higher

Python——高阶函数概念(Higher-order function)

爱⌒轻易说出口 提交于 2020-02-09 02:54:36
1、变量可以指向函数 以内置的求绝对值abs()函数为例,: >>> abs(-12) 12 >>> abs <built-in function abs> >>> m = abs >>> m <built-in function abs>>>> m(-12)1 可知,函数本身可以赋值给变量,即:变量指向函数。此时,我们可以通过变量来调用这个函数! 2、函数名其实也是变量 >>> abs = 10 >>> abs(-10) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: 'int' object is not callable 当abs指向10的时候,就无法通过abs(-10)调用该函数了。因为函数名其实就是一个指向函数的变量!abs这个变量已经指向一个整数-10!要恢复abs的原始功能,就要重启python的交互环境了。 3、高阶函数 既然变量可以指向函数,而函数的参数又能接收变量,那么一个函数就可以接收另外一个函数作为参数。这样的函数就是高阶函数。简单举例: >>> def add(x,y,f): ... return f(x)+f(y) ... >>> add(6,7,abs) 13 推导过程如下: x = 6 y = 7 f = abs f(x) + f(y)

LeetCode 374. Guess Number Higher or Lower

最后都变了- 提交于 2020-02-03 21:40:32
374. Guess Number Higher or Lower(猜数字大小) 链接 https://leetcode-cn.com/problems/guess-number-higher-or-lower 题目 我们正在玩一个猜数字游戏。 游戏规则如下: 我从 1 到 n 选择一个数字。 你需要猜我选择了哪个数字。 每次你猜错了,我会告诉你这个数字是大了还是小了。 你调用一个预先定义好的接口 guess(int num),它会返回 3 个可能的结果(-1,1 或 0): -1 : 我的数字比较小 1 : 我的数字比较大 0 : 恭喜!你猜对了! 示例 : 输入: n = 10, pick = 6 输出: 6 思路 这个也是二分查找,只不过又换了一种问法。 这里只需要注意到leftright的更新与guess函数的返回值即可。 代码 public static int guessNumber(int n) { int left = 1; int right = n; while (left <= right) { int mid = left + (right - left) / 2; if (guess(mid) == 0) { return mid; } else if (guess(mid) == 1) { left = mid + 1; } else if (guess

Guess Number Higher or Lower

寵の児 提交于 2020-01-28 02:32:06
原题链接在这里: https://leetcode.com/problems/first-bad-version/ 题目: You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad. Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad. You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad

ng-初步学习

我的未来我决定 提交于 2020-01-19 19:31:00
安装 依赖 Node 6.9.0 or higher NPM 3 or higher Python C++ 编译工具 安装 npm install -g @angular/cli 使用帮助 ng help 初始化项目 ng new <项目名称> 启动开发服务 ng serve ng serve 默认占用 4200 端口号,可以通过下面选项配置: ng serve --port 4201 来源: https://www.cnblogs.com/ygjzs/p/12215288.html

error: Autoconf version 2.67 or higher is required

回眸只為那壹抹淺笑 提交于 2019-12-23 13:08:54
error: Autoconf version 2.67 or higher is required 今天linux下遇到这种错误,顺便记录下来。 #rpm -qf /usr/bin/autoconf 查看当前的版本。 #rpm -e --nodeps autoconf-2.63 卸载当前的版本 #wget ftp://ftp.gnu.org/gnu/autoconf/autoconf-2.68.tar.gz 安装最新版本 下载并安装 # wget ftp://ftp.gnu.org/gnu/autoconf/autoconf-2.68.tar.gz # tar zxvf autoconf-2.68.tar.gz # cd autoconf-2.68 # ./configure --prefix=/usr/ # make && make install 来源: https://www.cnblogs.com/tonyY/p/4817792.html

SMS Receiver for AND API 19 and higher

时光毁灭记忆、已成空白 提交于 2019-12-12 01:05:35
问题 My job is to create SMS APP to hide selected numbers so that from falling further into default SMS app, this task is simple API for AND <19 using this code. public class SMSReceiver extends BroadcastReceiver { public static String TAG = "SMSReceiver"; ToneGenerator tg = new ToneGenerator(AudioManager.STREAM_MUSIC, 100); public SMSReceiver() { } @Override public void onReceive(Context context, Intent intent) { SMS_Throttle.VytvorDatabazi(context); String act = intent.getAction(); Log.d(TAG,

LeetCode_374. Guess Number Higher or Lower

给你一囗甜甜゛ 提交于 2019-12-04 09:45:00
374. Guess Number Higher or Lower Easy We are playing the Guess Game. The game is as follows: I pick a number from 1 to n . You have to guess which number I picked. Every time you guess wrong, I'll tell you whether the number is higher or lower. You call a pre-defined API guess(int num) which returns 3 possible results ( -1 , 1 , or 0 ): -1 : My number is lower 1 : My number is higher 0 : Congrats! You got it! Example : Input: n = 10, pick = 6 Output: 6 package leetcode.easy; /* The guess API is defined in the parent class GuessGame. @param num, your guess @return -1 if my number is lower, 1

Silverlight BusyIndicator : Higher Z-Index than all ChildWindows

匿名 (未验证) 提交于 2019-12-03 09:52:54
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Perhaps the title is worded incorrectly. I have a "global" Busy Indicator that works great, as long as I don't try to use it when a ChildWindow is open. I access the "global" Busy Indicator by using a static method in my App.xaml.cs: BusyIndicator b = (BusyIndicator)App.Current.RootVisual; if (b != null) { b.BusyContent = busyText; b.IsBusy = true; } However, if a ChildWindow is open, the BusyIndicator is always behind it. I thought that I could set b.Content = VisualTreeHelper.GetOpenPopups().First() , but that didn't work either. Does

In Java 6, why doesn't higher priority thread not run even if lower priority thread yields?

匿名 (未验证) 提交于 2019-12-03 09:06:55
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: In the code below, I am trying to get the higher priority thread to run by yielding the lower priority thread. But it doesn't seem to work, the higher priority thread seems to run after lower priority thread finishes. Can anyone explain what I am doing wrong? import java . util . ArrayList ; import java . util . List ; public class TestThreadPriority extends Thread { static List < String > messages = new ArrayList < String >(); public void run () { Thread t = Thread . currentThread (); int priority = t . getPriority (); String name