fibonacci

问题 This is the question : Given a positive integer num, return the sum of all odd Fibonacci numbers that are less than or equal to num. The first two numbers in the Fibonacci sequence are 1 and 1. Every additional number in the sequence is the sum of the two previous numbers. The first six numbers of the Fibonacci sequence are 1, 1, 2, 3, 5 and 8. For example, sumFibs(10) should return 10 because all odd Fibonacci numbers less than or equal to 10 are 1, 1, 3, and 5. This is what I tried function

问题 This is the question : Given a positive integer num, return the sum of all odd Fibonacci numbers that are less than or equal to num. The first two numbers in the Fibonacci sequence are 1 and 1. Every additional number in the sequence is the sum of the two previous numbers. The first six numbers of the Fibonacci sequence are 1, 1, 2, 3, 5 and 8. For example, sumFibs(10) should return 10 because all odd Fibonacci numbers less than or equal to 10 are 1, 1, 3, and 5. This is what I tried function

问题 I should preface this by saying this is a homework problem that I am having issues with, and Im not sure if that sort of thing is allowed around here, but I dont know where else to turn to. This is the question I've been asked: In the sample code for this question, you can see a Fibonacci predicate fibSimple/2 which calculates the Fibonacci of X, a natural number. The problem with the naive recursive solution, is that you end up recalculating the same recursive case several times. See here

问题 I'm trying to solve Fibonacci using java, but my code takes so long with big numbers. Problem Description Task. Given an integer 𝑛, find the last digit of the 𝑛th Fibonacci number 𝐹𝑛 (that is, 𝐹𝑛 mod 10). Input Format. The input consists of a single integer 𝑛. Constraints. 0 ≤ 𝑛 ≤ 10⁷. Output Format. Output the last digit of 𝐹𝑛 . My code: public class FibonacciLastDigit { private static int getFibonacciLastDigitNaive(int n) { if (n <= 1) { return n; } BigInteger first = BigInteger.ZERO;

问题 I'm trying to solve Fibonacci using java, but my code takes so long with big numbers. Problem Description Task. Given an integer 𝑛, find the last digit of the 𝑛th Fibonacci number 𝐹𝑛 (that is, 𝐹𝑛 mod 10). Input Format. The input consists of a single integer 𝑛. Constraints. 0 ≤ 𝑛 ≤ 10⁷. Output Format. Output the last digit of 𝐹𝑛 . My code: public class FibonacciLastDigit { private static int getFibonacciLastDigitNaive(int n) { if (n <= 1) { return n; } BigInteger first = BigInteger.ZERO;

问题 I am being very late to the google foobar party. I am stuck at level 2, and only the last test case is pending. But I am completely clueless of what this question is expecting in this last test case. I googled the question and looks like they've updated the test case and the constraint of lambs < 10 has been removed. Question is: Lovely Lucky LAMBs Being a henchman isn't all drudgery. Occasionally, when Commander Lambda is feeling generous, she'll hand out Lucky LAMBs (Lambda's All-purpose

问题 I'm trying to compute large numbers of the Fibonacci sequence, hence why I am using big integer. I can get up to about 10000 the way it is, but I run out of stack space. I realize I can increase stack and heap space, but it is my understanding that tail recursion can get around the space issue. Here is my code.. public class FibRecursion{ static BigInteger[] fval; public static void main(String[] args) { int index; Scanner input = new Scanner(System.in); index = input.nextInt(); fval = new

问题 My assignment for school is to implement a method that checks if a given ArrayList is part of the Fibonacci sequence. The array must not be empty and must be bigger than 3. I understood that I have to check if one number of the array and the next one are part of the Fibonacci sequence, however I have a lot of trouble with it since you're supposed to accept the array if it's any part of the sequence and not just from the start. e.g.: 0 1 1 2 3 5 will be accepted as well as 2 3 5 8 13 21 . This

问题 In Fibonacci sequence each item is the sum of the previous two. fibonacci(1) == 1, fibonacci(0) == 0; fibonacci(2) = fibonacci(1) + fibonacci(0); ... After searching the web I find this algorithm to solve: And here is my code: import java.math.BigInteger; public class Fibonacci { public static BigInteger fib(BigInteger n) { double p = (1 + Math.sqrt(5)) / 2; double q = (1 - Math.sqrt(5) / 2; BigInteger result = BigInteger.ZERO; result = ( Math.pow(p, n) - Math.pow(q, n) ) / Math.sqrt(5); /

问题 I am trying to write a simple Python program. It's supposed to return a a closure that returns successive fibonacci numbers: def fibGen(): n_1 = 0 n_2 = 0 n = 1 def fib(): if n_1 ==0 and n_2 ==0: n_1 = 1 return n else: n = n_1 + n_2 n_2 = n_1 n_1 = n return n return fib f = fibGen() for i in range(0,10): print(f()) I get this error at run time: UnboundLocalError: local variable 'n_1' referenced before assignment EDIT: In my original post, I had not included n = 1 in the definition of fibGen