datetime-parsing

org.threeten.bp.format.DateTimeParseException: Text '2018-07-22T14:00:00-03:00' could not be parsed at index 19

拈花ヽ惹草 提交于 2019-12-08 09:18:20
问题 public static String formatter(String dateInPattern, String dateOutPattern) { OffsetDateTime dateInPatternFormat = OffsetDateTime.parse(dateInPattern, DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ssZ")); Date dateInValue = DateTimeUtils.toDate(Instant.parse(dateInPatternFormat.toString())); OffsetDateTime dateOutPatternFormat = OffsetDateTime.parse(dateOutPattern); return dateOutPatternFormat.format(DateTimeFormatter.ofPattern(dateInValue.toString())); } I need to enter a date in this

How to handle all Zone Offset in one DateTimeFormater Java 8

Deadly 提交于 2019-12-07 13:44:47
问题 I need to create a DateTimeFormatter for the following valid dates. String date1 = "2017-06-20T17:25:28"; String date2 = "2017-06-20T17:25:28.477777"; String date3 = "2017-06-20T17:25:28.477777Z"; String date4 = "2017-06-20T17:25:28.477777UTC"; String date5 = "2017-06-20T17:25:28.477777-05"; String date6 = "2017-06-20T17:25:28.477777+05"; String date7 = "2017-06-20T17:25:28.477777+05:30"; String date8 = "2017-06-20T17:25:28.477777-05:30"; String date9 = "2017-06-20T17:25:28.477777+0530";

Java date time format check and reset

霸气de小男生 提交于 2019-12-06 12:48:00
问题 String is an input and i have to check whether it is in any of these formats. If it is in sdf1 format then pass, if it is in sdf2,3.... then i add the missing the format and parse it with sdf1 format SimpleDateFormat sdf1 = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a"); SimpleDateFormat sdf2 = new SimpleDateFormat("MM/dd/yyyy hh:mm:ssa"); SimpleDateFormat sdf3 = new SimpleDateFormat("MM/dd/yyyy hh:mm a"); SimpleDateFormat sdf3 = new SimpleDateFormat("MM/dd/yyyy hh:mma"); SimpleDateFormat sdf3

How to handle all Zone Offset in one DateTimeFormater Java 8

拜拜、爱过 提交于 2019-12-06 01:50:25
I need to create a DateTimeFormatter for the following valid dates. String date1 = "2017-06-20T17:25:28"; String date2 = "2017-06-20T17:25:28.477777"; String date3 = "2017-06-20T17:25:28.477777Z"; String date4 = "2017-06-20T17:25:28.477777UTC"; String date5 = "2017-06-20T17:25:28.477777-05"; String date6 = "2017-06-20T17:25:28.477777+05"; String date7 = "2017-06-20T17:25:28.477777+05:30"; String date8 = "2017-06-20T17:25:28.477777-05:30"; String date9 = "2017-06-20T17:25:28.477777+0530"; String date10 = "2017-06-20T17:25:28.477777-0530"; I have tried the following date time formatter, but this

Java date time format check and reset

…衆ロ難τιáo~ 提交于 2019-12-04 20:33:09
String is an input and i have to check whether it is in any of these formats. If it is in sdf1 format then pass, if it is in sdf2,3.... then i add the missing the format and parse it with sdf1 format SimpleDateFormat sdf1 = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a"); SimpleDateFormat sdf2 = new SimpleDateFormat("MM/dd/yyyy hh:mm:ssa"); SimpleDateFormat sdf3 = new SimpleDateFormat("MM/dd/yyyy hh:mm a"); SimpleDateFormat sdf3 = new SimpleDateFormat("MM/dd/yyyy hh:mma"); SimpleDateFormat sdf3 = new SimpleDateFormat("MM/dd/yyyy hh:mm"); SimpleDateFormat sdf3 = new SimpleDateFormat("MM/dd/yyyy")

DST changes caused an java.text.ParseException: Unparseable date

笑着哭i 提交于 2019-12-02 22:36:18
问题 Following is the code snippet which is throwing an exception: SimpleDateformat dateFormatter = new SimpleDateFormat("yyyyMMddHHmm"); Date date = dateFormatter.parse("201710010200"); The code above threw exception for all the dates after 2:00 A.M. It ran well till 01:30 A.M. DayLight saving time was configured (I'm using Australia/Sydney timezone). After that, I could see logs of 3:00 A.M. Time between 2:00 A.M. and 3:00 A.M. is not logged too. Log: 01 Oct 03:02:01 ERROR : Unparseable date:

Not able to convert the string to date on Android

旧城冷巷雨未停 提交于 2019-12-02 19:53:09
问题 I have obtained a string from an API in form of 2017-04-23T19:47:39+00:00 How do i convert it into date of format "2017-04-23T19:47:39-0000"? I tried the following but it gave ParseException String created_at_string = "2017-04-23T19:47:39+00:00"; SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ"); Date created_at = sdf.parse(created_at_string); Exception: 06-22 18:18:32.517 10396-10396/com.harit.abs W/System.err: java.text.ParseException: Unparseable date: ""2018-04-29T10

DateTimeParseException: Text '2019-06-07 12:18:16' could not be parsed

对着背影说爱祢 提交于 2019-12-02 13:15:43
I have following code to convert an Instant to String then convert it back to I String timestampString = LocalDateTime.now().format(DateTimeFormatter.ofPattern("yyyy-MM-dd hh:mm:ss")); LOGGER.info("timestampString: " + timestampString); Instant instant = LocalDateTime.parse(timestampString, DateTimeFormatter.ofPattern("yyyy-MM-dd hh:mm:ss")).toInstant(ZoneOffset.UTC); it print the timestampString as: 2019-06-07 12:45:57 and failed at parse the string: java.time.format.DateTimeParseException: Text '2019-06-07 12:45:57' could not be parsed: Unable to obtain LocalDateTime from TemporalAccessor:

Not able to convert the string to date on Android

你说的曾经没有我的故事 提交于 2019-12-02 11:38:00
I have obtained a string from an API in form of 2017-04-23T19:47:39+00:00 How do i convert it into date of format "2017-04-23T19:47:39-0000"? I tried the following but it gave ParseException String created_at_string = "2017-04-23T19:47:39+00:00"; SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ"); Date created_at = sdf.parse(created_at_string); Exception: 06-22 18:18:32.517 10396-10396/com.harit.abs W/System.err: java.text.ParseException: Unparseable date: ""2018-04-29T10:55:37+00:00"" at java.text.DateFormat.parse(DateFormat.java:358) at com.harit.abs.Sync_Activity.bu(Sync

java to mysql. I need convert from string parametre to timestamp

假装没事ソ 提交于 2019-12-02 04:47:00
问题 I'm trying to parser String to Timestamp because I need to save this data on bbdd mysql. String dateString: "2018-10-17T22:37:10.000+0000"; java.sql.Timestamp timeStampDate = null; try { DateFormat formatter; formatter = new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.SSS"); Date date = (Date) formatter.parse(dateString); timeStampDate = new Timestamp(date.getTime()); } catch (ParseException e) { log.debug("ERROR parser String to Timestamp to save bbdd. ", e.getMessage()); } When I run my app I get