decimalformat

NB: To the best of my knowledge this question is not a duplicate! All the questios/answers I found are either how to eliminate points from data that are already in R or how to change the decimal point to a comma when loading it. I have a csv with numbers like: 4.123,98 . The problem is that because of the . the output becomes a character string matrix when loading with read.table , read.csv or read.csv2 . Changing dec to , doesn't help. My question What is the most elegant way to load this csv so that the numbers become e.g. 4123.98 as numeric? cryo111 Adapted from this post: Specify custom

This might look like a repeated question but I tried in all the below links and can't get a proper answer. Cannot format given Object as a Number ComboBox Illegal Argument Exception But I'm not getting whats wrong. Here is my code DecimalFormat twoDForm = new DecimalFormat("#.##"); double externalmark = 1.86; double internalmark = 4.0; System.out.println(String.valueOf((externalmark*3+internalmark*1)/4)); String val = String.valueOf((externalmark*3+internalmark*1)/4); String wgpa1=twoDForm.format(val); // gives exception String wgpa2=twoDForm.format((externalmark*3+internalmark*1)/4)); //

Laravel does not have a validation for decimal , so I need a regex or other validation method to validate a numeric value of 0 - 99.99 I have tried required|regex:^\d{0,2}(\.\d{1,2})?$/ required|regex:[1-9]\d?(\.\d\d?)?|0\.[1-9]\d?||0\.0[1-9] required|regex:/[1-9]\d?(\.\d\d?)?|0\.[1-9]\d?||0\.0[1-9]/ required|regex:/[\d]{2}.[\d]{2}/ required|regex:/[\d]{0-2}.[\d]{0,2}/ I am either getting "invalid format" when trying to enter 0.05 or unknown modifiers for preg_match any help with the regex needed to validate a decimal in laravel is appreciated (with optional values before or after decimal The

package com.lee.test; import java.text.DecimalFormat; import java.util.Locale; /** * DecimalFormat的几种用法！ * @author lee * @depict NumberFormat.getInstance()方法返回NumberFormat的一个实例( * 实际上是NumberFormat具体的一个子类，例如DecimalFormat), 这适合根 * 据本地设置格式化一个数字。你也可以使用非缺省的地区设置，例如德国。然后格式 * 化方法根据特定的地区规则格式化数字。这个程序也可以使用一个简单的形式： * NumberFormat.getInstance().format(1234.56) */ public class Demo_test { public static void main(String[] args) { // for (int i = 1; i <= 100; i++) { // String squence = new DecimalFormat("00000").format(i); // System.out.println(squence+","); // } // 得到本地的缺省格式 DecimalFormat df1 = new

I'm trying to format some numbers in a Java program. The numbers will be both doubles and integers. When handling doubles, I want to keep only two decimal points but when handling integers I want the program to keep them unaffected. In other words: Doubles - Input 14.0184849945 Doubles - Output 14.01 Integers - Input 13 Integers - Output 13 (not 13.00) Is there a way to implement this in the same DecimalFormat instance? My code is the following, so far: DecimalFormat df = new DecimalFormat("#,###,##0.00"); DecimalFormatSymbols otherSymbols = new DecimalFormatSymbols(Locale.ENGLISH);

public static String formatAmountUpToTwoDecimalNumber(String amount) { if(amount==null || "".equals(amount)) { return ""; } Double doubleAmount = Double.valueOf(amount); double myAmount = doubleAmount.doubleValue(); NumberFormat f = new DecimalFormat("###,###,###,###,##0.00"); String s = f.format(myAmount); return s; } "###,###,###,###,##0.00" , What exactly is the purpose of this pattern ? I believe it serves two purposes to group numbers, that is put thousand seperator comma to append two zeros after decimal if decimal is missing that is convert 23 to 23.00 But why there is "0" instead of "#