问题
I have a list o tuples:
list = [(element1, element2, element3), (elementelel4, element5, elementelement6), (el7, el8, elel9)]
I want to print it as a table (so the distance between elements should be the same):
HEADER1 HEADER2 HEADER3
element1 element2 element3
elementelel4 element5 elementelement6
el7 el8 elel9
I was trying to use some examples which I found, but it was used to print a list of lists, and I have a list of tuples.
回答1:
Using Format Specification Mini-Language
print "HEADER1 HEADER2 HEADER3"
for ele1,ele2,ele3 in l:
print "{:<14}{:<11}{}".format(ele1,ele2,ele3)
HEADER1 HEADER2 HEADER3
element1 element2 element3
elementelel4 element5 elementelement6
el7 el8 elel9
回答2:
You can use ljust
for left-aligning the element within a fixed width
column_width=20
for row in list:
for el in row:
print el.ljust(column_width),
print
output
element1 element2 element3
elementelel4 element5 elementelement6
el7 el8 elel9
回答3:
Assume that, all tuples in the list is of the same length, you can use this:
l = [('element1', 'element2', 'element3'), ('elementelel4', 'element5', 'elementelement6'), ('el7', 'el8', 'elel9')]
width = max(len(e) for t in l for e in t[:-1]) + 1
format=('%%-%ds' % width) * len(l[0])
print '\n'.join(format % tuple(t) for t in l)
Output:
element1 element2 element3
elementelel4 element5 elementelement6
el7 el8 elel9
回答4:
Python 3 solution:
L = [('element1', 'element2', 'element3'),
('elementelel4', 'element5', 'elementelement6'),
('el7', 'el8', 'elel9')]
max_length_column = []
element_in_tuple = 3
for i in range(elements_in_tuple):
max_length_column.append(max(len(e[i])+2 for e in L))
for e in L:
for i in range(element_in_tuple):
print(e[i].ljust(max_length_column[i]), end='')
print()
output:
element1 element2 element3
elementelel4 element5 elementelement6
el7 el8 elel9
来源:https://stackoverflow.com/questions/25403249/print-a-list-of-tuples-as-table