Convert a Julian Date to Regular Calendar Date

问题

How do I convert a 7-digit julian date into a format like MM/dd/yyy?

回答1:

Found a useful site: http://www.rgagnon.com/javadetails/java-0506.html

This should do the trick:

 public static int[] fromJulian(double injulian) {

      int jalpha,ja,jb,jc,jd,je,year,month,day;
      double julian = julian + HALFSECOND / 86400.0;
      ja = (int) julian;
      if (ja>= JGREG) {    

       jalpha = (int) (((ja - 1867216) - 0.25) / 36524.25);
       ja = ja + 1 + jalpha - jalpha / 4;
       }
     jb = ja + 1524;
   jc = (int) (6680.0 + ((jb - 2439870) - 122.1) / 365.25);
   jd = 365 * jc + jc / 4;
   je = (int) ((jb - jd) / 30.6001);
   day = jb - jd - (int) (30.6001 * je);
   month = je - 1;
   if (month > 12) month = month - 12;
   year = jc - 4715;
   if (month > 2) year--;
   if (year <= 0) year--;

   return new int[] {year, month, day};
  }

回答2:

simple way is here and this will return approx 100% accurate information.

String getDobInfo(double doubleString){
        SweDate sweDate = new SweDate(doubleString);
        int year = sweDate.getYear();
        int month = sweDate.getMonth();
        int day = sweDate.getDay();
        // getting hour,minute and sec from julian date
        int hour = (int) Math.floor(sweDate.getHour());
        int min = (int) Math
                .round((sweDate.getHour() - Math.floor(hour)) * 60.0);
        int sec = (int) (((sweDate.getHour() - Math.floor(hour)) * 60.0 - Math
                .floor(min)) * 60.0);
        return "DOB:(DD:MM:YY) "+day+":"+month+":"+year+" TOB:(HH:MM:SS) "+hour+":"+min+":"+sec;
    }

download the Swiss Ephemeris library and enjoy coding!!!

回答3:

Starting with Java 8, this becomes a one-liner to get the LocalDate:

LocalDate.MIN.with(JulianFields.JULIAN_DAY, julianDay)
.format(DateTimeFormatter.ofPattern("MM/dd/yyyy"));

Where julianDay is your 7-digit number.

回答4:

Do you really mean a Julian date, like astronomers use? Ordinal dates, which are specified as a year (four digits) and the day within that year (3 digits), are sometimes incorrectly called Julian dates.

static String formatOrdinal(int year, int day) {
  Calendar cal = Calendar.getInstance();
  cal.clear();
  cal.set(Calendar.YEAR, year);
  cal.set(Calendar.DAY_OF_YEAR, day);
  Date date = cal.getTime();
  SimpleDateFormat formatter = new SimpleDateFormat("MM/dd/yyyy");
  return formatter.format(date);
}

This will give you the date at 00:00 local time; you may want to set the timezone on the calendars to GMT instead, depending on the application.

回答5:

I see there are enough answers already provided. But any calendar related question is only half answered without mentioning joda-time ;-). Here is how simple it is with this library

// setup date object for the Battle of Hastings in 1066
Chronology chrono = JulianChronology.getInstance();
DateTime dt = new DateTime(1066, 10, 14, 10, 0, 0, 0, chrono);

来源：https://stackoverflow.com/questions/3017954/convert-a-julian-date-to-regular-calendar-date

标签

java

julian-date