fibonacci

来源： https://stackoverflow.com/questions/42370456/how-can-i-create-the-fibonacci-series-using-a-list-comprehension

来源： https://stackoverflow.com/questions/22909549/fibonacci-series-with-javascript

来源： https://stackoverflow.com/questions/22909549/fibonacci-series-with-javascript

问题 What would be the most efficient way to calculate the sum of Fibonacci numbers from F(n) to F(m) where F(n) and F(m) are nth and mth Fibonacci numbers respectively and 0 =< n <= m <10 9 (with F(0)=0, F(1)=1). For example, if n=0 , m=3 , we need to find F(0)+F(1)+F(2)+F(3) . Just by brute force it will take long time for the range of n and m mentioned. If it can be done via matrix exponentiation then how? 回答1: F(m+2) - F(n+2) - 2 (discussion) Literally, the sum of your upper bound m, minus the

问题 What would be the most efficient way to calculate the sum of Fibonacci numbers from F(n) to F(m) where F(n) and F(m) are nth and mth Fibonacci numbers respectively and 0 =< n <= m <10 9 (with F(0)=0, F(1)=1). For example, if n=0 , m=3 , we need to find F(0)+F(1)+F(2)+F(3) . Just by brute force it will take long time for the range of n and m mentioned. If it can be done via matrix exponentiation then how? 回答1: F(m+2) - F(n+2) - 2 (discussion) Literally, the sum of your upper bound m, minus the

问题 This question already has answers here : Python - Difference between variable value declaration on Fibonacci function (4 answers) Closed 6 years ago . I was looking at the Python Manual and found this snippet for a Fibonacci-Number generator: def fib(n): # write Fibonacci series up to n a, b = 0, 1 while b < n: print(b, end=' ') a, b = b, a+b print() The output is dependent on n and returns a valid Fibonacci sequence. If you remodel this to use the variables "a" and "b" seperately like so:

问题 This question already has answers here : Python - Difference between variable value declaration on Fibonacci function (4 answers) Closed 6 years ago . I was looking at the Python Manual and found this snippet for a Fibonacci-Number generator: def fib(n): # write Fibonacci series up to n a, b = 0, 1 while b < n: print(b, end=' ') a, b = b, a+b print() The output is dependent on n and returns a valid Fibonacci sequence. If you remodel this to use the variables "a" and "b" seperately like so:

问题 My code is as follow : m, n = map(int, input().split()) # write function "fibtotal" which takes input x and gives accurate fib(x+2)%10 (as sum till fib(x) == fib(x+2) - 1) # using above function get fibtotal(m-1) and fibtotal(n) # subtract fibtotal(m-1) from fibtotal(n) and do mod 10 gives last digit of sum from m to n # take care of handling large input sizes, 0 ≤ 𝑚 ≤ 𝑛 ≤ 10^14 def fibtotal(x): sum = 1 # if both initial conditions fail then loop starts from 2 x= x % 60 # pisano period of 10

问题 This question already has answers here : nth fibonacci number in sublinear time (15 answers) Closed 3 years ago . I am a CSE student and preparing myself for programming contest.Now I am working on Fibonacci series. I have a input file of size about some Kilo bytes containing positive integers. Input formate looks like 3 5 6 7 8 0 A zero means the end of file. Output should like 2 5 8 13 21 my code is #include<stdio.h> int fibonacci(int n) { if (n==1 || n==2) return 1; else return fibonacci(n

问题 This is the question : Given a positive integer num, return the sum of all odd Fibonacci numbers that are less than or equal to num. The first two numbers in the Fibonacci sequence are 1 and 1. Every additional number in the sequence is the sum of the two previous numbers. The first six numbers of the Fibonacci sequence are 1, 1, 2, 3, 5 and 8. For example, sumFibs(10) should return 10 because all odd Fibonacci numbers less than or equal to 10 are 1, 1, 3, and 5. This is what I tried function