formatting

问题 I am new to coding and I can understand that this is a very basic question I have a dataframe as: df Unnamed: 0 time home_team away_team full_time_result both_teams_to_score double_chance -- ------------ ------------------- ------------- -------------- ---------------------------------- ------------------------- ------------------------------------ 0 0 2021-01-12 18:00:00 Sheff Utd Newcastle {'1': 2400, 'X': 3200, '2': 3100} {'yes': 2000, 'no': 1750} {'1X': 1360, '12': 1360, '2X': 1530} 1 1

问题 Problem: I have 2d array which is filled with numbers. I have to output it in a way that it shows: "*" between neighbours with different values and with " " if values are the same. Example: ********* *1 1*3*4* ***** * * *2 2*3*4* ********* I have tried many things like creating another array with [Nx2][Mx2] size or System.out.format , but in the end it's never formatted the way I like. Any suggestions how can I solve this? private static void changeColumn(int[][] secondLayerArr, int n, int m)

问题 The Goal is to format a polynomial with more than 6 parameters into a plot title. Here is my polynomial parameter to string expression function, inspired by this answer, followed by sym.latex() : def func(p_list): str_expr = "" for i in range(len(p_list)-1,-1,-1): if (i%2 == 0 and i !=len(p_list)): str_expr =str_expr + " \n " if p_list[i]>0: sign = " +" else: sign = "" if i > 1: str_expr = str_expr+" + %s*x**%s"%(p_list[i],i) if i == 1: str_expr = str_expr+" + %s*x"%(p_list[i]) if i == 0: str

问题 I have a list o tuples: list = [(element1, element2, element3), (elementelel4, element5, elementelement6), (el7, el8, elel9)] I want to print it as a table (so the distance between elements should be the same): HEADER1 HEADER2 HEADER3 element1 element2 element3 elementelel4 element5 elementelement6 el7 el8 elel9 I was trying to use some examples which I found, but it was used to print a list of lists, and I have a list of tuples. 回答1: Using Format Specification Mini-Language print "HEADER1

问题 The issue is that using to_char will turn order by date into order by ascii. Example: SELECT foo, bar FROM baz ORDER BY foo; I would like to format foo using to_char, but doing this will affect the order: SELECT to_char(foo,'dd/MM/yyyy') as foo, bar FROM baz ORDER BY foo; Because foo now is of type text. There is a way to correctly do this? Or only in the code? 回答1: You can use a different alias for the formatted column: SELECT to_char(foo,'dd/MM/yyyy') as formatted_foo, bar FROM baz ORDER BY

问题 The issue is that using to_char will turn order by date into order by ascii. Example: SELECT foo, bar FROM baz ORDER BY foo; I would like to format foo using to_char, but doing this will affect the order: SELECT to_char(foo,'dd/MM/yyyy') as foo, bar FROM baz ORDER BY foo; Because foo now is of type text. There is a way to correctly do this? Or only in the code? 回答1: You can use a different alias for the formatted column: SELECT to_char(foo,'dd/MM/yyyy') as formatted_foo, bar FROM baz ORDER BY

问题 The issue is that using to_char will turn order by date into order by ascii. Example: SELECT foo, bar FROM baz ORDER BY foo; I would like to format foo using to_char, but doing this will affect the order: SELECT to_char(foo,'dd/MM/yyyy') as foo, bar FROM baz ORDER BY foo; Because foo now is of type text. There is a way to correctly do this? Or only in the code? 回答1: You can use a different alias for the formatted column: SELECT to_char(foo,'dd/MM/yyyy') as formatted_foo, bar FROM baz ORDER BY

问题 The issue is that using to_char will turn order by date into order by ascii. Example: SELECT foo, bar FROM baz ORDER BY foo; I would like to format foo using to_char, but doing this will affect the order: SELECT to_char(foo,'dd/MM/yyyy') as foo, bar FROM baz ORDER BY foo; Because foo now is of type text. There is a way to correctly do this? Or only in the code? 回答1: You can use a different alias for the formatted column: SELECT to_char(foo,'dd/MM/yyyy') as formatted_foo, bar FROM baz ORDER BY

问题 The issue is that using to_char will turn order by date into order by ascii. Example: SELECT foo, bar FROM baz ORDER BY foo; I would like to format foo using to_char, but doing this will affect the order: SELECT to_char(foo,'dd/MM/yyyy') as foo, bar FROM baz ORDER BY foo; Because foo now is of type text. There is a way to correctly do this? Or only in the code? 回答1: You can use a different alias for the formatted column: SELECT to_char(foo,'dd/MM/yyyy') as formatted_foo, bar FROM baz ORDER BY

问题 The issue is that using to_char will turn order by date into order by ascii. Example: SELECT foo, bar FROM baz ORDER BY foo; I would like to format foo using to_char, but doing this will affect the order: SELECT to_char(foo,'dd/MM/yyyy') as foo, bar FROM baz ORDER BY foo; Because foo now is of type text. There is a way to correctly do this? Or only in the code? 回答1: You can use a different alias for the formatted column: SELECT to_char(foo,'dd/MM/yyyy') as formatted_foo, bar FROM baz ORDER BY