julian-date

问题 This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. Closed 6 years ago . Lot and lot of thanks in advance ! The following code snippet is a function that gives me Year, Month and Day for a given Julian Day.. Can you please

问题 how can I select Julian day of year in Oracle database? I tried: select to_char(sysdate, 'J') from dual; Which gives me the number of days since January 1, 4712 BC. But I would need the number of days since 1.1. of current year. 回答1: If you check the TO_CHAR (datetime) documentation you get a link to "Format Models" with a comprehensive list of available formats. I guess you want this: DDD Day of year (1-366) 回答2: SELECT TO_CHAR(SYSDATE, 'DDD') from DUAL; 回答3: One way would be to use: select

问题 how can I select Julian day of year in Oracle database? I tried: select to_char(sysdate, 'J') from dual; Which gives me the number of days since January 1, 4712 BC. But I would need the number of days since 1.1. of current year. 回答1: If you check the TO_CHAR (datetime) documentation you get a link to "Format Models" with a comprehensive list of available formats. I guess you want this: DDD Day of year (1-366) 回答2: SELECT TO_CHAR(SYSDATE, 'DDD') from DUAL; 回答3: One way would be to use: select

问题 I'm trying to convert JDE dates, and have amassed a large quantity of information and figured I'd try to do an SQL conversion function to simplify some tasks. Here's the function I came up with, which I simply call "ToGregorian" CREATE FUNCTION [dbo].[ToGregorian](@julian varchar(6)) RETURNS datetime AS BEGIN DECLARE @datetime datetime SET @datetime = CAST(19+CAST(SUBSTRING(@julian, 1, 1) as int) as varchar(4))+SUBSTRING(@julian, 2,2)+'-01-01' SET @datetime = DATEADD(day, CAST(SUBSTRING(

问题 I'm writing an application in Lua that calculates the sunset/sunrise, and to do this I had to convert the Gregorian date in to Julian days initially and do all the complex maths and such from there. I've completed the hard maths, but now I need to convert the Julian date (2456495.6833865 as an example) back to a Gregorian one, complete with the time. The only code I've found that can do this only has the day, year and month, but no mention of the time (which I believe is expressed as a

问题 I have searched far and wide, but I can't seem find a way to convert julian to yyyy-mm-dd . Here is the format of my julian: The Julian format consists of the year, the first two digits, and the day within the year, the last three digits. For example, 95076 is March 17, 1995 . The 95 indicates the year and the 076 indicates it is the 76th day of the year. 15260 I have tried this but it isn't working: dateadd(d,(convert(int,LAST_CHANGED_DATE) % 1000)-1, convert(date,(convert(varchar,convert

问题 How do I convert a 7-digit julian date into a format like MM/dd/yyy? 回答1: Found a useful site: http://www.rgagnon.com/javadetails/java-0506.html This should do the trick: public static int[] fromJulian(double injulian) { int jalpha,ja,jb,jc,jd,je,year,month,day; double julian = julian + HALFSECOND / 86400.0; ja = (int) julian; if (ja>= JGREG) { jalpha = (int) (((ja - 1867216) - 0.25) / 36524.25); ja = ja + 1 + jalpha - jalpha / 4; } jb = ja + 1524; jc = (int) (6680.0 + ((jb - 2439870) - 122.1

问题 I am writing code to convert from a Gregorian date to a JDE (J.D.Edwards) Julian date. Note: a JDE Julian date is different from the normal usage of the term Julian date. As far as I can work out from Googling, the definition of a JDE Julian date is: 1000*(year-1900) + dayofyear where year is the 4-digit year (e.g. 2009), and dayofyear is 1 for 1st January, and counts up all year to either 365 or 366 for 31st December (depending whether this is a leap year). My question is this: are years

问题 I have seen the "solution" at http://www.rgagnon.com/javadetails/java-0506.html, but it doesn't work correctly. E.g. yesterday (June 8) should have been 159, but it said it was 245. So, does someone have a solution in Java for getting the current date's three digit Julian day (not Julian date - I need the day this year)? Thanks! Mark 回答1: If all you want is the day-of-year, why don'you just use GregorianCalendars DAY_OF_YEAR field? import java.util.GregorianCalendar; public class CalTest {

问题 I have a year value and a day of year and would like to convert to a date (day/month/year). Thanks in advance. :) 回答1: datetime.datetime(year, 1, 1) + datetime.timedelta(days - 1) 回答2: >>> import datetime >>> datetime.datetime.strptime('2010 120', '%Y %j') datetime.datetime(2010, 4, 30, 0, 0) >>> _.strftime('%d/%m/%Y') '30/04/2010' 回答3: The toordinal() and fromordinal() functions of the date class could be used: from datetime import date date.fromordinal(date(year, 1, 1).toordinal() + days -