Doubly Linked List

#ifndef DOUBLY_LINKED_LIST #define DOUBLY_LINKED_LIST #include<stdio.h> #include<stdlib.h> #include<memory.h> /*链表节点*/ typedef struct DoublyLinkedListNodeS{ struct DoublyLinkedListNodeS *prev,*next; }DoublyLinkedListNode; typedef struct DoublyLinkedList{ DoublyLinkedListNode root;//sentinel list element, only &root, root.prev, and root.next are used int length; }DoublyLinkedList; //初始化双向链表 DoublyLinkedList* DoublyLinkedList_Init(); //销毁链表 void DoublyLinkedList_Destory(DoublyLinkedList* list); //链表长度 int DoublyLinkedList_Len(DoublyLinkedList* list); //求头节点 DoublyLinkedListNode* DoublyLinkedList

［抄题］： Convert a BST to a sorted circular doubly-linked list in-place. Think of the left and right pointers as synonymous to the previous and next pointers in a doubly-linked list. Let's take the following BST as an example, it may help you understand the problem better: We want to transform this BST into a circular doubly linked list. Each node in a doubly linked list has a predecessor and successor. For a circular doubly linked list, the predecessor of the first element is the last element, and the successor of the last element is the first element. The figure below shows the circular doubly

原题链接在这里： https://leetcode.com/problems/convert-binary-search-tree-to-sorted-doubly-linked-list/ 题目： Convert a BST to a sorted circular doubly-linked list in-place. Think of the left and right pointers as synonymous to the previous and next pointers in a doubly-linked list. Let's take the following BST as an example, it may help you understand the problem better: We want to transform this BST into a circular doubly linked list. Each node in a doubly linked list has a predecessor and successor. For a circular doubly linked list, the predecessor of the first element is the last element, and the

二叉查找树基础 二叉查找树(BST)满足这样的性质，或是一颗空树；或左子树节点值小于根节点值、右子树节点值大于根节点值，左右子树也分别满足这个性质。 利用这个性质，可以迭代(iterative)或递归(recursive)地用O(lgN)的时间复杂度在二叉查找树中进行值查找。 相关LeetCode题： 700. Search in a Binary Search Tree 题解 701. Insert into a Binary Search Tree 题解 450. Delete Node in a BST 题解 776. Split BST 题解 二叉查找树与有序序列 由性质可知，如果按中序(inorder)遍历二叉查找树，我们将得到递增序列；反过来，如果中序遍历的结果不是递增序列，则所遍历树不是二叉查找树。以下框架适用于多数需要中序遍历二叉树的场景： // 98. Validate Binary Search Tree bool isValidBST(TreeNode* root) { stack <TreeNode*> st; TreeNode * prv= NULL; while (root!=NULL||! st.empty()){ while (root!= NULL){ st.push(root); root =root-> left; } root = st

Convert a BST to a sorted circular doubly-linked list in-place. Think of the left and right pointers as synonymous to the previous and next pointers in a doubly-linked list. Let's take the following BST as an example, it may help you understand the problem better: We want to transform this BST into a circular doubly linked list. Each node in a doubly linked list has a predecessor and successor. For a circular doubly linked list, the predecessor of the first element is the last element, and the successor of the last element is the first element. The figure below shows the circular doubly linked

双向链表实现： // 1.3.31 package com.qiusongde.linkedlist; public class DoublyLinkedList<Item> { private DoublyNode<Item> first; private DoublyNode<Item> last; // can be accessed outside this class public static class DoublyNode<E> { public E item; public DoublyNode<E> next; public DoublyNode<E> pre; } public DoublyLinkedList() { first = null ; last = null ; } /** * insert item at the beginning of the list * * @param list the list to insert * @param item the item to be inserted */ public static <T> void insertAtBeginning(DoublyLinkedList<T> list, T item) { DoublyNode <T> oldfirst = list.first; //

Description Difficulty: Medium Tag: LinkedList, DFS You are given a doubly linked list which in addition to the next and previous pointers, it could have a child pointer, which may or may not point to a separate doubly linked list. These child lists may have one or more children of their own, and so on, to produce a multilevel data structure, as shown in the example below. Flatten the list so that all the nodes appear in a single-level, doubly linked list. You are given the head of the first level of the list. Example: Input: 1---2---3---4---5---6--NULL | 7---8---9---10--NULL | 11--12--NULL