inline-functions

问题 Is there a good reason to choose between using inline functions vs anonymous functions in MATLAB? This exact question has been asked and answered here, but the answer is not helpful for rookie MATLAB users because the code snippets are incomplete so they do not run when pasted into the MATLAB command window. Can someone please provide an answer with code snippets that can be pasted into MATLAB? 回答1: Anonymous functions replaced inline functions (as mentioned in both the docs and in the link

问题 I know that an inline function will maybe improve performance & cause the generated code to grow, but I'm not sure when it is correctly to use it. lock(l) { foo() } Instead of creating a function object for the parameter and generating a call, the compiler could emit the following code. (Source) l.lock() try { foo() } finally { l.unlock() } but I found that there is no function object created by kotlin for a non-inline function. why? /**non-inline function**/ fun lock(lock: Lock, block: () ->

问题 We all know that inline functions can make debugging trickier, as they can be elided from stack traces etc. But suppose I want to call an inline function from within gdb, and I know its name and its arguments. I think I should be able to do that, but I get this: Cannot evaluate function -- may be inlined I used nm to list the symbols in the shared library I'm using, and found that the functions I want to call are not in there. No big surprise. What I'd like is a way to generate visible

问题 I'm trying to clean up code by stripping parameters from a function within a private scope, like this: Function complicatedFunction(x as Double, param1 as Double, param2 as Double) ... End Function Function mainActionHappensHere(L as Double, U as Double ...) Function cleaner(x) cleaner = complicatedFunction(x, L, U) End Function ... cleaner(x) 'Many calls to this function ... End Function Is this possible? Compiler complains, "Expected End Function", since I'm beginning a function before

问题 This question already has answers here : Decrementing a pointer out of bounds; incrementing it into bounds [duplicate] (3 answers) Why is out-of-bounds pointer arithmetic undefined behaviour? (7 answers) Closed 5 years ago . I found this problem in a very large application, have made an SSCCE from it. I don't know whether the code has undefined behavior or -O2 breaks it. When compiling it with gcc a.c -o a.exe -O2 -Wall -Wextra -Werror it prints 5 . But it prints 25 when compiling without -O2

问题 What's the difference between inline function and then main like so: inline double cube(double side) { return side * side * side; } int main( ) { cube(5); } vs just declaring a function regularly like: double cube(double side) { return side * side * side; } int main( ) { cube(5); } vs function prototype? double cube(double); int main( ) { cube(5); } double cube(double side) { return side * side * side; } 回答1: An inline function can be defined in multiple translation units (cpp file + includes

问题 Does LLVM automatically convert Objective-C methods to inline functions when possible? (I.e., is it just as performant to create an Objective-C method for a block of code that you could otherwise paste inline?) If LLVM doesn't perform this optimization, why not? If it does, (a) are there certain build settings I must set for this to happen? (b) How can I tell if an Objective-C method will be inlined? 回答1: No, because its impossible to know in the context of the Obj-C runtime if those kind of

问题 What's the difference between a static inline , extern inline and a normal inline function? I've seen some vague explanations about this. As far as I've understood, static inline is not just an inline function that is meant to only be referred to within a certain file as the static keyword usually means. The same goes for extern inline too I guess, it's not the same explanation as with extern variables. Any answers would be greatly appreciated! 回答1: A function definition with static inline

问题 Statement: "Inline-functions must be defined before they are called." Is this statement correct? [EDIT] The question is originally in german: Inline-Funktionen müssen vor ihrem Aufruf definiert sein. Maybe it helps anybody... 回答1: Yes it is correct but only partly.It maybe re-framed correctly as follows: "Inline-functions must be defined in every translation unit (but not necessarily before) in which they are called." C11++ Standard: §7.1.2.4 An inline function shall be defined in every

问题 class MyClass { public: MyClass() { m_dbLoopStart = 0.0; m_dbLoopStop = 100.0; m_dbLoopStep = 0.001; } // Which of the following methods complete in a shorter time? void Foo1() const // This one? { for (double x=m_dbLoopStart; x<=m_dbLoopStop; x+=m_dbLoopStep) { f(x); } } void Foo2() const // Or, this one? { for (double x=m_dbLoopStart; x<=m_dbLoopStop; x+=m_dbLoopStep) { 2.0 * x + 1.0; } } private: double m_dbLoopStart, m_dbLoopStop, m_dbLoopStep; inline static double f(double x) { return 2