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- Safe String to BigDecimal conversion 9 answers
I have this String: 10,692,467,440,017.120 (it's an amount).
I want to parse it to a BigDecimal. The problem is that I have tried both DecimalFormat and NumbeFormat in vain. Any help?
Try this
// Create a DecimalFormat that fits your requirements
DecimalFormatSymbols symbols = new DecimalFormatSymbols();
symbols.setGroupingSeparator(',');
symbols.setDecimalSeparator('.');
String pattern = "#,##0.0#";
DecimalFormat decimalFormat = new DecimalFormat(pattern, symbols);
decimalFormat.setParseBigDecimal(true);
// parse the string
BigDecimal bigDecimal = (BigDecimal) decimalFormat.parse("10,692,467,440,017.120");
System.out.println(bigDecimal);
If you are building an application with I18N support you should use DecimalFormatSymbols(Locale)
Also keep in mind that decimalFormat.parse
can throw a ParseException
so you need to handle it (with try/catch) or throw it and let another part of your program handle it
Try this
String str="10,692,467,440,017.120".replaceAll(",","");
BigDecimal bd=new BigDecimal(str);
BigDecimal offers a string constructor. You'll need to strip all commas from the number, via via an regex or String filteredString=inString.replaceAll(",","")
.
You then simply call BigDecimal myBigD=new BigDecimal(filteredString);
You can also create a NumberFormat
and call setParseBigDecimal(true)
. Then parse(
will give you a BigDecimal without worrying about manually formatting.
Try the correct constructor http://docs.oracle.com/javase/7/docs/api/java/math/BigDecimal.html#BigDecimal(java.lang.String)
You can directly instanciate the BigDecimal with the String ;)
Example:
BigDecimal bigDecimalValue= new BigDecimal("0.5");
来源:https://stackoverflow.com/questions/18231802/how-can-i-parse-a-string-to-bigdecimal