This question already has an answer here:
For example I have the variable 3.545555555, which I would want to truncate to just 3.54.
If you want that for display purposes, use java.text.DecimalFormat:
new DecimalFormat("#.##").format(dblVar);
If you need it for calculations, use java.lang.Math:
Math.floor(value * 100) / 100;
DecimalFormat df = new DecimalFormat(fmt);
df.setRoundingMode(RoundingMode.DOWN);
s = df.format(d);
Check available RoundingMode and DecimalFormat.
Bit Old Forum, None of the above answer worked for both positive and negative values ( I mean for the calculation and just to do truncate without Rounding). From the How to round a number to n decimal places in Java link
private static BigDecimal truncateDecimal(double x,int numberofDecimals)
{
if ( x > 0) {
return new BigDecimal(String.valueOf(x)).setScale(numberofDecimals, BigDecimal.ROUND_FLOOR);
} else {
return new BigDecimal(String.valueOf(x)).setScale(numberofDecimals, BigDecimal.ROUND_CEILING);
}
}
This method worked fine for me .
System.out.println(truncateDecimal(0, 2));
System.out.println(truncateDecimal(9.62, 2));
System.out.println(truncateDecimal(9.621, 2));
System.out.println(truncateDecimal(9.629, 2));
System.out.println(truncateDecimal(9.625, 2));
System.out.println(truncateDecimal(9.999, 2));
System.out.println(truncateDecimal(-9.999, 2));
System.out.println(truncateDecimal(-9.0, 2));
Results :
0.00
9.62
9.62
9.62
9.62
9.99
-9.99
-9.00
Note first that a double is a binary fraction and does not really have decimal places.
If you need decimal places, use a BigDecimal, which has a setScale() method for truncation, or use DecimalFormat to get a String.
If, for whatever reason, you don't want to use a BigDecimal you can cast your double to an int to truncate it.
If you want to truncate to the Ones place:
- simply cast to
int
To the Tenths place:
- multiply by ten
- cast to
int - cast back to
double - and divide by ten.
Hundreths place
- multiply and divide by 100 etc.
Example:
static double truncateTo( double unroundedNumber, int decimalPlaces ){
int truncatedNumberInt = (int)( unroundedNumber * Math.pow( 10, decimalPlaces ) );
double truncatedNumber = (double)( truncatedNumberInt / Math.pow( 10, decimalPlaces ) );
return truncatedNumber;
}
In this example, decimalPlaces would be the number of places PAST the ones place you wish to go, so 1 would round to the tenths place, 2 to the hundredths, and so on (0 rounds to the ones place, and negative one to the tens, etc.)
Maybe Math.floor(value * 100) / 100? Beware that the values like 3.54 may be not exactly represented with a double.
You can use NumberFormat Class object to accomplish the task.
// Creating number format object to set 2 places after decimal point
NumberFormat nf = NumberFormat.getInstance();
nf.setMaximumFractionDigits(2);
nf.setGroupingUsed(false);
System.out.println(nf.format(precision));// Assuming precision is a double type variable
3.545555555 to get 3.54. Try Following for this:
DecimalFormat df = new DecimalFormat("#.##");
df.setRoundingMode(RoundingMode.FLOOR);
double result = new Double(df.format(3.545555555);
This will give= 3.54!
Here is the method I use:
double a=3.545555555; // just assigning your decimal to a variable
a=a*100; // this sets a to 354.555555
a=Math.floor(a); // this sets a to 354
a=a/100; // this sets a to 3.54 and thus removing all your 5's
This can also be done:
a=Math.floor(a*100) / 100;
Formating as a string and converting back to double i think will give you the result you want.
The double value will not be round(), floor() or ceil().
A quick fix for it could be:
String sValue = (String) String.format("%.2f", oldValue);
Double newValue = Double.parseDouble(sValue);
You can use the sValue for display purposes or the newValue for calculation.
Maybe following :
double roundTwoDecimals(double d) {
DecimalFormat twoDForm = new DecimalFormat("#.##");
return Double.valueOf(twoDForm.format(d));
}
A quick check is to use the Math.floor method. I created a method to check a double for two or less decimal places below:
public boolean checkTwoDecimalPlaces(double valueToCheck) {
// Get two decimal value of input valueToCheck
double twoDecimalValue = Math.floor(valueToCheck * 100) / 100;
// Return true if the twoDecimalValue is the same as valueToCheck else return false
return twoDecimalValue == valueToCheck;
}
I have a slightly modified version of Mani's.
private static BigDecimal truncateDecimal(final double x, final int numberofDecimals) {
return new BigDecimal(String.valueOf(x)).setScale(numberofDecimals, BigDecimal.ROUND_DOWN);
}
public static void main(String[] args) {
System.out.println(truncateDecimal(0, 2));
System.out.println(truncateDecimal(9.62, 2));
System.out.println(truncateDecimal(9.621, 2));
System.out.println(truncateDecimal(9.629, 2));
System.out.println(truncateDecimal(9.625, 2));
System.out.println(truncateDecimal(9.999, 2));
System.out.println(truncateDecimal(3.545555555, 2));
System.out.println(truncateDecimal(9.0, 2));
System.out.println(truncateDecimal(-9.62, 2));
System.out.println(truncateDecimal(-9.621, 2));
System.out.println(truncateDecimal(-9.629, 2));
System.out.println(truncateDecimal(-9.625, 2));
System.out.println(truncateDecimal(-9.999, 2));
System.out.println(truncateDecimal(-9.0, 2));
System.out.println(truncateDecimal(-3.545555555, 2));
}
Output:
0.00
9.62
9.62
9.62
9.62
9.99
9.00
3.54
-9.62
-9.62
-9.62
-9.62
-9.99
-9.00
-3.54
This worked for me:
double input = 104.8695412 //For example
long roundedInt = Math.round(input * 100);
double result = (double) roundedInt/100;
//result == 104.87
I personally like this version because it actually performs the rounding numerically, rather than by converting it to a String (or similar) and then formatting it.
//if double_v is 3.545555555
String string_v= String.valueOf(double_v);
int pointer_pos = average.indexOf('.');//we find the position of '.'
string_v.substring(0, pointer_pos+2));// in this way we get the double with only 2 decimal in string form
double_v = Double.valueOf(string_v);//well this is the final result
well this might be a little awkward, but i think it can solve your problem :)
来源：https://stackoverflow.com/questions/7747469/how-can-i-truncate-a-double-to-only-two-decimal-places-in-java