eager

How can I run the initialization code for a generator function immediately, rather than at the first call?

流过昼夜 提交于 2019-11-29 17:38:42
问题 I have a generator function that goes something like this: def mygenerator(): next_value = compute_first_value() # Costly operation while next_value != terminating_value: yield next_value next_value = compute_next_value() I would like the initialization step (before the while loop) to run as soon as the function is called, rather than only when the generator is first used. What is a good way to do this? I want to do this because the generator will be running in a separate thread (or process,

Linq for NHibernate and fetch mode of eager loading

▼魔方 西西 提交于 2019-11-28 17:11:31
Is there a way to set the fetchmode to eager for more than one object using linq for nhibernate. There seems to be an expand method which only allows me to set one object. However I need to set it for more than one object. Is this possible? Thanks just use it more then once. IList<Entity> GetDataFromDatabase() { var query = session.Linq<Entity>(); query.Expand("Property1"); query.Expand("Property2"); return query.ToList(); } The new Linq provider does it a little differently: var customers = session.Query<Customer>().Fetch(c => c.Orders).ToList(); More here: http://mikehadlow.blogspot.com/2010

Hibernate: Overriding mapping's EAGER in HQL?

♀尐吖头ヾ 提交于 2019-11-27 12:59:49
问题 It's possible to override LAZY in HQL using LEFT JOIN FETCH . FROM Obj AS obj LEFT JOIN FETCH obj.otherObj WHERE obj.id = :id Is it also possible to override EAGER ? How? 回答1: The qualifier in this snippet from the Hibernate Docs implies that you can override lazy with eager, but not the other way around: If you are using property-level lazy fetching (with bytecode instrumentation), it is possible to force Hibernate to fetch the lazy properties in the first query immediately using fetch all