junction

I am trying to get the target of a junction in my program, but the only way I managed do it is: Requesting Backup privileges p-invoke CreateFile with special parameters to get a handle to the file/dir. DeviceIoControl call to the get the target. The 1st step will not work with normal user accounts, because they have no Backup privileges, and I don't want to get the UAC User Consent window every time I do this. I think this is doable somehow, because a normal "dir /A:L" command resolves the target of the links. flq I think that this answer in stackoverflow would help you? How do I

Is it possible to use junction to match any of the values in a junction? I want to match any of the values in an array. What is the proper way to do it? lisprog$ perl6 To exit type 'exit' or '^D' > my @a=<a b c> [a b c] > any(@a) any(a, b, c) > my $x=any(@a) any(a, b, c) > my $y = "a 1" a 1 > say $y ~~ m/ $x / False > say $y ~~ m/ "$x" / False > my $x = any(@a).Str any("a", "b", "c") > say $y ~~ m/ $x / False > say $y ~~ m/ || $x / False > say $y ~~ m/ || @a / ｢a｣ > Thanks !! Junctions are not meant to be interpolated into regexes. They're meant to be used in normal Perl 6 expressions,

　　三极管，全称应为半导体三极管，也称双极型晶体管、晶体三极管，是一种控制电流的半导体器件。其作用是把微弱信号放大成幅度值较大的电信号，也用作无触点开关。 　　三极管是半导体基本元器件之一，具有电流放大作用，是电子电路的核心元件。三极管是在一块半导体基片上制作两个相距很近的PN结，两个PN结把整块半导体分成三部分，中间部分是基区，两侧部分是发射区和集电区，排列方式有PNP和NPN两种。 　　三极管 [1] （也称晶体管）在中文含义里面只是对三个引脚的放大器件的统称，我们常说的三极管，可能是 如图所示的几种器件。 　　可以看到，虽然都叫三极管，其实在英文里面的说法是千差万别的，三极管这个词汇其实也是中文特有的一个象形意义上的的词汇。 　　电子三极管 Triode 这个是英汉字典里面“三极管”这个词汇的唯一英文翻译，这是和电子三极管最早出现有关系的，所以先入为主，也是真正意义上的三极管这个词最初所指的物品。其余的那些被中文里叫做三极管的东西，实际翻译的时候是绝对不可以翻译成Triode的，否则就麻烦大咯，严谨地说，在英文里面根本就没有三个脚的管子这样一个词汇！ 　　电子三极管 Triode （俗称电子管的一种） 　　双极型晶体管 BJT （Bipolar Junction Transistor）J型场效应管 Junction gate FET（Field Effect

I want to make a quick check if in a complete path a Junction point is used. I already have a function to test a folder like IsJunction() but maybe there is an other solution to not call IsJunction() on every subfolder. So I'm looking for a function like HasJunctionsInPath(string path) without testing each folder of the path. Is there something which can do this? Edit: Or better... Is it possible to resolve all junctions in a path to get the real location of a file or folder? This would be even better solve my problem and I still can compare the result with the original path to implement a

I've been trying to figure out a way to get some sort of ability to be able to return the true abspath of a symbolic link in Windows, under Python 2.7. (I cannot upgrade to 3.x, as most DCCs such as Maya/3ds max do not use that version of Python) I've looked at the sid0 ntfs utils (whose islink() function works, but readlink() function always returns an empty unicode string for me for some reason), and the juntalis ntfs libs (which unfortunately, I couldn't get to work), along with a helpful script someone posted: import os, ctypes, struct from ctypes import windll, wintypes FSCTL_GET_REPARSE

In PowerShell, I need resolve the target path of a junction (symlink). for example, say I have a junction c:\someJunction whose target is c:\temp\target I tried variations of $junc = Get-Item c:\someJunction , but was only able to get c:\someJunction How do I find the target path of the junction, in this example c:\temp\target , of a given junction? Josh You can get the path by doing the following: Get-ChildItem -Path C:\someJunction Edit for finding the path and not the contents of the folder Add-Type -MemberDefinition @" private const int FILE_SHARE_READ = 1; private const int FILE_SHARE