n-queens

Puzzled about backtracking in Eight Queen

时光怂恿深爱的人放手 提交于 2019-12-12 08:14:06
问题 I have a difficult time understanding recursion and backtracking, albeit I have done some simple exercises (e.g. Fibonacci). So allow me to present my "brain flow" here: I read the textbook and know that you can use backtracking to remove the previous queen if its current position eliminates the possibility of placing the next queen in the next column. So this seems to be easy and all I need to do is to remove it and let the program decide the next possible place. After a while I found that

N * N queen algorithm getting the coordinates

心已入冬 提交于 2019-12-11 07:26:52
问题 I'm trying to implement the N*N queen algorithm with a little twist to it. In this version the queen can also move like a knight... Everything is working fine, but I'm trying to get the coordinates of all the possible solutions. The problem is that if I put it inside col == n it just prints the last one. Any ideas of how to solve this? static void placement(int col, int queens[], int n){ //int solution =0; for (int row = 1; row <= n; row++) { queens[col] = row; if((check_Queen(row,col,queens)

Algorithm of N queens

白昼怎懂夜的黑 提交于 2019-12-07 11:15:50
问题 Algorithm NQueens ( k, n) //Prints all Solution to the n-queens problem { for i := 1 to n do { if Place (k, i) then { x[k] := i; if ( k = n) then write ( x [1 : n] else NQueens ( k+1, n); } } } Algorithm Place (k, i) { for j := 1 to k-1 do if (( x[ j ] = // in the same column or (Abs( x [ j ] - i) =Abs ( j – k ))) // or in the same diagonal then return false; return true; } The above code is for solving N Queens problem using backtracking.I think that it can place the first 2 queens of two

How to Solve N-Queens in Scheme?

倾然丶 夕夏残阳落幕 提交于 2019-12-07 10:36:35
问题 I'm stuck on the extended exercise 28.2 of How to Design Programs. I used a vector of true or false values to represent the board instead of using a list. This is what I've got which doesn't work: #lang Scheme (define-struct posn (i j)) ;takes in a position in i, j form and a board and ; returns a natural number that represents the position in index form ;example for board xxx ; xxx ; xxx ;(0, 1) -> 1 ;(2, 1) -> 7 (define (board-ref a-posn a-board) (+ (* (sqrt (vector-length a-board)) (posn-i

fast heuristic algorithm for n queens (n > 1000)

和自甴很熟 提交于 2019-12-06 07:01:51
问题 I write two program : put together n queens in chess board without any threatening by backtracking algorithm. but that is very heavy for big n . at last you can run that for 100 queens. put together n queens in chess board without any threatening by Hill climbing algorithm. this algorithm better than past solution but it take 2 min for 300 queens and this time increase exponentially! But I didn't have any idea for doing that fast! I want algorithm for doing that faster . I want faster manner

Algorithm of N queens

跟風遠走 提交于 2019-12-05 15:12:12
Algorithm NQueens ( k, n) //Prints all Solution to the n-queens problem { for i := 1 to n do { if Place (k, i) then { x[k] := i; if ( k = n) then write ( x [1 : n] else NQueens ( k+1, n); } } } Algorithm Place (k, i) { for j := 1 to k-1 do if (( x[ j ] = // in the same column or (Abs( x [ j ] - i) =Abs ( j – k ))) // or in the same diagonal then return false; return true; } The above code is for solving N Queens problem using backtracking.I think that it can place the first 2 queens of two rows in respective columns and then when it comes to 3rd row queen it can't be placed as no queen needs

How to Solve N-Queens in Scheme?

吃可爱长大的小学妹 提交于 2019-12-05 13:23:05
I'm stuck on the extended exercise 28.2 of How to Design Programs . I used a vector of true or false values to represent the board instead of using a list. This is what I've got which doesn't work: #lang Scheme (define-struct posn (i j)) ;takes in a position in i, j form and a board and ; returns a natural number that represents the position in index form ;example for board xxx ; xxx ; xxx ;(0, 1) -> 1 ;(2, 1) -> 7 (define (board-ref a-posn a-board) (+ (* (sqrt (vector-length a-board)) (posn-i a-posn)) (posn-j a-posn))) ;reverse of the above function ;1 -> (0, 1) ;7 -> (2, 1) (define (get-posn

Solving the n-queen puzzle

和自甴很熟 提交于 2019-12-04 11:18:43
I have just solved the nqueen problem in python. The solution outputs the total number of solutions for placing n queens on an nXn chessboard but trying it with n=15 takes more than an hour to get an answer. Can anyone take a look at the code and give me tips on speeding up this program...... A novice python programmer. #!/usr/bin/env python2.7 ############################################################################## # a script to solve the n queen problem in which n queens are to be placed on # an nxn chess board in a way that none of the n queens is in check by any other #queen using

8-queen problem using Dynamic programming

怎甘沉沦 提交于 2019-12-02 23:53:52
I am quite confused with idea of implementing 8-queen problem using dynamic programming. It seems it is not possible at one end as for DP " if the problem was broken up into a series of subproblems and the optimal solution for each subproblem was found, then the resulting solution would be realized through the solution to these subproblems. A problem that does not have this structure cannot be solved with dynamic programming" ( Reference ). By taking this in account, the optimal solution for 7x7 board might not optimal as well (even incorrect) for 8x8. So, the result of problem might not

Hints to understand splendid program to solve Queens

人盡茶涼 提交于 2019-11-30 18:29:26
In Art of Prolog of Sterling & Shapiro, exercise Section 14.1 (v): queens(N,Qs) :- length(Qs,N), place_queens(N,Qs,_,_). place_queens(0,_Qs,_Ups,_Downs). place_queens(I,Qs,Ups,[_|Downs]) :- I > 0, I1 is I-1, place_queens(I1,Qs,[_|Ups] ,Downs), place_queen(I,Qs,Ups,Downs). place_queen(Q,[Q|_],[Q|_],[Q|_]). place_queen(Q,[_|Qs],[_|Ups],[_|Downs] ):- place_queen(Q,Qs,Ups,Downs). It is a splendid program, in 11 lines, which quickly solves the problem of positioning queens on a chessboard. It's magical: there is only a counter, recursion, and lists that get longer and shorter. I, even with the help