inverse

There is XOR function in Java - a^b For exemple: 5^3 = 6 Can you tell me inverse function? If I have 6 and 3 can i get range of numbers which include number 5 ? The inverse is XOR! If you have: c = a^b; You can get a or b back if you have the other value available: a = c^b; // or b^c (order is not important) b = c^a; // or a^c For example if a = 5 , b = 3 (and thus c = 6 as you mentioned) you get: b=0011 (3) a=0101 (5) c=0110 (6) XOR or c=0110 (6) XOR ---------- ---------- a=0101 (5) b=0011 (3) The inverse of XOR is XOR..... 来源： https://stackoverflow.com/questions/14279866/what-is-inverse

I want to determine (in c++) if one float number is the multiplicative inverse of another float number. The problem is that i have to use a third variable to do it. For instance this code: float x=5,y=0.2; if(x==(1/y)) cout<<"They are the multiplicative inverse of eachother"<<endl; else cout<<"They are NOT the multiplicative inverse of eachother"<<endl; will output: "they are not..." which is wrong and this code: float x=5,y=0.2,z; z=1/y; if(x==z) cout<<"They are the multiplicative inverse of eachother"<<endl; else cout<<"They are NOT the multiplicative inverse of eachother"<<endl; will output

I want to invert a matrix without using numpy.linalg.inv . The reason is that I am using Numba to speed up the code, but numpy.linalg.inv is not supported, so I am wondering if I can invert a matrix with 'classic' Python code. With numpy.linalg.inv an example code would look like that: import numpy as np M = np.array([[1,0,0],[0,1,0],[0,0,1]]) Minv = np.linalg.inv(M) Here is a more elegant and scalable solution, imo. It'll work for any nxn matrix and you may find use for the other methods. Note that getMatrixInverse(m) takes in an array of arrays as input. Please feel free to ask any questions

Is there any way for R to solve for the inverse of a given single variable function? The motivation is for me to later tell R to use a vector of values as inputs of the inverse function so that it can spit out the inverse function values. For instance, I have the function y(x) = x^2 , the inverse is y = sqrt(x) . Is there a way R can solve for the inverse function? I looked up uniroot() , but I am not solving for the zero of a function. Any suggestions would be helpful. Thanks! What kind of inverse are you finding? If you're looking for a symbolic inverse (e.g., a function y that is

Can someone recommend a more elegant way to achieve these compile-time constants? template <int> struct Map; template <> struct Map<0> {static const int value = 4;}; template <> struct Map<1> {static const int value = 8;}; template <> struct Map<2> {static const int value = 15;}; template <int> struct MapInverse; template <> struct MapInverse<4> {static const int value = 0;}; template <> struct MapInverse<8> {static const int value = 1;}; template <> struct MapInverse<15> {static const int value = 2;}; The values need to be constexpr in my program, yet the inverse mapped values are getting

I am new in OpenCV and image processing algorithms. I need to do inverse discrete fourier transformation in OpenCV in C++, but I don't know how. I searched over internet and I didn't find answer. I am doing fourier transformation in my program with this code from this page: http://opencv.itseez.com/doc/tutorials/core/discrete_fourier_transform/discrete_fourier_transform.html . I have tried to do inverse to that code, but I don't know where I am doing wrong. My code is here (I think that whole code is wrong): void doFourierInverse(const Mat &src, Mat &dst) { normalize(src, dst, 0, -1, CV_MINMAX