function

问题 For the sake of code readability, I'd like to move my Excel stuff to a function and leave the worksheet object available to write cell values as my program processes stuff. How do I call a function that creates an Excel spreadsheet and return a worksheet reference so I can continue to access the open/active Excel app object I've created? Function Create-Excel-Spreadsheet() { # open excel $excel = New-Object -ComObject excel.application $excel.visible = $True # add a worksheet $workbook =

问题 I want to shuffle the numbers in my array variable once, so I called my Shuffle method from Start() . I then attempt access the shuffled array from update, but I am unable to do so. How can I access it? Is there any other way to shuffle my array once, then use it forever? private System.Random _random = new System.Random(); float sec; float timecount; float starttime; void Start () { starttime = Time.time; int[] array = { 1, 2, 3, 4, 5, 6, 7, 8}; Shuffle(array); foreach (int value in array) {

问题 Let us say we have this function: function greetMe (string $name) { echo '<br/>'.$name; echo '<br/>'.gettype($name); } As you can see, we can get the type of the parameter $name . Now I am interested to know if there is a possibility, within the body of this function, to know that I declared the type string and not some other type. Any hints? 回答1: In PHP 7 and later, you can use ReflectionParameter.getType. Example #1 ReflectionParameter::getType() example <?php function someFunction(int

问题 I have build a function where I append the returns of 5 portfolios to a dataframe which I want to return to a variable . When I run the commands within the function row by row(kind of debugging) I end upwith the variable 'folioReturn'(which is the one I want my script to return) having the right amount of values (e.x 5). But if I call the function, only the first value of the dataframe is returned. Does anyone know how I can get the whole dataframe ? def portfolioReturns (securities,

问题 I have been using Allen Browne's ConcatRelated function, and while it works fine when the data comes from a table, but it doesn't work when the data comes from a query. The green 'running query' bar appears for a few seconds, but then when it tries to display the data it shows only one field from the first row, runs very slowly and can take a few minutes to display the first screen of records. I've not managed to leave it long enough to complete the result set, have to shut down Access using

问题 Thanks in advance for the help. I am new to kdb/q, coming from a Python and C++ background. Just a simple syntax question: I have a string with fields and their corresponding values pp_str: "field_1:abc field_2:xyz field_3:kdb" I wrote an atomic (scalar) function to extract the value of a given field. get_field_value: {[field; pp_str] pp_fields: " " vs pp_str; pid_field: pp_fields[where like[pp_fields; field,":*"]]; start_i: (pid_field[0] ss ":")[0] + 1; end_i: count pid_field[0]; indices:

问题 Thanks in advance for the help. I am new to kdb/q, coming from a Python and C++ background. Just a simple syntax question: I have a string with fields and their corresponding values pp_str: "field_1:abc field_2:xyz field_3:kdb" I wrote an atomic (scalar) function to extract the value of a given field. get_field_value: {[field; pp_str] pp_fields: " " vs pp_str; pid_field: pp_fields[where like[pp_fields; field,":*"]]; start_i: (pid_field[0] ss ":")[0] + 1; end_i: count pid_field[0]; indices:

问题 I came across a function where it had a setTimeout inside with a timeout growing exponentially (timeout *= 2) . let timeout = 10000 function foo() { // doSomething without breaking, returning setTimeout(foo, timeout) timeout *= 2; } foo() It seems that this should not be a problem and intuitively feels like setInterval is kinda doing the same already (having an infinite loop until it's cancelled if ever) , however, my question is in the approach itself. Is this something that could lead to

问题 I came across a function where it had a setTimeout inside with a timeout growing exponentially (timeout *= 2) . let timeout = 10000 function foo() { // doSomething without breaking, returning setTimeout(foo, timeout) timeout *= 2; } foo() It seems that this should not be a problem and intuitively feels like setInterval is kinda doing the same already (having an infinite loop until it's cancelled if ever) , however, my question is in the approach itself. Is this something that could lead to

问题 Whats the difference between using the built-in call and return instructions vs manually pushing and popping the stack and using jumps for functions? 回答1: Functionally, if you do it correctly, nothing. However it takes more instructions and/or registers to emulate call / ret using push / pop . Of course if you really wanted to take it to the extreme, you could also emulate push / pop using lea and mov :) Also, current processors have specialized hardware to handle function calls for the