equation

I have read about Linear Diophantine equations such as ax+by=c are called diophantine equations and give an integer solution only if gcd(a,b) divides c . These equations are of great importance in programming contests. I was just searching the Internet, when I came across this problem. I think its a variation of diophantine equations. Problem : I have two persons,Person X and Person Y both are standing in the middle of a rope. Person X can jump either A or B units to the left or right in one move. Person Y can jump either C or D units to the left or right in one move. Now, I'm given a number K

Answers in C, Python, C++ or Javascript would be very much appreciated. I've read a few books, done all the examples. Now I'd like to write a simple program. But, I already ran into the following roadblock: My intention is to take an equation from the user and save it in a variable, For example: -3*X+4 or pow(2,(sin(cos(x))/5)) > [In valid C Math syntax] And then calculate the given expression for a certain X-Value. Something like this: printf("%g", UserFunction(3.2)) // Input 3.2 for X in User's Function and Print Result Any ideas? For the life of me, I can't figure this out. Adding to my

As it currently stands, this question is not a good fit for our Q&A format. We expect answers to be supported by facts, references, or expertise, but this question will likely solicit debate, arguments, polling, or extended discussion. If you feel that this question can be improved and possibly reopened, visit the help center for guidance. I'm sure there must be something like this somewhere but I can't seem to find anything useful on here or Google. I had hoped Boost might have something but alas not. What I'm after is a lightweight library that can take a string from the user, for example "y

I am trying to add an equation in a new line. The problem is that the equation is too long for the line, and I need to break it manually. Otherwise, it just overlaps to the right column, or to the right margins (and looks ugly...). Is there a way LaTeX can brake the equation for me, so it seems nice? I'm attaching my latex code: \begin{align*} f(n)-f(0) &= A(n)-B(n)-C(n)-D(n)\cdot d-\left(A(0)-B(0)-C(0)-D(0)\cdot d\right) \\ &= A(n)-0-X-D(n)\cdot d-\left(0-0-0-0\right) \\ &= A(n)-X-D(n)\cdot d \end{align*} The problematic line is the first line, which is too long. The breqn package is designed

How do I calculate the position of an accelerating body (e.g. a car) after a certain time (e.g. 1 second)? For a moving body that it not accelerating, it is a linear relationship, so I presume for an accelerating body it involves a square somewhere. Any ideas? The equation is: s = ut + (1/2)a t^2 where s is position, u is velocity at t=0, t is time and a is a constant acceleration. For example, if a car starts off stationary, and accelerates for two seconds with an acceleration of 3m/s^2, it moves (1/2) * 3 * 2^2 = 6m This equation comes from integrating analytically the equations stating that