +]) >>> [ [+,+], [+,-], [-,+], [-,-] ] foo([-, +]) >>> [ [+,+], [+,-], [-,+], [-,-] ] foo([-1, 3]) >>> [ [1,3], [1,-3], [-1,3], [-1,-3] ] foo( [+,-,+] ) >>> [ [-,-,-],[+,-,-],[-,+,-],[-,-,+],[+,+,-],[+,-,+],[-,+,+],[+,+,+] ] 回答1: For just

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm trying to get the nth root of a number using JavaScript, but I don't see a way to do it using the built in Math object. Am I overlooking something? If not... Is there a math library I can use that has this functionality? If not... What's the best algorithm to do this myself? 回答1: Can you use something like this? Math.pow(n, 1/root); eg. Math.pow(25, 1/2) == 5 回答2: The n th root of x is the same as x to the power of 1/n . You can simply use Math.pow : var original = 1000; var fourthRoot = Math.pow(original, 1/4); original == Math.pow

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: In a TC++ compiler, the binary representation of 5 is (00000000000000101) . I know that negative numbers are stored as 2's complement, thus -5 in binary is (111111111111011) . The most significant bit (sign bit) is 1 which tells that it is a negative number. So how does the compiler know that it is -5 ? If we interpret the binary value given above (111111111111011) as an unsigned number, it will turn out completely different? Also, why is the 1's compliment of 5 -6 (1111111111111010) ? 回答1: The compiler doesn't know . If you cast -5 to

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: All I want to do is find the sentiment (positive/negative/neutral) of any given string. On researching I came across Stanford NLP. But sadly its in Java. Any ideas on how can I make it work for python? 回答1: Use py-corenlp Install Stanford CoreNLP The latest version at this time (2018-02-21) is 3.9.0: wget http://nlp.stanford.edu/software/stanford-corenlp-full-2018-01-31.zip unzip stanford-corenlp-full-2018-01-31.zip Start the server cd stanford-corenlp-full-2018-01-31 java -mx5g -cp "*" edu.stanford.nlp.pipeline.StanfordCoreNLPServer

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to write a regular expression that will find any word that is followed by a space so long as that word is not AND , OR , NOT . I've tried a negative lookahead after searching for similar problems, this is my current regex: (?!AND|OR|NOT).*?\\s If I try this with "AND " I get a match on "ND". If I try with "OR " I get "R" and if I try with "NOT " I get "OT". Can anyone help? 回答1: Try with this pattern: \\b(?!(?:AND|OR|NOT)\\b)[a-zA-Z]+\\s I have added some word boundaries (\b) and used the character class [a-zA-Z] (you can replace