问题
I have been working ot see the equivalent function for Oracle lead and lag function.
The oracle lead would look like
LEAD(col1.date,1,ADD_MONTHS(col1.DATE,12))
OVER(Partition By tab.a,tab.b,tab.c Order By tab.a)-1 END_DATE
LAG(col1.DATE + 7,1,col1.DATE-1)
OVER(partition by tab.a,tab.b Order By tab.b) LAG_DATE
Any better idea
回答1:
I believe you can take the following SQL as a basis and modify it to meet your needs:
SELECT CALENDAR_DATE
, MAX(CALENDAR_DATE)
OVER(PARTITION BY 1 ORDER BY CALENDAR_DATE
ROWS BETWEEN 1 PRECEDING AND 1 PRECEDING) AS Lag_ --Yesterday
, MIN(CALENDAR_DATE)
OVER(PARTITION BY 1 ORDER BY CALENDAR_DATE
ROWS BETWEEN 1 FOLLOWING AND 1 FOLLOWING) AS Lead_ --Tomorrow
FROM SysCalendar.CALENDAR
WHERE year_of_calendar = 2011
AND month_of_year = 11
NULL is returned when there is no record before or after and can be addressed with a COALESCE as necessary.
EDIT In Teradata 16.00 LAG/LEAD functions were introduced.
来源:https://stackoverflow.com/questions/8124756/teradata-equivalent-for-lead-and-lag-function-of-oracle