lead

Sorry for the long post, but I have provided copy & paste sample data and a possible solution approach below. The relevant part of the question is in the upper part of the post (above the horizontal rule). I have the following table Dt customer_id buy_time money_spent ------------------------------------------------- 2000-01-04 100 11:00:00.00 2 2000-01-05 100 16:00:00.00 1 2000-01-10 100 13:00:00.00 4 2000-01-10 100 14:00:00.00 3 2000-01-04 200 09:00:00.00 10 2000-01-06 200 10:00:00.00 11 2000-01-06 200 11:00:00.00 5 2000-01-10 200 08:00:00.00 20 and want a query to get this result set Dt Dt

#include <iostream> #include <stdio.h> #include <string.h> #include <algorithm> #include <vector> #include <map> #include <queue> #define int long long using namespace std ; int read() { int x = 0 ;bool f = 1 ; char s = getchar() ; while(s > '9' || s < '0') {if(s == '-') f = -1 ; s = getchar() ;} while(s <='9' && s >='0') {x = x * 10 + (s-'0'); s = getchar() ;} return x*f ; } signed num[20] ; int f[20][201][201][2] ; int l , r , MOD ; int dfs(int pos ,int sum ,int ha, int lead ,int limit) { if(!pos) { if(!ha&&sum==MOD) return 1 ; else return 0 ; } if(!limit&&!lead&&f[pos][sum][ha][lead] != -1)

和某道题出奇的相似 #include <iostream> #include <stdio.h> #include <string.h> #include <algorithm> #include <vector> #include <map> #include <queue> #define int long long using namespace std ; int read() { int x = 0 , f = 1 ; char s = getchar() ; while(s > '9' || s < '0') {if(s == '-') f = -1 ; s = getchar() ;} while(s <='9' && s >='0') {x = x * 10 + (s-'0'); s = getchar() ;} return x*f ; } int f[20][20][2][2][11] , num[20] ; int dfs(int pos ,int sum ,bool lead,bool limit ,int d) { if(!pos) return sum ; if(!limit&&!lead&&f[pos][sum][lead][limit][d] != -1) return f[pos][sum][lead][limit][d] ; int up =

i have a table like this: Number Price Type Date Time ------ ----- ---- ---------- --------- 23456 0,665 SV 2014/02/02 08:00:02 23457 1,3 EC 2014/02/02 07:50:45 23460 0,668 SV 2014/02/02 07:36:34 For each EC I need previous/next SV price. In this case, the query is simple. Select Lag(price, 1, price) over (order by date desc, time desc), Lead(price, 1, price) over (order by date desc, time desc) from ITEMS But, there are some special cases where two or more rows are EC type: Number Price Type Date Time ------ ----- ---- ---------- --------- 23456 0,665 SV 2014/02/02 08:00:02 23457 1,3 EC 2014

I have been working ot see the equivalent function for Oracle lead and lag function. The oracle lead would look like LEAD(col1.date,1,ADD_MONTHS(col1.DATE,12)) OVER(Partition By tab.a,tab.b,tab.c Order By tab.a)-1 END_DATE LAG(col1.DATE + 7,1,col1.DATE-1) OVER(partition by tab.a,tab.b Order By tab.b) LAG_DATE Any better idea I believe you can take the following SQL as a basis and modify it to meet your needs: SELECT CALENDAR_DATE , MAX(CALENDAR_DATE) OVER(PARTITION BY 1 ORDER BY CALENDAR_DATE ROWS BETWEEN 1 PRECEDING AND 1 PRECEDING) AS Lag_ --Yesterday , MIN(CALENDAR_DATE) OVER(PARTITION BY 1