ios6.1 | 易学教程

Display screen for iOS6 and iOS7 in simulator is different

阅读更多关于 Display screen for iOS6 and iOS7 in simulator is different

问题 My application i will give deployment target 6.1 so in 7.0 display and 6.1 display screen different so how to adjust the size in both 6.1 and 7.0 回答1: Main UI difference in iOS 6 and iOS 7 is that status bar is included inside the viewcontroller in iOS 7. it means your view controller is 20 px greater than iOS6. you have to adjust your items. First design your items according to iOS 6 which is better way and you must have a lot of practice of doing that, now set Δy to 20 for every item. Or

How to hide the status bar programmatically in iOS 7?

阅读更多关于 How to hide the status bar programmatically in iOS 7?

In ios7 , how can I hide the statusbar programmatically? I am using XCode 4.6.1 ( ios6.1 ) and I want to implement this in XCode itself. in iOS7 you should implement in your viewController - (BOOL)prefersStatusBarHidden { return YES; } you can hide status bar to set the key value "View controller-based status bar appearance" NO in plist. This is easiest way. or You can hide in code by using property statusBarHidden of UIApplication class. [[UIApplication sharedApplication] setStatusBarHidden:YES]; Swift 3.0 Hide status bar for any particular view controller override var prefersStatusBarHidden:

Error after upgrading to xcode 4.6 and iOS 6.1 “used as the name of the previous parameter rather than as part of the selector”

阅读更多关于 Error after upgrading to xcode 4.6 and iOS 6.1 “used as the name of the previous parameter rather than as part of the selector”

After updating to xcode 4.6 and ios6.1, I get this new error "'objectType' used as the name of the previous parameter rather than as part of the selector ". I get this multiple times. Any ideas? PS: The method that it get displayed is a custom one for reverse geocoding. -(void) getAddress: (NSString *) objectType: (CLLocationCoordinate2D) objectCoordinate iDev It says that objectType is the name of the NSString object in your method and not part of the method name and it should not be used as objectType: (CLLocationCoordinate2D) objectCoordinate which normally denotes a part of method name.

GoogleMap API Gives Wrong Coordinates for Direction between two Points

阅读更多关于 GoogleMap API Gives Wrong Coordinates for Direction between two Points

问题 I am using GoogleMap API for showing draw direction between two points on GoogleMap. i want to give support on iOS 6.1 so i use GoogleMap i know about iOS7 recover this. using below code for parsing and get Steps for coordinates to draw polyline on Map: NSString *str=@"http://maps.googleapis.com/maps/api/directions/json?origin=bharuch,gujarat&destination=vadodara,gujarat&sensor=false"; NSURL *url=[[NSURL alloc]initWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]

Error after upgrading to xcode 4.6 and iOS 6.1 “used as the name of the previous parameter rather than as part of the selector”

阅读更多关于 Error after upgrading to xcode 4.6 and iOS 6.1 “used as the name of the previous parameter rather than as part of the selector”

问题 After updating to xcode 4.6 and ios6.1, I get this new error "'objectType' used as the name of the previous parameter rather than as part of the selector ". I get this multiple times. Any ideas? PS: The method that it get displayed is a custom one for reverse geocoding. -(void) getAddress: (NSString *) objectType: (CLLocationCoordinate2D) objectCoordinate 回答1: It says that objectType is the name of the NSString object in your method and not part of the method name and it should not be used as