exponent

问题 Assume I have a square matrix which can be raised to the -1/2 power. I want to raise the square matrix represented as a numpy.ndarray to -1/2. Note I want to raise the matrix to a non-integer power. I do not want raise each element of the matrix to a non-integer power. I know I can raise a matrix to an integer power using numpy.linalg.matrix_power as described in How to raise a numpy array to a power? How can I raise a numpy.ndarray to non-integer powers? 回答1: SciPy has scipy.linalg.sqrtm,

问题 I'd searching many websites trying to understand how does RSA works. I have a modulus "A89F25A56FA6DA258C8CA8B40427D927B4A1EB4D7EA326BBB12F97DED70AE5E4480FC9C5E8A972177110A1CC318D06D2F8F5C4844AC5FA79A4DC470BB11ED635699C17081B90F1B984F12E92C1C529276D8AF8EC7F28492097D8CD5BECEA16FE4088F6CFAB4A1B42328A1B996F9278B0B7E3311CA5EF856C2F888474B83612A82E4E00D0CD4069A6783140433D50725F" and exponent "03" and i have to decrypt information formated in hex bytes. My questions are: How do i create a public

问题 I am basically making a Java program that will have to run a lot of calculations pretty quickly(each frame, aiming for at least 30 f/s). These will mostly be trigonometric and power functions. The question I'm asking is: Which is faster: using the already-supplied-by-Java Math functions? Or writing my own functions to run? 回答1: The built-in Math functions will be extremely difficult to beat, given that most of them have special JVM magic that makes them use hardware intrinsics. You could

问题 Is it possible to use numpy's linalg.matrix_power with a modulo so the elements don't grow larger than a certain value? 回答1: In order to prevent overflow, you can use the fact that you get the same result if you first take the modulo of each of your input numbers; in fact: (M**k) mod p = ([M mod p]**k) mod p, for a matrix M . This comes from the following two fundamental identities, which are valid for integers x and y : (x+y) mod p = ([x mod p]+[y mod p]) mod p # All additions can be done on

问题 Outline of problem: Please note I will abuse the life out of ^ and use it as a power symbol, despite the caret symbol being the bitwise XOR operator in JS. Take a list of positive integers, [ x_0, x_1, ..., x_n ] and find the last digit of the equation given by x_0 ^ ( x_1 ^ (... ^ x_n ) ... ) I'll call this function LD(...) for the rest of this question. Example: For a list of integers a = [2, 2, 2, 2] and given that 2 ^ (2 ^ (2 ^ 2)) = 65536 , it's easy to see that LD(a) = 6 . Note that 0 ^

问题 Using C# I cannot import a public RSA key with an exponent of {1, 0, 0, 0, 15}: There is an exception: System.Security.Cryptography.CryptographicException was caught HResult=-2146893819 Message=Bad Data. Source=mscorlib StackTrace: at System.Security.Cryptography.CryptographicException.ThrowCryptographicException(Int32 hr) at System.Security.Cryptography.Utils._ImportKey(SafeProvHandle hCSP, Int32 keyNumber, CspProviderFlags flags, Object cspObject, SafeKeyHandle& hKey) at System.Security

问题 Can someone tell me why the Haskell Prelude defines two separate functions for exponentiation (i.e. ^ and ** )? I thought the type system was supposed to eliminate this kind of duplication. Prelude> 2^2 4 Prelude> 4**0.5 2.0 回答1: There are actually three exponentiation operators: (^) , (^^) and (**) . ^ is non-negative integral exponentiation, ^^ is integer exponentiation, and ** is floating-point exponentiation: (^) :: (Num a, Integral b) => a -> b -> a (^^) :: (Fractional a, Integral b) =>

问题 When the numbers are really small, Matlab automatically shows them formatted in Scientific Notation. Example: A = rand(3) / 10000000000000000; A = 1.0e-016 * 0.6340 0.1077 0.6477 0.3012 0.7984 0.0551 0.5830 0.8751 0.9386 Is there some in-built function which returns the exponent? Something like: getExponent(A) = -16 ? I know this is sort of a stupid question, but I need to check hundreds of matrices and I can't seem to figure it out. Thank you for your help. 回答1: Basic math can tell you that:

问题 This question already has answers here : Why do integers in database row tuple have an 'L' suffix? (3 answers) Closed 5 years ago . If you've noticed, python adds an L on to the end of large exponent results like this: >>> 25 ** 25 88817841970012523233890533447265625L After doing some tests, I found that any number below 10 doesn't include the L . For example: >>> 9 ** 9 387420489 This was strange, so, why does this happen, is there any method to prevent it? All help is appreciated! 回答1:

问题 My program seems to be crashing almost arbitrarily. My code includes these two lines: z[i, j] = -math.exp(oneminusbeta[j, i]) weights[i,j] = math.exp(beta[j,i] + oneminusbeta[j,i]) I've run my whole code before on data that had 2 dimensions, it was 7341 x 648 . I had no issues at all running that code. But now the data I'm using is about ten times as big. It's 71678 x 648 , and I'm getting this error: OverflowError: math range error And I'm not getting this on any specific point. I'm logging