decimalformat

I want to be able to convert a string to a Double given a number of decimal places in a format string. So "###,##0.000" should give me a Double to 3 decimal places. Edit - added more info to what happens The user enters the value in the UI - which is input into a String. The rule is this value is limited to 3 decimal places. The underlying code stores the value in the database which is then used in a calculation. Therefore the trailing decimal places will cause the calculations to be out slightly to what would be expected. I have the following code: try { // output current locale we are

I have an XML file where the number are comma-separated <foo> <bar val="1,23"/> <bar val="4,56"/> <bar val="7,89"/> </foo> I would like to make a sum over /foo/bar/@val values in XSLT, but I am a bit stuck the formatting. Does anyone knows what would be the proper syntax? I am guessing, that the value specified in a "val" attribute is a number that has comma instead of a decimal point. Several solutions are possible : I. XSLT 1.0 This transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ext="http://exslt.org/common" > <xsl:output method="text"/>

I'm using DecimalFormat to format doubles to 2 decimal places like this: DecimalFormat dec = new DecimalFormat("#.##"); double rawPercent = ( (double)(count.getCount().intValue()) / (double)(total.intValue()) ) * 100.00; double percentage = Double.valueOf(dec.format(rawPercent)); It works, but if i have a number like 20, it gives me this: 20.0 and I want this: 20.00 Any suggestions? The DecimalFormat class is for transforming a decimal numeric value into a String. In your example, you are taking the String that comes from the format( ) method and putting it back into a double variable. If you

This question already has an answer here: Safe String to BigDecimal conversion 9 answers I have this String: 10,692,467,440,017.120 (it's an amount). I want to parse it to a BigDecimal. The problem is that I have tried both DecimalFormat and NumbeFormat in vain. Any help? René Link Try this // Create a DecimalFormat that fits your requirements DecimalFormatSymbols symbols = new DecimalFormatSymbols(); symbols.setGroupingSeparator(','); symbols.setDecimalSeparator('.'); String pattern = "#,##0.0#"; DecimalFormat decimalFormat = new DecimalFormat(pattern, symbols); decimalFormat

This question already has an answer here: How to round a number to n decimal places in Java 29 answers For example I have the variable 3.545555555, which I would want to truncate to just 3.54. Bozho If you want that for display purposes, use java.text.DecimalFormat : new DecimalFormat("#.##").format(dblVar); If you need it for calculations, use java.lang.Math : Math.floor(value * 100) / 100; Cedric Dubourg DecimalFormat df = new DecimalFormat(fmt); df.setRoundingMode(RoundingMode.DOWN); s = df.format(d); Check available RoundingMode and DecimalFormat . Mani Bit Old Forum, None of the above