lru

How does Lru_cache (from functools) Work?

旧时模样 提交于 2019-11-30 06:45:02
Especially when using recursive code there are massive improvements with lru_cache . I do understand that a cache is a space that stores data that has to be served fast and saves the computer from recomputing. How does the Python lru_cache from functools work internally? I'm Looking for a specific answer, does it use dictionaries like the rest of Python? Does it only store the return value? I know that Python is heavily built on top of dictionaries, however, I couldn't find a specific answer to this question. Hopefully, someone can simplify this answer for all the users on StackOverflow .

Least Recently Used cache using C++

人盡茶涼 提交于 2019-11-30 06:38:00
问题 I am trying to implement LRU Cache using C++ . I would like to know what is the best design for implementing them. I know LRU should provide find(), add an element and remove an element. The remove should remove the LRU element. what is the best ADTs to implement this For ex: If I use a map with element as value and time counter as key I can search in O(logn) time, Inserting is O(n), deleting is O(logn). 回答1: One major issue with LRU caches is that there is little "const" operations, most

Use LinkedHashMap to implement LRU cache

岁酱吖の 提交于 2019-11-29 20:29:12
I was trying to implement a LRU cache using LinkedHashMap. In the documentation of LinkedHashMap ( http://docs.oracle.com/javase/7/docs/api/java/util/LinkedHashMap.html ), it says: Note that insertion order is not affected if a key is re-inserted into the map. But when I do the following puts public class LRUCache<K, V> extends LinkedHashMap<K, V> { private int size; public static void main(String[] args) { LRUCache<Integer, Integer> cache = LRUCache.newInstance(2); cache.put(1, 1); cache.put(2, 2); cache.put(1, 1); cache.put(3, 3); System.out.println(cache); } private LRUCache(int size) {

How to limit the size of a dictionary?

笑着哭i 提交于 2019-11-29 19:42:41
I'd like to work with a dict in python, but limit the number of key/value pairs to X. In other words, if the dict is currently storing X key/value pairs and I perform an insertion, I would like one of the existing pairs to be dropped. It would be nice if it was the least recently inserted/accesses key but that's not completely necessary. If this exists in the standard library please save me some time and point it out! Python 2.7 and 3.1 have OrderedDict and there are pure-Python implementations for earlier Pythons. from collections import OrderedDict class LimitedSizeDict(OrderedDict): def _

How does the lazy expiration mechanism in memcached operate?

蹲街弑〆低调 提交于 2019-11-29 08:05:54
(First of all, my English is not very good, please) As we know, memcached provides lazy expiration, and "replaces" LRU data in its slabs, however I'm not very clear how it does this. For example, if a slab is full, but some data in this slab are expired, what will happen when data are added to the slab? Does memcached find some expired data and replace them with the added data, or does it replace the LRU data, or does it do something else? As far as I know, the lazy expiration is such that memcached is not actively removing expired data from each slab, but instead only removing expired entries

Least Recently Used cache using C++

人走茶凉 提交于 2019-11-28 19:45:16
I am trying to implement LRU Cache using C++ . I would like to know what is the best design for implementing them. I know LRU should provide find(), add an element and remove an element. The remove should remove the LRU element. what is the best ADTs to implement this For ex: If I use a map with element as value and time counter as key I can search in O(logn) time, Inserting is O(n), deleting is O(logn). One major issue with LRU caches is that there is little "const" operations, most will change the underlying representation (if only because they bump the element accessed). This is of course

Python functools lru_cache with class methods: release object

耗尽温柔 提交于 2019-11-28 18:42:50
问题 How can I use functools' lru_cache inside classes without leaking memory? In the following minimal example the foo instance won't be released although going out of scope and having no referrer (other than the lru_cache). from functools import lru_cache class BigClass: pass class Foo: def __init__(self): self.big = BigClass() @lru_cache(maxsize=16) def cached_method(self, x): return x + 5 def fun(): foo = Foo() print(foo.cached_method(10)) print(foo.cached_method(10)) # use cache return

Use LinkedHashMap to implement LRU cache

假装没事ソ 提交于 2019-11-28 16:31:19
问题 I was trying to implement a LRU cache using LinkedHashMap. In the documentation of LinkedHashMap (http://docs.oracle.com/javase/7/docs/api/java/util/LinkedHashMap.html), it says: Note that insertion order is not affected if a key is re-inserted into the map. But when I do the following puts public class LRUCache<K, V> extends LinkedHashMap<K, V> { private int size; public static void main(String[] args) { LRUCache<Integer, Integer> cache = LRUCache.newInstance(2); cache.put(1, 1); cache.put(2

What is the difference between LRU and LFU

对着背影说爱祢 提交于 2019-11-28 03:39:41
What is the difference between LRU and LFU cache implementations? I know that LRU can be implemented using LinkedHashMap . But how to implement LFU cache? Zorayr Let's consider a constant stream of cache requests with a cache capacity of 3, see below: A, B, C, A, A, A, A, A, A, A, A, A, A, A, B, C, D If we just consider a Least Recently Used (LRU) cache with a HashMap + doubly linked list implementation with O(1) eviction time and O(1) load time, we would have the following elements cached while processing the caching requests as mentioned above. [A] [A, B] [A, B, C] [B, C, A] <- a stream of

How does the lazy expiration mechanism in memcached operate?

拥有回忆 提交于 2019-11-28 01:42:55
问题 (First of all, my English is not very good, please) As we know, memcached provides lazy expiration, and "replaces" LRU data in its slabs, however I'm not very clear how it does this. For example, if a slab is full, but some data in this slab are expired, what will happen when data are added to the slab? Does memcached find some expired data and replace them with the added data, or does it replace the LRU data, or does it do something else? As far as I know, the lazy expiration is such that