问题
public static String formatter(String dateInPattern, String dateOutPattern) {
OffsetDateTime dateInPatternFormat = OffsetDateTime.parse(dateInPattern, DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ssZ"));
Date dateInValue = DateTimeUtils.toDate(Instant.parse(dateInPatternFormat.toString()));
OffsetDateTime dateOutPatternFormat = OffsetDateTime.parse(dateOutPattern);
return dateOutPatternFormat.format(DateTimeFormatter.ofPattern(dateInValue.toString()));
}
I need to enter a date in this pattern yyyy-MM-dd'T'HH:mm:ss'Z' this is equals (2018-07-22T14:00:00-03:00). And I need an output in this pattern dd/MM/yyyy
Helpe me please.
I have had many problems with date on android :(
回答1:
Your code is very confusing, with weird names and you seem to be mixing up pattern strings, e.g. yyyy-MM-dd, with value strings, e.g. 2018-07-22.
The value string 2018-07-22T14:00:00-03:00 can be parsed into an OffsetDateTime without specifying a DateTimeFormatter, since that is the default format of an OffsetDateTime.
If you then need to format that as dd/MM/yyyy, then use a DateTimeFormatter.
Don't know why your method takes 2 parameters.
Example:
String input = "2018-07-22T14:00:00-03:00";
OffsetDateTime offsetDateTime = OffsetDateTime.parse(input);
String output = offsetDateTime.format(DateTimeFormatter.ofPattern("dd/MM/yyyy"));
System.out.println(output); // prints: 22/07/2018
来源：https://stackoverflow.com/questions/52545720/org-threeten-bp-format-datetimeparseexception-text-2018-07-22t140000-0300