inverse

Can anyone explain to me what is going on in this line of MatLAB code

本秂侑毒 提交于 2019-12-14 04:13:37
问题 y = rand(20,3); aa= unidrnd(2,20,3) - 1; val = ( aa & y<1.366e-04) | (~aa & y<8.298e-04); aa(val) = ~aa(val); I have this code. Can any one explain to me what is happening here. I have tried to understand it step by step (debugging) but I cannot understand the purpose of using inverse '~' in line 4 and also using 'val' as indices. 回答1: y = rand(20,3); Creates a matrix of uniformly distributed random numbers, y . aa= unidrnd(2,20,3) - 1; Creates a matrix of uniformly distributed random

Inverted Index in Python not returning desired results

孤街浪徒 提交于 2019-12-13 09:29:29
问题 I'm having trouble returning proper results for an inverted index in python. I'm trying to load a list of strings in the variable 'strlist' and then with my Inverse index looping over the strings to return the word + where it occurs. Here is what I have going so far: def inverseIndex(strlist): d={} for x in range(len(strlist)): for y in strlist[x].split(): for index, word in set(enumerate([y])): if word in d: d=d.update(index) else: d._setitem_(index,word) break break break return d Now when

Do I Have to Manually Set a Core Data Object's Inverse Relationship in Code on the iPhone

拟墨画扇 提交于 2019-12-12 11:15:05
问题 I am new to core data so please excuse me if I get some of the terms wrong. I have several objects in my xcdatamodel file. They are all inter connected with relationships and inverse relationships. If I connect two of these objects with the following code the inverse relationship is not set. [managedObj1 setValue: managedObj2 forKey:@"relatiohipName"]; I seem to have to manually set the inverse relationship myself with the following code [managedObj1 setValue: managedObj2 forKey:@

Matlab: How to compute the inverse of a matrix

故事扮演 提交于 2019-12-12 03:44:16
问题 I want to find the T inverse as given in the picture. The first picture is the matrix T and the other is T inverse. I = eye(3); T = [I/2, (j/2)*I, 0; I/2, (-j/2)*I, 0; 0,0,I]; Error using horzcat CAT arguments dimensions are not consistent. Then I tried with I = eye(2) and got the same error. What is the proper way? 回答1: Given I = eye(3); you want to multiply element-wise using .* with A (make sure you use the imaginary unit 1j and not an undefined variable j ) A = [1/2, (1j/2), 0; 1/2, (-1j

finding difference between two rotation matrices

强颜欢笑 提交于 2019-12-11 15:12:40
问题 I am having following problem, I have developed code for converting the large array of euler angles to rotation matrices, my data is phi1,phi and phi2 values like as follows phi1 phi phi2 2 3 5 1 2.2 4.3 3 4 5 .....there are other 2 million array of data. but I want to carry out inverse of the rotation matrix formed from first row of euler angles and multiply it to matrix developed from the second row. Then I have to use one of the elements of the resultant matrix. Is there any way to do that

nhibernate bidirectional mapping

泄露秘密 提交于 2019-12-11 14:16:47
问题 Given the object model, mapping, and code below, I want to achieve the following: On SAVE of new parent Party objects, I'd like for the parent to persist child PartyNames as well. SO ideally I can just do: var party = new Party(); party.AddPartyName(_developerName) using(var tx = session.BeginTransaction){ _session.Save (party); tx.Commit() } But my understanding from the last question I asked on this is that while this is doable with inverse="false", I really want to define the children set

Get opposite/inverse of jQuery .filter() results

坚强是说给别人听的谎言 提交于 2019-12-11 06:16:44
问题 I have a .filter function, which works and marks all parents of <td> that contain an input field in red. However, I need the exact opposite. So return all fields that don't contain <input . I tried if ($(this).html().indexOf('<input') == -1) { but that just marks all rows somehow. My jQuery: $(document).ready(function () { $("#ListView1_itemPlaceholderContainer table table table td").filter(function (index) { if ($(this).html().indexOf('<input') > 0) { return true; } }).closest('div').css(

Invert a series of data as if inverting a function using MATLAB

浪尽此生 提交于 2019-12-10 21:15:52
问题 Is it possible to "invert" a series of data like when a function is inverted? Let me explain. If I have a function that I can plot in MATLAB, I can always (almost) find the inverse of such function with the finverse and the plot would provide this: But I do not have the a function for my data, and I would still like to find a sort of inverse of such series of data, like for example y=f(x) where x=[0.0050879 0.0056528 0.0062176 0.0067822 0.0073467 0.0079111 0.0084752 0.0090392 0.0096030 0

Inverse function in Scala

左心房为你撑大大i 提交于 2019-12-10 13:59:36
问题 Is there a way to express the inverse of any function in Scala? For example if I have a function f like this: (x: Int) => x + 1 I would like to be able write an inverse function g like: (f(x): Int) => x // not a valid scala syntax or (x: Int) => inverse(f(x)) // inverse would return (x => x -1) Do you know a way to do this kind of thing in Scala? N.B: x => x+1 is just for the example. I'm looking for a generic way to solve this kind of task. 回答1: No, something like that is not possible. The

sympy.solve() doesn't give one of the solutions with LambertW

僤鯓⒐⒋嵵緔 提交于 2019-12-10 09:44:24
问题 Background: I am trying to implement a function doing an inverse transform sampling. I use sympy for calculating CDF and getting its inverse function. While for some simple PDFs I get correct results, for a PDF which CDF's inverse function includes Lambert-W function, results are wrong. Example: Consider following example CDF: import sympy as sym y = sym.Symbol('y') cdf = (-y - 1) * sym.exp(-y) + 1 # derived from `pdf = x * sym.exp(-x)` sym.plot(cdf, (y, -1, 5)) Now calculating inverse of