inverse

Sorry if this has been asked before, but I couldn't find any answers on the web. I'm having a hard time figuring out the inverse to this regex: "\"[^>]*\">" I want to use replaceAll to replace everything except the link. So if I had a tag similar to this: <p><a href="http://www.google.com">Google</a></p> I need a regex that would satisfy this: s.replaceAll(regex, ""); to give me this output: http://www.google.com I know there are better ways to do this, but I have to use a regex. Any help is really appreciated, thanks! You do not have to use replaceAll . Better use pattern groups like the

e.g. The inverse color from black should be white. iOS5+ -(UIColor*) inverseColor { CGFloat r,g,b,a; [self getRed:&r green:&g blue:&b alpha:&a]; return [UIColor colorWithRed:1.-r green:1.-g blue:1.-b alpha:a]; } ---- EDIT ---- Based on @amleszk's answer, I updated the UIColor extension/category with this method: // Swift func inverseColor() -> UIColor { var alpha: CGFloat = 1.0 var white: CGFloat = 0.0 if self.getWhite(&white, alpha: &alpha) { return UIColor(white: 1.0 - white, alpha: alpha) } var hue: CGFloat = 0.0, saturation: CGFloat = 0.0, brightness: CGFloat = 0.0 if self.getHue(&hue,

级联（Cascade） ： 二个以上的设备通过某种方式连接起来，能起到扩容的效果就是级联。Hibernate级联（Cascade）是用来说明数据库中两个表之间相互关系(一对一,一对多,多对多)中，当对主对象进行某种操作时，是否对其关联的从对象也作类似的操作（比如有对象Department和Employee，它们之间是一对多的关系，当保存Department时，其对应的Employee是否也相应的保存），常见的级联(Cascade)有： (1)none：在保存，删除或修改当前对象时，不对其附属对象（关联对象）进行级联操作。它是默认值。 (2)save-update：在保存，更新当前对象时，级联保存，更新附属对象(临时对象，游离对象)。 (3)delete：在删除当前对象时，级联删除附属对象。 (4)all：所有情况下均进行级联操作，即包含save-update和delete等等操作。 (5)delete-orphan：删除此对象的同时删除与当前对象解除关系的孤儿对象(仅仅使用于一对多关联关系中)。 对Hibernate session的每一个基本操作，如：persist(),merge(),saveOrUpdate(),delete(),lock(),refresh(),evict(),replicate(),都有一个相关的级联形式与之对应，他们分别命名为：create,merge

I didn't find any similar question to mine. I'm trying to write the gaussian-jordan inverse matrix algorithm. The idea of the algorithm is simple:) I want to inverse only a lower triangular matrix. I got almost correct answer. Where did I do sth wrong? Does anyone can help me? I will appreciate it. d _ A lower triangular matrix (nxn) dI identity matrix (nxn) n size of a matrix in one direction (n%16=0) dim3 threadsPerBlock(n/16,n/16); dim3 numBlocks(16,16); I know it is a simple implementation but at first I need it to work correctly :) Does anyone can help me or give me any hint? I will

I have a larger SQL that produces a similar output as this simplified example: SELECT 5 AS L0, 2 AS L1, 3 AS L2, 4 AS L3 FROM DUAL current output is this row: | L0 | L1 | L2 | L3 | | 5 | 2 | 3 | 4 | desired output are this columns: | kind | value | | 0 | 5 | | 1 | 2 | | 2 | 3 | | 3 | 4 | I know I could get this by union the select 4 times. I'm looking for advice if union is the best I can do here and if this output can be achieved by other means. I also found many examples to inverse a column to a row but here I'm looking for inversion from a row to column. Please try UnPIVOT: SELECT substr

I am trying to build a CoreData model similar to Twitter user when User can have many other users who follows him and many other users followed by him. I attached the model that I have tried to use but seems it is getting to complicating to retrieve followers. What is the best way to deal with this situation? I think you need to create a second relationship ( followedBy ) and make that the inverse. 来源： https://stackoverflow.com/questions/12709842/ios-coredata-inverse-relationships-to-itself

I'm looking for an algorithm (or code) to help me compute the inverse a polynomial, I need it for implementing NTRUEncrypt. An algorithm that is easily understandable is what I prefer, there are pseudo-codes for doing this, but they are confusing and difficult to implement, furthermore I can not really understand the procedure from pseudo-code alone. Any algorithms for computing the inverse of a polynomial with respect to a ring of truncated polynomials ? I work for Security Innovation, which owns NTRU, so I'm glad to see this interest. The IEEE standard 1363.1-2008 specifies how to implement

My problem is that i want to check the browserstring with pure regex. Mozilla/5.0 (Linux; U; Android 3.0; en-us; Xoom Build/HRI39) AppleWebKit/534.13 (KHTML, like Gecko) Version/4.0 Safari/534.13 -> should match Mozilla/5.0 (Linux; U; Android 2.2.1; en-us; Nexus One Build/FRG83) AppleWebKit/533.1 (KHTML, like Gecko) Version/4.0 Mobile Safari/533.1 should not match my tried solution is: /?((?<=Android)(?:[^])*?(?=Mobile))/i but it matches exactly wrong. You use look ahead assertions to check if a string contains a word or not. If you want to assure that the string contains "Android" at some